結果

問題 No.8024 等式
ユーザー kimiyuki
提出日時 2017-04-01 02:01:41
言語 C++14
(gcc 13.3.0 + boost 1.87.0)
結果
WA  
実行時間 -
コード長 2,488 bytes
コンパイル時間 887 ms
コンパイル使用メモリ 78,272 KB
実行使用メモリ 6,940 KB
最終ジャッジ日時 2024-07-07 15:06:23
合計ジャッジ時間 3,271 ms
ジャッジサーバーID
（参考情報） 		judge5 / judge3
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ファイルパターン 結果
other AC * 22 WA * 1
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ソースコード

diff # 

#pragma GCC optimize "O3"
#pragma GCC target "avx"
#include <cstdio>
#include <vector>
#include <algorithm>
#include <array>
#include <stack>
#include <set>
#include <map>
#include <queue>
#include <tuple>
#include <unordered_set>
#include <unordered_map>
#include <functional>
#include <cassert>
#define repeat(i,n) for (int i = 0; (i) < int(n); ++(i))
#define whole(f,x,...) ([&](decltype((x)) whole) { return (f)(begin(whole), end(whole), ## __VA_ARGS__); })(x)
using ll = long long;
using namespace std;

ll gcd(ll a, ll b) { while (a) { b %= a; swap(a, b); } return b; }
struct rational_t {
    ll p, q;
    rational_t() : p(0), q(1) {}
    rational_t(ll num, ll den = 1) : p(num), q(p ? den : 1) {}
    rational_t(rational_t const & other) : p(other.p), q(other.q) {}
    rational_t & operator = (rational_t const & other) { this->p = other.p; this->q = other.q; return *this; }
    bool operator == (rational_t other) const { return this->p == other.p and this->q == other.q; }
    rational_t operator + (rational_t other) const { return { this->p * other.q + other.p * this->q, this->q * other.q }; }
    rational_t operator - (rational_t other) const { return { this->p * other.q - other.p * this->q, this->q * other.q }; }
    rational_t operator * (rational_t other) const { return { this->p * other.p, this->q * other.q }; }
    rational_t operator / (rational_t other) const { return { this->p * other.q, this->q * other.p }; }
};

constexpr int max_n = 7;
struct loop_exception {};
int main() {
    int n; scanf("%d", &n);
    vector<int> a(n); repeat (i,n) scanf("%d", &a[i]);
    whole(sort, a);
    bool found = false;
    array<rational_t, max_n> x;
    repeat (i,n) x[i] = rational_t(a[i]);
    function<void (int)> go = [&](int n) {
        if (n <= 1) return;
        repeat (j,n) {
            swap(x[j], x[n-1]);
            repeat (i,j) {
                if (x[i] == x[n-1]) {
                    throw loop_exception {};
                }
                rational_t saved = x[i];
                x[i] = saved + x[n-1]; go(n-1);
                x[i] = saved - x[n-1]; go(n-1);
                x[i] = saved * x[n-1]; go(n-1);
                if (x[n-1].p) {
                    x[i] = saved / x[n-1]; go(n-1);
                }
                x[i] = saved;
            }
            swap(x[j], x[n-1]);
        }
    };
    try {
        go(n);
    } catch (loop_exception e) {
        found = true;
    }
    printf("%s\n", found ? "YES" : "NO");
    return 0;
}
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