結果
問題 | No.270 next_permutation (1) |
ユーザー |
|
提出日時 | 2017-01-10 17:49:47 |
言語 | Rust (1.83.0 + proconio) |
結果 |
WA
(最新)
AC
(最初)
|
実行時間 | - |
コード長 | 2,466 bytes |
コンパイル時間 | 14,839 ms |
コンパイル使用メモリ | 396,156 KB |
実行使用メモリ | 18,048 KB |
最終ジャッジ日時 | 2024-12-21 07:32:47 |
合計ジャッジ時間 | 16,219 ms |
ジャッジサーバーID (参考情報) |
judge3 / judge4 |
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ファイルパターン | 結果 |
---|---|
other | AC * 14 WA * 1 |
ソースコード
#[allow(unused_imports)]use std::cmp::*;#[allow(unused_imports)]use std::collections::*;use std::io::*;#[allow(dead_code)]fn getline() -> String {let mut ret = String::new();std::io::stdin().read_line(&mut ret).ok();return ret;}fn get_word() -> String {let mut stdin = std::io::stdin();let mut u8b: [u8; 1] = [0];loop {let mut buf: Vec<u8> = Vec::with_capacity(16);loop {let res = stdin.read(&mut u8b);if res.is_err() || res.ok().unwrap() == 0 || u8b[0] <= ' ' as u8 {break;} else {buf.push(u8b[0]);}}if buf.len() >= 1 {let ret = std::string::String::from_utf8(buf).unwrap();return ret;}}}fn parse<T: std::str::FromStr>(s: &str) -> T { s.parse::<T>().ok().unwrap() }#[allow(dead_code)]fn get<T: std::str::FromStr>() -> T { parse(&get_word()) }fn next_permutation<T: Ord>(v: &mut [T]) -> usize {let mut tail_dec: usize = 1;let n = v.len();while tail_dec < n {if v[n - tail_dec - 1] > v[n - tail_dec] {tail_dec += 1;} else {break;}}// v[n - tail_dec .. n] is strictly decreasingif tail_dec < n {let x = n - tail_dec - 1;let mut y = n;{let pivot = &v[x];for i in (n - tail_dec .. n).rev() {if v[i] > *pivot {y = i;break;}}assert!(y < n);}v.swap(x, y);}v[n - tail_dec .. n].sort();return max(n - tail_dec, 1) - 1;}fn main() {let n: usize = get();let k: usize = get();let mut p: Vec<i64> = (0 .. n).map(|_| get()).collect();let b: Vec<i64> = (0 .. n).map(|_| get()).collect();let mut mods: Vec<Vec<(i64, usize)>> = vec![Vec::new(); n];for i in 0 .. n {mods[i].push((p[i], 1));}let mut tot: i64 = 0;for stage in 1 .. (k + 1) {let ret = next_permutation(&mut p);for i in ret .. n {mods[i].push((p[i], stage));}}for i in 0 .. n {mods[i].push((0x1145141919810893, k + 1));}for i in 0 .. n {let m = &mods[i];for j in 0 .. m.len() - 1 {tot += (b[i] - m[j].0).abs() * ((m[j + 1].1 - m[j].1) as i64);}}println!("{}", tot);}