#14455 (C++11) No.160 最短経路のうち辞書順最小

• 問題: No.160 最短経路のうち辞書順最小
• ユーザー: purple_jwl
• 提出日時: 2015-03-01 23:52:08
• 言語: C++11 (gcc 13.3.0)
• 結果: WA (最新)
  AC
  (最初)
• 実行時間: -
• コード長: 1,771 bytes
• コンパイル時間: 1,392 ms
• コンパイル使用メモリ: 170,132 KB
• 実行使用メモリ: 6,948 KB
• 最終ジャッジ日時: 2024-06-24 00:42:37
• 合計ジャッジ時間: 2,347 ms
• ジャッジサーバーID （参考情報）: judge3 / judge2

ファイルパターン	結果
sample	AC * 4
other	AC * 8 WA * 18

ソースコード

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#include <bits/stdc++.h>
#define REP(i, x, n) for(int i = x; i < (int)(n); i++)
#define rep(i, n) REP(i, 0, n)
#define all(x) (x).begin(), (x).end()
#define rall(x) (x).rbegin(), (x).rend()
#define F first
#define S second
#define mp make_pair
using namespace std;
typedef long long ll;
typedef unsigned long long ull;
typedef pair<int, int> P;
const int INF = 1 << 30;
struct State {
  int pos, dist;
  State(int p, int d): pos(p), dist(d) {}
  bool operator < (const State &stt) const {
    return stt.dist < dist;
  }
};
struct Edge {
  int to, dist;
  Edge(int t, int d): to(t), dist(d) {}
};
int N, M, S, G;
vector<Edge> edge[200];
int prevN[200];
int minDist[200];
void solve() {
  rep(i, N) {
    prevN[i] = -1;
    minDist[i] = INF;
  }
  priority_queue<State> pq;
  pq.push(State(S, 0));
  minDist[S] = 0;
  while(!pq.empty()) {
    State stt = pq.top();
    pq.pop();
    if(stt.pos == G) break;
    rep(i, edge[stt.pos].size()) {
      int to = edge[stt.pos][i].to;
      int dist = edge[stt.pos][i].dist;
      if(minDist[to] > minDist[stt.pos] + dist ||
         (minDist[to] == minDist[stt.pos] + dist && prevN[to] > stt.pos)) {
        prevN[to] = stt.pos;
        minDist[to] = minDist[stt.pos] + dist;
        pq.push(State(to, minDist[to]));
      }
    }
  }
  vector<int> ans;
  ans.push_back(G);
  for(int p = prevN[G]; p != S; p = prevN[p]) {
    ans.push_back(p);
  }
  ans.push_back(S);
  
  reverse(all(ans));
  rep(i, ans.size()) {
    if(i) cout << ' ';
    cout << ans[i];
  }
  cout << endl;
}
int main() {
  // ios_base::sync_with_stdio(false);
  cin >> N >> M >> S >> G;
  rep(i, M) {
    int a, b, c;
    cin >> a >> b >> c;
    edge[a].push_back(Edge(b, c));
    edge[b].push_back(Edge(a, c));
  }
  solve();
  return 0;
}
 
 
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