結果
問題 | No.463 魔法使いのすごろく🎲 |
ユーザー |
|
提出日時 | 2016-12-14 01:27:44 |
言語 | C++11 (gcc 13.3.0) |
結果 |
WA
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実行時間 | - |
コード長 | 2,190 bytes |
コンパイル時間 | 971 ms |
コンパイル使用メモリ | 87,912 KB |
実行使用メモリ | 6,824 KB |
最終ジャッジ日時 | 2024-11-30 06:51:12 |
合計ジャッジ時間 | 2,085 ms |
ジャッジサーバーID (参考情報) |
judge1 / judge3 |
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ファイルパターン | 結果 |
---|---|
sample | AC * 3 |
other | AC * 26 WA * 10 |
コンパイルメッセージ
main.cpp: In function ‘int main()’: main.cpp:66:55: warning: division by zero [-Wdiv-by-zero] 66 | vector<vector<double> > dp(2, vector<double>(n, 1.0 / 0)); | ~~~~^~~
ソースコード
#include <algorithm>#include <bitset>#include <cassert>#include <cctype>#include <cmath>#include <cstdio>#include <cstdlib>#include <cstring>#include <ctime>#include <deque>#include <functional>#include <iomanip>#include <iostream>#include <vector>#define REP(i,s,n) for(int i=(int)(s);i<(int)(n);i++)using namespace std;typedef long long int ll;typedef vector<int> VI;typedef vector<ll> VL;typedef pair<int, int> PI;int gauss_elim(vector<vector<double> > &A,vector<double> &b) {int n = A.size();int m = A[0].size();assert (b.size() == n);int c = 0;// TODO no pivotingREP(i, 0, n) {while (c < m && A[i][c] == 0) {c++;}if (c >= m) {return i;}double aic = A[i][c];A[i][c] = 1;REP(j, c + 1, m) {A[i][j] /= aic;}b[i] /= aic;REP(j, 0, n) {if (i == j) { continue; }double ajc = A[j][c];A[j][c] = 0;REP(k, c + 1, m) {A[j][k] -= ajc * A[i][k];}b[j] -= ajc * b[i];}}return n;}int main(void){int n, m;cin >> n >> m;vector<double> c(n, 0);REP(i, 1, n - 1) {cin >> c[n - 1 - i];}vector<vector<double> > dp(2, vector<double>(n, 1.0 / 0));REP(i, 0, m + 1) {dp[0][i] = 0.0;}// Calculates dp[1][i], by using Gaussian eliminationvector<vector<double> > A(m, vector<double>(m, 0));REP(i, 0, m) {A[i][i] = m;}REP(i, 1, m) {REP(j, 1, m + 1) {A[i][abs(i - j)] -= 1.0;}}vector<double> b(m);REP(i, 0, m) {b[i] = c[i] * m;}int result = gauss_elim(A, b);assert (result == m);REP(i, 0, m) {dp[1][i] = b[i];}REP(i, m, n) {double tot = 0;REP(j, 1, m + 1) {tot += dp[1][i - j] + c[i - j];}dp[1][i] = tot / m;}REP(i, m, n) {double tot = 0;REP(j, 1, m + 1) {tot += dp[0][i - j] + c[i - j];}double mi = tot / m;REP(j, 1, m + 1) {mi = min(mi, dp[1][i - j] + c[i - j]);}dp[0][i] = mi;}if (0) {REP(i, 0, 2) {REP(j, 0, n) {cerr << "dp[" << i << "," << j << "]=" << dp[i][j] << endl;}}}printf("%.15f\n", dp[0][n - 1]);}