結果

問題 No.463 魔法使いのすごろく🎲
ユーザー tails
提出日時 2016-12-14 00:42:01
言語 C90
(gcc 12.3.0)
結果
WA  
実行時間 -
コード長 456 bytes
コンパイル時間 303 ms
コンパイル使用メモリ 21,760 KB
実行使用メモリ 10,624 KB
最終ジャッジ日時 2024-11-30 01:54:13
合計ジャッジ時間 19,960 ms
ジャッジサーバーID
（参考情報） 		judge1 / judge4
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ファイルパターン 結果
sample AC * 3
other AC * 23 WA * 10 TLE * 3
権限があれば一括ダウンロードができます
コンパイルメッセージ
main.c:3:1: warning: return type defaults to ‘int’ [-Wimplicit-int]
    3 | main(n,m,h,i,j,k){
      | ^~~~
main.c: In function ‘main’:
main.c:3:1: warning: type of ‘n’ defaults to ‘int’ [-Wimplicit-int]
main.c:3:1: warning: type of ‘m’ defaults to ‘int’ [-Wimplicit-int]
main.c:3:1: warning: type of ‘h’ defaults to ‘int’ [-Wimplicit-int]
main.c:3:1: warning: type of ‘i’ defaults to ‘int’ [-Wimplicit-int]
main.c:3:1: warning: type of ‘j’ defaults to ‘int’ [-Wimplicit-int]
main.c:3:1: warning: type of ‘k’ defaults to ‘int’ [-Wimplicit-int]
main.c:5:9: warning: implicit declaration of function ‘scanf’ [-Wimplicit-function-declaration]
    5 |         scanf("%d%d",&n,&m);
      |         ^~~~~
main.c:1:1: note: include ‘<stdio.h>’ or provide a declaration of ‘scanf’
  +++ |+#include <stdio.h>
    1 | double c[110],e0[110],e1[110];
main.c:5:9: warning: incompatible implicit declaration of built-in function ‘scanf’ [-Wbuiltin-declaration-mismatch]
    5 |         scanf("%d%d",&n,&m);
      |         ^~~~~
main.c:5:9: note: include ‘<stdio.h>’ or provide a declaration of ‘scanf’
main.c:29:9: warning: implicit declaration of function ‘printf’ [-Wimplicit-function-declaration]
   29 |         printf("%.10f\n",e0[1]);
      |         ^~~~~~
main.c:29:9: note: include ‘<stdio.h>’ or provide a declaration of ‘printf’
main.c:29:9: warning: incompatible implicit declaration of built-in function ‘printf’ [-Wbuiltin-declaration-mismatch]
main.c:29:9: note: include ‘<stdio.h>’ or provide a declaration of ‘printf’

ソースコード

diff #
プレゼンテーションモードにする

double c[110],e0[110],e1[110];
main(n,m,h,i,j,k){
    scanf("%d%d",&n,&m);
    for(i=2;i<n;++i){
        scanf("%lf",&c[i]);
    }
    for(h=0;h<100000;++h){
        for(i=n;--i;){
            e0[i]=0;
            e1[i]=0;
            for(j=i+1;j<=i+m;++j){
                k=j<n?j:n*2-j;
                e0[i]+=e0[k]+c[k];
                e1[i]+=e1[k]+c[k];
            }
            e0[i]/=m;
            e1[i]/=m;
            for(j=i+1;j<=i+m;++j){
                k=j<n?j:n*2-j;
                if(e0[i]>e1[k]+c[k]){
                    e0[i]=e1[k]+c[k];
                }
            }
        }
    }
    printf("%.10f\n",e0[1]);
    return 0;
}
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