結果
問題 | No.493 とても長い数列と文字列(Long Long Sequence and a String) |
ユーザー |
|
提出日時 | 2017-03-11 17:06:38 |
言語 | C++14 (gcc 13.3.0 + boost 1.87.0) |
結果 |
WA
|
実行時間 | - |
コード長 | 2,819 bytes |
コンパイル時間 | 1,027 ms |
コンパイル使用メモリ | 91,040 KB |
実行使用メモリ | 6,944 KB |
最終ジャッジ日時 | 2024-06-24 12:32:17 |
合計ジャッジ時間 | 3,825 ms |
ジャッジサーバーID (参考情報) |
judge1 / judge5 |
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ファイルパターン | 結果 |
---|---|
sample | AC * 4 |
other | AC * 103 WA * 12 |
ソースコード
#include <iostream>#include <vector>#include <sstream>#include <functional>#include <cassert>#define repeat(i,n) for (int i = 0; (i) < int(n); ++(i))using ll = long long;using namespace std;template <class T> inline void setmin(T & a, T const & b) { a = min(a, b); }ll powmod(ll x, ll y, ll p) { // O(log y)assert (y >= 0);x %= p; if (x < 0) x += p;ll z = 1;for (ll i = 1; i <= y; i <<= 1) {if (y & i) z = z * x % p;x = x * x % p;}return z;}ll inv(ll x, ll p) { // p must be a prime, O(log p)assert ((x % p + p) % p != 0);return powmod(x, p-2, p);}constexpr int mod = 1e9+7;pair<ll, int> from_string(string const & s) {ll sum = 0;int prod = 1;for (char c : s) {int d = (c == '0' ? 10 : c - '0');sum += d;prod = prod *(ll) d % mod;}return { sum, prod };}pair<ll, int> addmul(pair<ll, int> a, pair<ll, int> b) {return { a.first + b.first, a.second *(ll) b.second % mod };}int main() {int k; ll l, r; cin >> k >> l >> r; -- l;vector<string> str { "" };vector<ll> width { 0 };vector<ll> sums { 0 };vector<int> prods { 1 };repeat (i,k) {ostringstream oss;oss << (i+1)*(i+1);string s = oss.str();str.push_back(s);width.push_back(2 * width.back() + s.length());ll sum = 2 * sums.back();int prod = prods.back() *(ll) prods.back() % mod;tie(sum, prod) = addmul(make_pair(sum, prod), from_string(s));sums.push_back(sum);prods.push_back(prod);if (r <= width.back()) break;}setmin<int>(k, width.size() - 1);function<pair<ll, int> (int, ll)> func = [&](int i, ll r) {if (i == 0 or r == 0) {return make_pair(0ll, 1);} else if (r < width[i]) {return func(i-1, r);} else if (r == width[i]) {return make_pair(sums[i], prods[i]);} else if (r < width[i] + str[i].length()) {ll sum = sums[i];int prod = prods[i];string s = str[i+1].substr(0, r - width[i]);return addmul(make_pair(sum, prod), from_string(s));} else {assert (r <= width[i] + str[i].length() + width[i]);ll sum = sums[i];int prod = prods[i];string s = str[i+1];ll nr = r - width[i] - s.length();return addmul(addmul(make_pair(sum, prod), from_string(s)), func(i-1, nr));}};if (width.back() < r) {cout << -1 << endl;} else {ll lsum; int lprod; tie(lsum, lprod) = func(k, l);ll rsum; int rprod; tie(rsum, rprod) = func(k, r);cout << (rsum - lsum) << ' ' << (rprod *(ll) inv(lprod, mod) % mod) << endl;}return 0;}