結果
問題 | No.491 10^9+1と回文 |
ユーザー |
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提出日時 | 2017-03-11 02:14:05 |
言語 | C++14 (gcc 13.3.0 + boost 1.87.0) |
結果 |
AC
|
実行時間 | 11 ms / 1,000 ms |
コード長 | 2,343 bytes |
コンパイル時間 | 731 ms |
コンパイル使用メモリ | 94,656 KB |
実行使用メモリ | 5,248 KB |
最終ジャッジ日時 | 2024-10-01 08:28:22 |
合計ジャッジ時間 | 2,747 ms |
ジャッジサーバーID (参考情報) |
judge1 / judge4 |
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ファイルパターン | 結果 |
---|---|
sample | AC * 3 |
other | AC * 103 |
ソースコード
#include <iostream>#include <iomanip>#include <string>#include <vector>#include <queue>#include <algorithm>#include <utility>#include <cmath>#include <map>#include <set>#include <stack>#include <cstdio>#include <cstdlib>#include <cstring>#define INF_LL 1e18#define INF 1e9#define REP(i, n) for(int i = 0;i < (n);i++)#define FOR(i, a, b) for(int i = (a);i < (b);i++)#define all(x) x.begin(),x.end()using namespace std;using ll = long long;using PII = pair<int, int>;template<typename T>void chmax(T &a, T &b){a = max(a, b);}template<typename T>void chmin(T &a, T &b){a = min(a, b);}class Union_find{private:vector<int> par;vector<int> rank;int n;public:Union_find(int a){n = a;for(int i = 0;i < n;i++){par.push_back(i);rank.push_back(0);}}int find(int x){if(par[x] == x){return x;}else{return par[x] = find(par[x]);}}void unite(int x, int y){x = find(x);y = find(y);if(x == y) return;if(rank[x] < rank[y]){par[x] = y;}else{par[y] = x;if(rank[x] == rank[y]) rank[x]++;}}bool same(int x, int y){return find(x) == find(y);}};class RMQ{vector<int> dat;int n;public:RMQ(int n_){n = 1;while(n < n_) n *= 2;REP(i, n*2-1){dat.push_back(INF);}}void update(int x, int i){i += n-1;dat[i] = x;while(i > 0){i = (i-1)/2;dat[i] = min(dat[i*2+1], dat[i*2+2]);}}int query(int a, int b, int l, int r, int k){if(a <= l && r <= b) return dat[k];if(b <= l || r <= a) return INF;return min(query(a, b, l, (l+r)/2, k*2+1), query(a, b, (l+r)/2, r, k*2+2));}int query(int a, int b){return query(a, b, 0, n, 0);}};ll con = 1000000001;const ll mod = 1e9+7;int keta(ll n){int res = 0;while(n > 0){n /= 10;res++;}return res;}ll dbl(ll n, int f){ll res = n * pow(10, keta(n)-f);int p = keta(n)-1-f;if(f)n /= 10;while(n > 0){res += (n%10)*pow(10, p);n/=10;p--;}return res;}int main(void){ll N;ll res = 0;cin >> N;N /= con;int p = 0;int dig = keta(N);if(dig == 0){cout << 0 << endl;return 0;}REP(i, dig-1){if(i < 2){res += 9;}else{res += (ll)9*pow(10, (i+1)/2+(i+1)%2-1);}}for(ll i = pow(10, dig/2+dig%2-1);dbl(i, dig%2) <= N;i++){res++;}cout << res << endl;}