結果
問題 | No.171 スワップ文字列(Med) |
ユーザー |
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提出日時 | 2015-03-22 23:27:58 |
言語 | C++11(廃止可能性あり) (gcc 13.3.0) |
結果 |
AC
|
実行時間 | 4 ms / 1,000 ms |
コード長 | 3,324 bytes |
コンパイル時間 | 846 ms |
コンパイル使用メモリ | 95,240 KB |
実行使用メモリ | 5,376 KB |
最終ジャッジ日時 | 2024-06-29 00:10:18 |
合計ジャッジ時間 | 1,516 ms |
ジャッジサーバーID (参考情報) |
judge2 / judge1 |
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ファイルパターン | 結果 |
---|---|
sample | AC * 3 |
other | AC * 10 |
ソースコード
#include <string>#include <vector>#include <algorithm>#include <numeric>#include <set>#include <map>#include <queue>#include <iostream>#include <sstream>#include <cstdio>#include <cmath>#include <ctime>#include <cstring>#include <cctype>#include <cassert>#include <limits>#include <functional>#define rep(i,n) for(int (i)=0;(i)<(int)(n);++(i))#define rer(i,l,u) for(int (i)=(int)(l);(i)<=(int)(u);++(i))#define reu(i,l,u) for(int (i)=(int)(l);(i)<(int)(u);++(i))#if defined(_MSC_VER) || __cplusplus > 199711L#define aut(r,v) auto r = (v)#else#define aut(r,v) __typeof(v) r = (v)#endif#define each(it,o) for(aut(it, (o).begin()); it != (o).end(); ++ it)#define all(o) (o).begin(), (o).end()#define pb(x) push_back(x)#define mp(x,y) make_pair((x),(y))#define mset(m,v) memset(m,v,sizeof(m))#define INF 0x3f3f3f3f#define INFL 0x3f3f3f3f3f3f3f3fLLusing namespace std;typedef vector<int> vi; typedef pair<int,int> pii; typedef vector<pair<int,int> > vpii; typedef long long ll;template<typename T, typename U> inline void amin(T &x, U y) { if(y < x) x = y; }template<typename T, typename U> inline void amax(T &x, U y) { if(x < y) x = y; }template<int MOD>struct ModInt {static const int Mod = MOD;unsigned x;ModInt(): x(0) { }ModInt(signed sig) { int sigt = sig % MOD; if(sigt < 0) sigt += MOD; x = sigt; }ModInt(signed long long sig) { int sigt = sig % MOD; if(sigt < 0) sigt += MOD; x = sigt; }int get() const { return (int)x; }ModInt &operator+=(ModInt that) { if((x += that.x) >= MOD) x -= MOD; return *this; }ModInt &operator-=(ModInt that) { if((x += MOD - that.x) >= MOD) x -= MOD; return *this; }ModInt &operator*=(ModInt that) { x = (unsigned long long)x * that.x % MOD; return *this; }ModInt operator+(ModInt that) const { return ModInt(*this) += that; }ModInt operator-(ModInt that) const { return ModInt(*this) -= that; }ModInt operator*(ModInt that) const { return ModInt(*this) *= that; }};typedef ModInt<573> mint;template<int MOD> ModInt<MOD> operator^(ModInt<MOD> a, unsigned long long k) {ModInt<MOD> r = 1;while(k) {if(k & 1) r *= a;a *= a;k >>= 1;}return r;}vector<int> smallestPrimeFactor;void getSmallestPrimeFactors(int n) {n = max(n, 1);if((int)smallestPrimeFactor.size() >= n+1) return;smallestPrimeFactor.assign(n+1, 0);smallestPrimeFactor[1] = 1;rer(i, 2, n) if(!smallestPrimeFactor[i]) {smallestPrimeFactor[i] = i;if((ll)i * i <= n)for(int j = i * i; j <= n; j += i)if(!smallestPrimeFactor[j]) smallestPrimeFactor[j] = i;}}typedef int FactorsInt;typedef vector<pair<FactorsInt,int> > Factors;void primeFactors(FactorsInt x, Factors &out_v) {getSmallestPrimeFactors(x);out_v.clear();while(x != 1) {int p = smallestPrimeFactor[x], k = 0;x /= p, k ++;while(x % p == 0) x /= p, k ++;out_v.push_back(make_pair(p, k));}}int main() {string S;cin >> S;vi cnt(26, 0);rep(i, S.size()) ++ cnt[S[i] - 'A'];vi fact(1001, 0);rer(i, 1, S.size())++ fact[i];rep(a, 26) {rer(i, 1, cnt[a])-- fact[i];}map<int,int> ps;Factors fs;rer(i, 1, 1000) {primeFactors(i, fs);each(j, fs)ps[j->first] += j->second * fact[i];}mint ans = 1;each(i, ps)ans *= mint(i->first) ^ i->second;ans -= 1;cout << ans.get() << endl;return 0;}