結果
問題 | No.461 三角形はいくつ? |
ユーザー | しらっ亭 |
提出日時 | 2016-12-12 04:59:34 |
言語 | C++14 (gcc 12.3.0 + boost 1.83.0) |
結果 |
TLE
|
実行時間 | - |
コード長 | 5,580 bytes |
コンパイル時間 | 2,005 ms |
コンパイル使用メモリ | 186,772 KB |
実行使用メモリ | 214,864 KB |
最終ジャッジ日時 | 2024-11-29 14:45:20 |
合計ジャッジ時間 | 89,841 ms |
ジャッジサーバーID (参考情報) |
judge4 / judge5 |
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テストケース
テストケース表示入力 | 結果 | 実行時間 実行使用メモリ |
---|---|---|
testcase_00 | AC | 2 ms
158,328 KB |
testcase_01 | AC | 2 ms
13,640 KB |
testcase_02 | AC | 2 ms
160,972 KB |
testcase_03 | AC | 2 ms
150,892 KB |
testcase_04 | AC | 11 ms
13,636 KB |
testcase_05 | AC | 2,572 ms
214,864 KB |
testcase_06 | AC | 1,269 ms
37,796 KB |
testcase_07 | AC | 1,632 ms
53,104 KB |
testcase_08 | AC | 1,069 ms
33,644 KB |
testcase_09 | AC | 5 ms
6,820 KB |
testcase_10 | AC | 314 ms
12,292 KB |
testcase_11 | AC | 1,910 ms
53,348 KB |
testcase_12 | AC | 819 ms
28,524 KB |
testcase_13 | AC | 2,867 ms
75,708 KB |
testcase_14 | AC | 2,685 ms
70,340 KB |
testcase_15 | AC | 2,859 ms
73,992 KB |
testcase_16 | AC | 557 ms
6,820 KB |
testcase_17 | AC | 575 ms
6,820 KB |
testcase_18 | AC | 4,918 ms
141,816 KB |
testcase_19 | TLE | - |
testcase_20 | AC | 2,987 ms
77,512 KB |
testcase_21 | AC | 2,832 ms
72,360 KB |
testcase_22 | AC | 2,834 ms
72,252 KB |
testcase_23 | AC | 626 ms
16,456 KB |
testcase_24 | AC | 603 ms
16,192 KB |
testcase_25 | TLE | - |
testcase_26 | TLE | - |
testcase_27 | AC | 11 ms
6,820 KB |
testcase_28 | AC | 13 ms
6,816 KB |
testcase_29 | TLE | - |
testcase_30 | TLE | - |
testcase_31 | TLE | - |
testcase_32 | TLE | - |
testcase_33 | AC | 4 ms
6,816 KB |
testcase_34 | AC | 3 ms
6,816 KB |
testcase_35 | AC | 5 ms
6,816 KB |
testcase_36 | AC | 997 ms
28,768 KB |
testcase_37 | AC | 828 ms
28,652 KB |
testcase_38 | AC | 879 ms
28,416 KB |
testcase_39 | AC | 748 ms
22,120 KB |
testcase_40 | AC | 876 ms
28,864 KB |
testcase_41 | AC | 886 ms
28,980 KB |
testcase_42 | AC | 2,065 ms
47,640 KB |
testcase_43 | AC | 2,051 ms
50,356 KB |
testcase_44 | AC | 1,960 ms
198,936 KB |
ソースコード
#include <bits/stdc++.h> using namespace std; #define _p(...) (void)printf(__VA_ARGS__) #define forr(x,arr) for(auto&& x:arr) #define _overload3(_1,_2,_3,name,...) name #define _rep2(i,n) _rep3(i,0,n) #define _rep3(i,a,b) for(int i=int(a);i<int(b);++i) #define rep(...) _overload3(__VA_ARGS__,_rep3,_rep2,)(__VA_ARGS__) #define _rrep2(i,n) _rrep3(i,0,n) #define _rrep3(i,a,b) for(int i=int(b)-1;i>=int(a);i--) #define rrep(...) _overload3(__VA_ARGS__,_rrep3,_rrep2,)(__VA_ARGS__) #define all(x) (x).begin(), (x).end() #define bit(n) (1LL<<(n)) #define sz(x) ((int)(x).size()) #define fst first #define snd second using ll=long long;using pii=pair<int,int>; using vb=vector<bool>;using vs=vector<string>; using vi=vector<int>;using vvi=vector<vi>;using vvvi=vector<vvi>; using vl=vector<ll>;using vvl=vector<vl>;using vvvl=vector<vvl>; using vd=vector<double>;using vvd=vector<vd>;using vvvd=vector<vvd>; using vpii=vector<pii>;using vvpii=vector<vpii>;using vvvpii=vector<vvpii>; template<typename T>T read(){T t;cin>>t;return t;} template<class T,class U>ostream&operator<<(ostream&o,const pair<T,U>&p){o<<'('<<p.fst<<", "<<p.snd<<')';return o;} #define A first #define B second typedef long long Integer; Integer gcd(Integer a, Integer b) { return a > 0 ? gcd(b % a, a) : b; } struct rational { Integer p, q; void normalize() { // keep q positive if (q < 0) p *= -1, q *= -1; Integer d = gcd(p < 0 ? -p : p, q); if (d == 0) p = 0, q = 1; else p /= d, q /= d; } rational(Integer p, Integer q = 1) : p(p), q(q) { normalize(); } rational &operator += (const rational &a) { p = a.q * p + a.p * q; q = a.q * q; normalize(); return *this; } rational &operator -= (const rational &a) { p = a.q * p - a.p * q; q = a.q * q; normalize(); return *this; } rational &operator *= (const rational &a) { p *= a.p; q *= a.q; normalize(); return *this; } rational &operator /= (const rational &a) { p *= a.q; q *= a.p; normalize(); return *this; } rational &operator - () { p *= -1; return *this; } }; rational operator + (const rational &a, const rational &b) { return rational(a) += b; } rational operator * (const rational &a, const rational &b) { return rational(a) *= b; } rational operator - (const rational &a, const rational &b) { return rational(a) -= b; } rational operator / (const rational &a, const rational &b) { return rational(a) /= b; } bool operator < (const rational &a, const rational &b) { // avoid overflow return (long double) a.p * b.q < (long double) a.q * b.p; } bool operator <= (const rational &a, const rational &b) { return !(b < a); } bool operator > (const rational &a, const rational &b) { return b < a; } bool operator >= (const rational &a, const rational &b) { return !(a < b); } bool operator == (const rational &a, const rational &b) { return !(a < b) && !(b < a); } bool operator != (const rational &a, const rational &b) { return (a < b) || (b < a); } struct Hash { typedef std::size_t result_type; std::size_t operator()(const rational& key) const; }; inline std::size_t Hash::operator()(const rational& key) const { return (key.p << 32) + key.q; } inline int cmp(int a, int b, int c, int d) { ll ad = a * d; ll cb = c * b; ll ret = ad - cb; if (ret > 0) return 1; if (ret < 0) return -1; return 0; } inline bool cmp_b(const pii &lhs, decltype(lhs) rhs) { return cmp(lhs.A, lhs.B, rhs.A, rhs.B) <= 0; } // a/(a+b) と足したら1を越えるのが何本あるか // O(log |S|) int bs(const rational &ab, const vector<rational> &S) { int ok = sz(S); int ng = -1; while (abs(ok - ng) > 1) { int mid = (ok + ng) / 2; bool c = ab + S[mid] > 1; // cout << "ok: " << ok << ", ng: " << ng << ", "; // cout << "check(" << mid << ") -> " << c << endl; if (c) ok = mid; else ng = mid; } return sz(S) - ok; } void Main() { int n = read<int>(); vector<rational> R[3]; rep(i, n) { int t = read<int>(); int a = read<int>(); int b = read<int>(); R[t].emplace_back(a, a + b); } rep(i, 3) sort(all(R[i])); //rep(ii,3) { cout << "R["<<ii<<"]:"; rep(jj, sz(R[ii])) cout << ' ' << R[ii][jj]; cout << endl; } ll ans = 1 + n; forr(ab, R[1]) { int c0 = bs(ab, R[0]); //_p("R1: a:%d, b:%d, c0: %d\n", a, b, c0); ans += c0; } forr(ab, R[2]) { int c0 = bs(ab, R[0]); int c1 = bs(ab, R[1]); //_p("R2: a:%lld, b:%lld, c0: %d, c1: %d\n", a, b, c0, c1); ans += c0; ans += c1; } // R[0] と R[1] O(N^2) vector<rational> X; map<rational, int> Y; { forr(ab, R[0]) { forr(cd, R[1]) { if (ab + cd >= 1) { if (ab < cd) { X.emplace_back(ab); } else { X.emplace_back(cd); } { auto e = (1-cd) + (1-ab); auto f = cd - (1-ab); if (f > 0) { //Y.emplace_back(e / (e+f)); Y[e / (e+f)]++; } } } } } } // O(N^2 log N^2) TLE? sort(all(X)); //sort(all(Y)); //cout << "X:"; rep(ii,sz(X)) cout << ' ' << X[ii]; cout << endl; // 3本 // O(n * log(N^2)) forr(ab, R[2]) { // b/(a+b) 以上の X を数える rational bab(1 - ab); ans += X.end() - lower_bound(all(X), bab); // 交点に重なる場合を除く //ans -= upper_bound(all(Y), ab) - lower_bound(all(Y), ab); ans -= Y[ab]; } cout << ans << endl; } int main() { cin.tie(nullptr); ios::sync_with_stdio(false); Main(); return 0; }