結果

問題 No.492 IOI数列
ユーザー antaanta
提出日時 2017-03-10 22:38:02
言語 C++14
(gcc 12.3.0 + boost 1.83.0)
結果
AC  
実行時間 2 ms / 1,000 ms
コード長 2,441 bytes
コンパイル時間 1,695 ms
コンパイル使用メモリ 164,344 KB
実行使用メモリ 4,384 KB
最終ジャッジ日時 2023-09-06 13:22:46
合計ジャッジ時間 2,329 ms
ジャッジサーバーID
(参考情報)
judge11 / judge14
このコードへのチャレンジ(β)

テストケース

テストケース表示
入力 結果 実行時間
実行使用メモリ
testcase_00 AC 2 ms
4,380 KB
testcase_01 AC 2 ms
4,380 KB
testcase_02 AC 1 ms
4,380 KB
testcase_03 AC 1 ms
4,380 KB
testcase_04 AC 1 ms
4,376 KB
testcase_05 AC 2 ms
4,380 KB
testcase_06 AC 2 ms
4,384 KB
testcase_07 AC 1 ms
4,384 KB
testcase_08 AC 1 ms
4,384 KB
testcase_09 AC 1 ms
4,380 KB
testcase_10 AC 2 ms
4,376 KB
testcase_11 AC 1 ms
4,376 KB
testcase_12 AC 1 ms
4,380 KB
testcase_13 AC 2 ms
4,384 KB
testcase_14 AC 2 ms
4,380 KB
testcase_15 AC 1 ms
4,376 KB
testcase_16 AC 2 ms
4,380 KB
testcase_17 AC 1 ms
4,380 KB
testcase_18 AC 2 ms
4,376 KB
testcase_19 AC 2 ms
4,380 KB
testcase_20 AC 2 ms
4,376 KB
testcase_21 AC 1 ms
4,380 KB
権限があれば一括ダウンロードができます

ソースコード

diff #

#include "bits/stdc++.h"
using namespace std;
#define rep(i,n) for(int (i)=0;(i)<(int)(n);++(i))
#define rer(i,l,u) for(int (i)=(int)(l);(i)<=(int)(u);++(i))
#define reu(i,l,u) for(int (i)=(int)(l);(i)<(int)(u);++(i))
static const int INF = 0x3f3f3f3f; static const long long INFL = 0x3f3f3f3f3f3f3f3fLL;
typedef vector<int> vi; typedef pair<int, int> pii; typedef vector<pair<int, int> > vpii; typedef long long ll;
template<typename T, typename U> static void amin(T &x, U y) { if (y < x) x = y; }
template<typename T, typename U> static void amax(T &x, U y) { if (x < y) x = y; }


template<int MOD>
struct ModInt {
	static const int Mod = MOD;
	unsigned x;
	ModInt() : x(0) { }
	ModInt(signed sig) { int sigt = sig % MOD; if (sigt < 0) sigt += MOD; x = sigt; }
	ModInt(signed long long sig) { int sigt = sig % MOD; if (sigt < 0) sigt += MOD; x = sigt; }
	int get() const { return (int)x; }

	ModInt &operator+=(ModInt that) { if ((x += that.x) >= MOD) x -= MOD; return *this; }
	ModInt &operator-=(ModInt that) { if ((x += MOD - that.x) >= MOD) x -= MOD; return *this; }
	ModInt &operator*=(ModInt that) { x = (unsigned long long)x * that.x % MOD; return *this; }
	ModInt &operator/=(ModInt that) { return *this *= that.inverse(); }

	ModInt operator+(ModInt that) const { return ModInt(*this) += that; }
	ModInt operator-(ModInt that) const { return ModInt(*this) -= that; }
	ModInt operator*(ModInt that) const { return ModInt(*this) *= that; }
	ModInt operator/(ModInt that) const { return ModInt(*this) /= that; }

	ModInt inverse() const {
		signed a = x, b = MOD, u = 1, v = 0;
		while (b) {
			signed t = a / b;
			a -= t * b; std::swap(a, b);
			u -= t * v; std::swap(u, v);
		}
		if (u < 0) u += Mod;
		ModInt res; res.x = (unsigned)u;
		return res;
	}

	bool operator==(ModInt that) const { return x == that.x; }
	bool operator!=(ModInt that) const { return x != that.x; }
	ModInt operator-() const { ModInt t; t.x = x == 0 ? 0 : Mod - x; return t; }
};
template<int MOD> ModInt<MOD> operator^(ModInt<MOD> a, unsigned long long k) {
	ModInt<MOD> r = 1;
	while (k) {
		if (k & 1) r *= a;
		a *= a;
		k >>= 1;
	}
	return r;
}
typedef ModInt<1000000007> mint;

int main() {
	long long N;
	while (~scanf("%lld", &N)) {
		mint ans = (mint(1) - (mint(100) ^ N)) / (mint(1) - 100);
		printf("%d\n", ans.get());
		ll ans2 = 0;
		for (ll P = 1, k = N % 11; k > 0; -- k, P *= 100)
			ans2 += P;
		printf("%lld\n", ans2);
	}
	return 0;
}
0