結果

問題 No.493 とても長い数列と文字列(Long Long Sequence and a String）
ユーザー しらっ亭
提出日時 2017-03-11 21:01:55
言語 C++14
(gcc 13.3.0 + boost 1.87.0)
結果
AC  
実行時間 2 ms / 800 ms
コード長 5,709 bytes
コンパイル時間 1,942 ms
コンパイル使用メモリ 177,960 KB
実行使用メモリ 6,948 KB
最終ジャッジ日時 2024-06-24 13:08:16
合計ジャッジ時間 4,874 ms
ジャッジサーバーID
（参考情報） 		judge4 / judge1
このコードへのチャレンジ
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ファイルパターン 結果
sample AC * 4
other AC * 115
権限があれば一括ダウンロードができます

ソースコード

diff #
プレゼンテーションモードにする

#include <bits/stdc++.h>
using namespace std;
#define _p(...) (void)printf(__VA_ARGS__)
#define forr(x,arr) for(auto&& x:arr)
#define _overload3(_1,_2,_3,name,...) name
#define _rep2(i,n) _rep3(i,0,n)
#define _rep3(i,a,b) for(int i=int(a);i<int(b);++i)
#define rep(...) _overload3(__VA_ARGS__,_rep3,_rep2,)(__VA_ARGS__)
#define _rrep2(i,n) _rrep3(i,0,n)
#define _rrep3(i,a,b) for(int i=int(b)-1;i>=int(a);i--)
#define rrep(...) _overload3(__VA_ARGS__,_rrep3,_rrep2,)(__VA_ARGS__)
#define all(x) (x).begin(), (x).end()
#define bit(n) (1LL<<(n))
#define sz(x) ((int)(x).size())
#define fst first
#define snd second
using ll=long long;
using pii=pair<int,int>;using pll=pair<ll,ll>;using pil=pair<int,ll>;using pli=pair<ll,int>;
using vs=vector<string>;using vvs=vector<vs>;using vvvs=vector<vvs>;
using vb=vector<bool>;using vvb=vector<vb>;using vvvb=vector<vvb>;
using vi=vector<int>;using vvi=vector<vi>;using vvvi=vector<vvi>;
using vl=vector<ll>;using vvl=vector<vl>;using vvvl=vector<vvl>;
using vd=vector<double>;using vvd=vector<vd>;using vvvd=vector<vvd>;
using vpii=vector<pii>;using vvpii=vector<vpii>;using vvvpii=vector<vvpii>;
template<class T,class U>istream&operator>>(istream&is,pair<T,U>&P){is>>P.fst;is>>P.snd;return is;}
template<class T>T read(){T t;cin>>t;return t;}
template<class T,class U>ostream&operator<<(ostream&o,const pair<T,U>&p){return o<<'('<<p.fst<<", "<<p.snd<<')';}
template<class T>ostream&operator<<(ostream&o,const vector<T>&t){o<<"{";rep(i,sz(t))o<<t[i]<<",";o<<"}"<<endl;return o;}
#ifdef LOCAL
vs s_p_l_i_t(const string&s,char c){vs v;stringstream ss(s);string x;while(getline(ss,x,c))v.emplace_back(x);return move(v);}
void e_r_r(vs::iterator it){cerr<<endl;}
template<class T,class... Args>void e_r_r(vs::iterator it,T a,Args... args){cerr<<it->substr((*it)[0]==' ',it->length())<<" = "<<a<<", ";e_r_r(++it
    ,args...);}
#define out(args...){vs a_r_g_s=s_p_l_i_t(#args,',');e_r_r(a_r_g_s.begin(),args);}
#else
#define out(args...)
#endif
const int mod = 1000000007;
template<int MOD>
struct Mint {
  int x;
  Mint() : x(0) {}
  Mint(int y) : x(y >= 0 ? y % MOD : MOD - (-y) % MOD) {}
  Mint(signed long long sll) : x(sll % MOD) { if (x < 0) x += MOD; }
  Mint &operator+=(const Mint &rhs){ if((x += rhs.x) >= MOD) x -= MOD; return *this; }
  Mint &operator-=(const Mint &rhs){ if((x += MOD - rhs.x) >= MOD) x -= MOD; return *this; }
  Mint &operator*=(const Mint &rhs){ x = 1LL*x*rhs.x % MOD; return *this; }
  Mint &operator/=(const Mint &rhs){ x = (1LL*x*rhs.inv().x) % MOD; return *this; }
  Mint operator-() const { return Mint(-x); }
  Mint operator+(const Mint &rhs) const { return Mint(*this) += rhs; }
  Mint operator-(const Mint &rhs) const { return Mint(*this) -= rhs; }
  Mint operator*(const Mint &rhs) const { return Mint(*this) *= rhs; }
  Mint operator/(const Mint &rhs) const { return Mint(*this) /= rhs; }
  bool operator<(const Mint &rhs) const { return x < rhs.x; }
  Mint inv() const {
    signed a = x, b = MOD, u = 1, v = 0, t;
    while(b){ t = a / b; a -= t * b; swap(a, b); u -= t * v; swap(u, v); }
    return Mint(u);
  }
  Mint operator^(unsigned long long t) const {
    Mint e = *this, res = 1;
    for(; t; e *= e, t>>=1) if (t & 1) res *= e;
    return res;
  }
};
template<int MOD> ostream &operator<<(ostream &os, const Mint<MOD> &rhs) { return os << rhs.x; }
template<int MOD> istream &operator>>(istream &is, Mint<MOD> &rhs) { long long s; is >> s; rhs = Mint<MOD>(s); return is; };
using mint = Mint<mod>;
using vm=vector<mint>;using vvm=vector<vm>;using vvvm=vector<vvm>;
const int B = 63;
vs strs(B);
vl lens(B);
vl sums(B);
vm muls(B);
pair<ll, mint> calc(ll l, ll r, int k) {
  if (k == 0 || l == r) {
    return {0, 1};
  }
  if (l == 0 && r == lens[k]) {
    return {sums[k], muls[k]};
  }
  ll p1 = lens[k-1];
  ll p2 = lens[k] - p1;
  if (l < p1 && r <= p1) {
    // lef, lef
    return calc(l, r, k-1);
  }
  else if (l < p1 && r <= p2) {
    // lef, mid
    auto a1 = calc(l, lens[k-1], k-1);
    rep(i, r-p1) {
      int d = strs[k][i] - '0';
      if (d == 0) d = 10;
      a1.fst += d;
      a1.snd *= d;
    }
    return a1;
  }
  else if (l < p1) {
    // lef, rig
    auto a1 = calc(l, lens[k-1], k-1);
    auto a2 = calc(0, r-p2, k-1);
    rep(i, p2-p1) {
      int d = strs[k][i] - '0';
      if (d == 0) d = 10;
      a1.fst += d;
      a1.snd *= d;
    }
    a1.fst += a2.fst;
    a1.snd *= a2.snd;
    return a1;
  }
  else if (l < p2 && r <= p2) {
    // mid, mid
    pair<ll, mint> a1{0, 1};
    rep(i, l - p1, r - p1) {
      int d = strs[k][i] - '0';
      if (d == 0) d = 10;
      a1.fst += d;
      a1.snd *= d;
    }
    return a1;
  }
  else if (l < p2) {
    // mid, rig
    auto a1 = calc(0, r-p2, k-1);
    rep(i, l-p1, p2-p1) {
      int d = strs[k][i] - '0';
      if (d == 0) d = 10;
      a1.fst += d;
      a1.snd *= d;
    }
    return a1;
  }
  else {
    // rig, rig
    return calc(l-p2, r-p2, k-1);
  }
}
void Main() {
  int k = read<int>();
  ll l = read<ll>() - 1;
  ll r = read<ll>();
  sums[1] = 1;
  lens[1] = 1;
  muls[1] = 1;
  strs[1] = "1";
  rep(i, 2, B) {
    strs[i] = to_string(i * i);
    lens[i] = lens[i-1] * 2;
    sums[i] = sums[i-1] * 2;
    muls[i] = muls[i-1] * muls[i-1];
    lens[i] += sz(strs[i]);
    forr(c, strs[i]) {
      int d = c - '0';
      if (d == 0) d = 10;
      sums[i] += d;
      muls[i] *= d;
    }
  }
  //out(lens);
  //out(sums);
  //out(muls);
  //out(strs);
  //out(l, r, lens[k]);
  if (k >= B) k = B-1;
  if (r > lens[k]) {
    cout << -1 << endl;
    return;
  }
  auto ans = calc(l, r, k);
  cout << ans.fst << ' ' << ans.snd << endl;
}
int main() { cin.tie(nullptr); ios::sync_with_stdio(false); Main(); return 0; }
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