#137752 (C90) No.461 三角形はいくつ？

• 問題: No.461 三角形はいくつ？
• ユーザー: tails
• 提出日時: 2016-12-12 01:48:32
• 言語: C90 (gcc 11.4.0)
• 結果: WA
• 実行時間: -
• コード長: 774 bytes
• コンパイル時間: 474 ms
• コンパイル使用メモリ: 23,168 KB
• 実行使用メモリ: 6,824 KB
• 最終ジャッジ日時: 2024-11-29 12:08:49
• 合計ジャッジ時間: 54,963 ms
• ジャッジサーバーID （参考情報）: judge2 / judge4

入力	結果	実行時間; 実行使用メモリ
testcase_00	WA	-
testcase_01	AC	1 ms; 5,248 KB
testcase_02	AC	0 ms; 5,248 KB
testcase_03	AC	1 ms; 5,248 KB
testcase_04	AC	1 ms; 5,248 KB
testcase_05	AC	3,019 ms; 5,248 KB
testcase_06	AC	1,300 ms; 5,248 KB
testcase_07	AC	1,550 ms; 5,248 KB
testcase_08	AC	853 ms; 5,248 KB
testcase_09	AC	1 ms; 5,248 KB
testcase_10	AC	134 ms; 5,248 KB
testcase_11	AC	2,004 ms; 5,248 KB
testcase_12	AC	517 ms; 5,248 KB
testcase_13	AC	3,812 ms; 5,248 KB
testcase_14	AC	3,599 ms; 5,248 KB
testcase_15	AC	3,820 ms; 5,248 KB
testcase_16	AC	11 ms; 5,248 KB
testcase_17	AC	11 ms; 5,248 KB
testcase_18	WA	-
testcase_19	WA	-
testcase_20	AC	3,795 ms; 5,248 KB
testcase_21	AC	3,720 ms; 5,248 KB
testcase_22	WA	-
testcase_23	WA	-
testcase_24	WA	-
testcase_25	AC	17 ms; 5,248 KB
testcase_26	AC	17 ms; 5,248 KB
testcase_27	AC	6 ms; 5,248 KB
testcase_28	AC	5 ms; 5,248 KB
testcase_29	AC	926 ms; 5,248 KB
testcase_30	AC	459 ms; 5,248 KB
testcase_31	AC	1,637 ms; 5,248 KB
testcase_32	AC	2,068 ms; 5,248 KB
testcase_33	AC	2 ms; 5,248 KB
testcase_34	AC	2 ms; 5,248 KB
testcase_35	AC	2 ms; 5,248 KB
testcase_36	WA	-
testcase_37	WA	-
testcase_38	WA	-
testcase_39	WA	-
testcase_40	WA	-
testcase_41	WA	-
testcase_42	WA	-
testcase_43	WA	-
testcase_44	WA	-

コンパイルメッセージ

main.c:1:1: warning: data definition has no type or storage class
    1 | n;c[3];
      | ^
main.c:1:1: warning: type defaults to ‘int’ in declaration of ‘n’ [-Wimplicit-int]
main.c:1:3: warning: data definition has no type or storage class
    1 | n;c[3];
      |   ^
main.c:1:3: warning: type defaults to ‘int’ in declaration of ‘c’ [-Wimplicit-int]
main.c:3:1: warning: data definition has no type or storage class
    3 | i;j;k;p;
      | ^
main.c:3:1: warning: type defaults to ‘int’ in declaration of ‘i’ [-Wimplicit-int]
main.c:3:3: warning: data definition has no type or storage class
    3 | i;j;k;p;
      |   ^
main.c:3:3: warning: type defaults to ‘int’ in declaration of ‘j’ [-Wimplicit-int]
main.c:3:5: warning: data definition has no type or storage class
    3 | i;j;k;p;
      |     ^
main.c:3:5: warning: type defaults to ‘int’ in declaration of ‘k’ [-Wimplicit-int]
main.c:3:7: warning: data definition has no type or storage class
    3 | i;j;k;p;
      |       ^
main.c:3:7: warning: type defaults to ‘int’ in declaration of ‘p’ [-Wimplicit-int]
main.c:4:1: warning: data definition has no type or storage class
    4 | r;
      | ^
main.c:4:1: warning: type defaults to ‘int’ in declaration of ‘r’ [-Wimplicit-int]
main.c:7:1: warning: return type defaults to ‘int’ [-Wimplicit-int]
    7 | main(){
      | ^~~~
main.c: In function ‘main’:
main.c:8:9: warning: implicit declaration of function ‘scanf’ [-Wimplicit-function-declaration]
    8 |         scanf("%d",&n);
      |         ^~~~~
main.c:1:1: note: include ‘<stdio.h>’ or provide a declaration of ‘scanf’
  +++ |+#include <stdio.h>
    1 | n;c[3];
main.c:8:9: warning: incompatible implicit declaration of built-in function ‘scanf’ [-Wbuiltin-declaration-mismatch]
    8 |         scanf("%d",&n);
      |         ^~~~~
main.c:8:9: note: include ‘<stdio.h>’ or provide a declaration of ‘scanf’
main.c:44:61: warning: implicit decla

ソースコード

n;c[3];
double d[3][5000],a,b;
i;j;k;p;
r;
double e=1e-17;

main(){
	scanf("%d",&n);
	r=n+1;
	for(i=0;i<n;++i){
		scanf("%d%lf%lf",&p,&a,&b);
		d[p][c[p]++]=a/(a+b);
	}
	for(i=0;i<c[0];++i){
		for(j=0;j<c[1];++j){
			if(d[0][i]+d[1][j]>1+e){
				++r;
			}
		}
	}
	for(i=0;i<c[0];++i){
		for(j=0;j<c[2];++j){
			if(d[0][i]+d[2][j]>1+e){
				++r;
			}
		}
	}
	for(i=0;i<c[1];++i){
		for(j=0;j<c[2];++j){
			if(d[1][i]+d[2][j]>1+e){
				++r;
			}
		}
	}
	for(i=0;i<c[0];++i){
		double d0=d[0][i];
		for(j=0;j<c[1];++j){
			double d1=d[1][j];
			if(d0+d1>1-e){
				double d01min = d0<d1?d0:d1;
				double d022 = d0+d1-2;
				for(k=0;k<c[2];++k){
					double d2=d[2][k];
					if(d01min+d2>1-e && fabs(d022+d2)>e){
						++r;
					}
				}
			}
		}
	}
	printf("%d",r);
	return 0;
}