結果

問題 No.260 世界のなんとか3
ユーザー tomatonosuke
提出日時 2017-04-05 00:41:34
言語 PyPy3
(7.3.15)
結果
MLE  
実行時間 -
コード長 2,181 bytes
コンパイル時間 208 ms
コンパイル使用メモリ 81,920 KB
実行使用メモリ 89,036 KB
最終ジャッジ日時 2024-07-08 09:12:00
合計ジャッジ時間 3,714 ms
ジャッジサーバーID
（参考情報） 		judge4 / judge5
このコードへのチャレンジ
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ファイルパターン 結果
sample AC * 1 MLE * 2
other AC * 1 MLE * 26
権限があれば一括ダウンロードができます

ソースコード

diff # 

minnum,maxnum = (n for n in input().split(" "))
minnum = str(int(minnum))
maxnum = str(int(maxnum) + 1)
min_len = len(minnum)
max_len = len(maxnum)
modu = 10 ** 9 + 7
maxdp = [[[[[0 for n in range(8)] for m in range(3)] for k in range(2)] for l in range(2)] for o in range(max_len + 1)]
mindp = [[[[[0 for n in range(8)] for m in range(3)] for k in range(2)] for l in range(2)] for o in range(min_len + 1)]
maxdp[0][0][0][0][0] = 1
mindp[0][0][0][0][0] = 1
for l in range(max_len):
    for over_flag in range(2):
        for is_three in range(2):
            for three_mod in range(3):
                for eight_mod in range(8):
                    limit = 9 if over_flag else int(maxnum[l])
                    for lim in range(limit + 1):
                        maxdp[l + 1][over_flag or lim < limit][is_three or lim == 3][(three_mod * 10 + lim) % 3][(eight_mod * 10 + lim) % 8] += (maxdp[l][over_flag][is_three][three_mod][eight_mod]) % modu
for l in range(min_len):
    for over_flag in range(2):
        for is_three in range(2):
            for three_mod in range(3):
                for eight_mod in range(8):
                    limit = 9 if over_flag else int(minnum[l])
                    for lim in range(limit + 1):
                        mindp[l + 1][over_flag or lim < limit][is_three or lim == 3][(three_mod * 10 + lim) % 3][(eight_mod * 10 + lim) % 8] += (mindp[l][over_flag][is_three][three_mod][eight_mod]) % modu
max_number = 0
min_number = 0

for over_flag in range(2):
    for is_three in range(2):
        for three_mod in range(3):
            for eight_mod in range(1,8):
                if over_flag and (is_three or three_mod == 0):
                    min_number = (min_number + mindp[min_len][over_flag][is_three][three_mod][eight_mod]) % modu

for over_flag in range(2):
    for is_three in range(2):
        for three_mod in range(3):
            for eight_mod in range(1,8):
                if over_flag and (is_three or three_mod == 0):
                    max_number = (max_number + maxdp[max_len][over_flag][is_three][three_mod][eight_mod]) % modu
# print(maxdp , mindp)
# print(max_number , min_number)
print((max_number - min_number) % modu)
0