結果

問題 No.270 next_permutation (1)
ユーザー koba-e964
提出日時 2017-01-10 17:49:47
言語 Rust
(1.83.0 + proconio)
結果
WA  
(最新)
AC  
(最初)
実行時間 -
コード長 2,466 bytes
コンパイル時間 14,839 ms
コンパイル使用メモリ 396,156 KB
実行使用メモリ 18,048 KB
最終ジャッジ日時 2024-12-21 07:32:47
合計ジャッジ時間 16,219 ms
ジャッジサーバーID
(参考情報)
judge3 / judge4
このコードへのチャレンジ
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ファイルパターン 結果
other AC * 14 WA * 1
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ソースコード

diff #
プレゼンテーションモードにする

#[allow(unused_imports)]
use std::cmp::*;
#[allow(unused_imports)]
use std::collections::*;
use std::io::*;
#[allow(dead_code)]
fn getline() -> String {
let mut ret = String::new();
std::io::stdin().read_line(&mut ret).ok();
return ret;
}
fn get_word() -> String {
let mut stdin = std::io::stdin();
let mut u8b: [u8; 1] = [0];
loop {
let mut buf: Vec<u8> = Vec::with_capacity(16);
loop {
let res = stdin.read(&mut u8b);
if res.is_err() || res.ok().unwrap() == 0 || u8b[0] <= ' ' as u8 {
break;
} else {
buf.push(u8b[0]);
}
}
if buf.len() >= 1 {
let ret = std::string::String::from_utf8(buf).unwrap();
return ret;
}
}
}
fn parse<T: std::str::FromStr>(s: &str) -> T { s.parse::<T>().ok().unwrap() }
#[allow(dead_code)]
fn get<T: std::str::FromStr>() -> T { parse(&get_word()) }
fn next_permutation<T: Ord>(v: &mut [T]) -> usize {
let mut tail_dec: usize = 1;
let n = v.len();
while tail_dec < n {
if v[n - tail_dec - 1] > v[n - tail_dec] {
tail_dec += 1;
} else {
break;
}
}
// v[n - tail_dec .. n] is strictly decreasing
if tail_dec < n {
let x = n - tail_dec - 1;
let mut y = n;
{
let pivot = &v[x];
for i in (n - tail_dec .. n).rev() {
if v[i] > *pivot {
y = i;
break;
}
}
assert!(y < n);
}
v.swap(x, y);
}
v[n - tail_dec .. n].sort();
return max(n - tail_dec, 1) - 1;
}
fn main() {
let n: usize = get();
let k: usize = get();
let mut p: Vec<i64> = (0 .. n).map(|_| get()).collect();
let b: Vec<i64> = (0 .. n).map(|_| get()).collect();
let mut mods: Vec<Vec<(i64, usize)>> = vec![Vec::new(); n];
for i in 0 .. n {
mods[i].push((p[i], 1));
}
let mut tot: i64 = 0;
for stage in 1 .. (k + 1) {
let ret = next_permutation(&mut p);
for i in ret .. n {
mods[i].push((p[i], stage));
}
}
for i in 0 .. n {
mods[i].push((0x1145141919810893, k + 1));
}
for i in 0 .. n {
let m = &mods[i];
for j in 0 .. m.len() - 1 {
tot += (b[i] - m[j].0).abs() * ((m[j + 1].1 - m[j].1) as i64);
}
}
println!("{}", tot);
}
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