結果
問題 | No.461 三角形はいくつ? |
ユーザー |
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提出日時 | 2016-12-12 00:44:58 |
言語 | C++11(廃止可能性あり) (gcc 13.3.0) |
結果 |
AC
|
実行時間 | 218 ms / 5,000 ms |
コード長 | 2,187 bytes |
コンパイル時間 | 1,479 ms |
コンパイル使用メモリ | 172,900 KB |
実行使用メモリ | 6,820 KB |
最終ジャッジ日時 | 2024-11-29 04:26:16 |
合計ジャッジ時間 | 6,164 ms |
ジャッジサーバーID (参考情報) |
judge4 / judge2 |
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ファイルパターン | 結果 |
---|---|
sample | AC * 4 |
other | AC * 41 |
コンパイルメッセージ
main.cpp: In function ‘int main()’: main.cpp:62:8: warning: ignoring return value of ‘int scanf(const char*, ...)’ declared with attribute ‘warn_unused_result’ [-Wunused-result] 62 | scanf("%d",&n); | ~~~~~^~~~~~~~~ main.cpp:65:10: warning: ignoring return value of ‘int scanf(const char*, ...)’ declared with attribute ‘warn_unused_result’ [-Wunused-result] 65 | scanf("%d%d%d",&p,&a,&b); | ~~~~~^~~~~~~~~~~~~~~~~~~
ソースコード
#include <bits/stdc++.h> using namespace std; typedef long long ll; typedef vector<int> vi; typedef vector<ll> vl; typedef pair<int,int> pii; typedef pair<ll,ll> pll; typedef int _loop_int; #define REP(i,n) for(_loop_int i=0;i<(_loop_int)(n);++i) #define FOR(i,a,b) for(_loop_int i=(_loop_int)(a);i<(_loop_int)(b);++i) #define FORR(i,a,b) for(_loop_int i=(_loop_int)(b)-1;i>=(_loop_int)(a);--i) #define DEBUG(x) cout<<#x<<": "<<x<<endl #define DEBUG_VEC(v) cout<<#v<<":";REP(i,v.size())cout<<" "<<v[i];cout<<endl #define ALL(a) (a).begin(),(a).end() #define CHMIN(a,b) a=min((a),(b)) #define CHMAX(a,b) a=max((a),(b)) // mod const ll MOD = 1000000007ll; #define FIX(a) ((a)%MOD+MOD)%MOD // floating typedef double Real; const Real EPS = 1e-11; #define EQ0(x) (abs(x)<EPS) #define EQ(a,b) (abs(a-b)<EPS) typedef complex<Real> P; class Ratio{ public: ll x,y; Ratio(){} Ratio(ll x,ll y):x(x),y(y){ ll g = __gcd(x,y); x/=g; y/=g; } Ratio operator+(const Ratio &that) const { return Ratio(this->x*that.y + that.x*this->y, this->y*that.y); } Ratio operator-(const Ratio &that) const { return Ratio(this->x*that.y - that.x*this->y, this->y*that.y); } bool operator<(const Ratio &that) const { return (ll)this->x * that.y < (ll)this->y * that.x; } bool operator>(const Ratio &that) const { return (ll)this->x * that.y > (ll)this->y * that.x; } }; int n; Ratio one(1,1); Ratio zero(0,1); set<Ratio> yo[3]; int main(){ scanf("%d",&n); REP(i,n){ int p,a,b; scanf("%d%d%d",&p,&a,&b); yo[p].insert(Ratio(a,a+b)); } REP(p,3)yo[p].insert(one); map<Ratio,int> rui; int it = 0; rui[Ratio(-1e9,1)] = it++; for(auto a:yo[0]){ rui[a] = it++; } rui[Ratio(1e9,1)] = it++; ll ans = 0; for(auto a1:yo[1])for(auto a2:yo[2]){ Ratio b1 = one-a1; Ratio b2 = one-a2; if(one - a2 > a1)continue; Ratio high = one, low = max(b1,b2); ll add = 0; auto it = rui.upper_bound(high);it--; add += it->second; it = rui.lower_bound(low); it--; add -= it->second; ans += add; // banned if(rui.count(one-(a1-b2))){ ans --; } } printf("%lld\n",ans); return 0; }