結果

問題 No.500 階乗電卓
ユーザー kou6839kou6839
提出日時 2017-05-02 13:56:03
言語 C++11
(gcc 13.3.0)
結果
AC  
実行時間 4 ms / 2,000 ms
コード長 3,992 bytes
コンパイル時間 1,110 ms
コンパイル使用メモリ 107,272 KB
実行使用メモリ 5,888 KB
最終ジャッジ日時 2024-06-25 03:00:11
合計ジャッジ時間 1,993 ms
ジャッジサーバーID
(参考情報)
judge1 / judge3
このコードへのチャレンジ
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ファイルパターン 結果
sample AC * 3
other AC * 20
権限があれば一括ダウンロードができます

ソースコード

diff #
プレゼンテーションモードにする

#include <vector>
#include <list>
#include <map>
#include <set>
#include <queue>
#include <deque>
#include <stack>
#include <bitset>
#include <algorithm>
#include <functional>
#include <numeric>
#include <utility>
#include <sstream>
#include <iostream>
#include <iomanip>
#include <cstdio>
#include <cmath>
#include <cstdlib>
#include <cctype>
#include <string>
#include <cstring>
#include <ctime>
#include <fstream>
#define _USE_MATH_DEFINES
#include <math.h>
using namespace std;
inline int toInt(string s) { int v; istringstream sin(s); sin >> v; return v; }
template<class T> inline string toString(T x) { ostringstream sout; sout << x; return sout.str(); }
template<class T> inline T sqr(T x) { return x*x; }
typedef vector<int> vi;
typedef vector<vi> vvi;
typedef vector<long long int> vll;
typedef vector<string> vs;
typedef pair<int, int> pii;
typedef long long ll;
typedef unsigned long long ull;
//repetition
//------------------------------------------
#define FOR(i,a,b) for(int i=(a);i<(b);++i)
#define rep(i,n) FOR(i,0,n)
#define P(p) cout<<(p)<<endl;
#define VEC_2D(a,b) vector<vector<int> >(a, vector<int>(b, 0))
#define ALL(a) (a).begin(),(a).end()
#define RALL(a) (a).rbegin(), (a).rend()
#define pb push_back
#define mp make_pair
#define INF (1100000000)
#define SZ(a) int((a).size())
#define EACH(i,c) for(typeof((c).begin()) i=(c).begin(); i!=(c).end(); ++i)
#define EXIST(s,e) ((s).find(e)!=(s).end())
#define SORT(c) sort((c).begin(),(c).end())
#define MOD 1000000007LL
#define FSP(a) cout << fixed << setprecision(a)
ll gcd(ll x, ll y) {
if (y == 0) return x;
else return gcd(y, x%y);
}
ll lcm(ll a, ll b) {
return a / gcd(a, b) * b;
}
bool is_prime(int n) {
for (int i = 2; i * i <= n; i++) {
if (n % i == 0) return false;
}
return n != 1;
}
map<int, int> prime_factor(int n) {
map<int, int> res;
for (int i = 2; i * i <= n; i++) {
while (n % i == 0) {
++res[i];
n /= i;
}
}
if (n != 1) res[n] = 1;
return res;
}
int extgcd(int a, int b, int& x, int& y) {//
int d = a;
if (b != 0) {
d = extgcd(b, a%b, y, x);
y -= (a / b)*x;
}
else {
x = 1; y = 0;
}
return d;
}
ll mod_pow(ll x, ll n, ll mod) {
if (n == 0) return 1;
ll res = mod_pow(x * x % mod, n / 2, mod);
if (n & 1) res = res * x % mod;
return res;
}
vector<string> split(const string &str, char delim) {
vector<string> res;
size_t current = 0, found;
while ((found = str.find_first_of(delim, current)) != string::npos) {
res.push_back(string(str, current, found - current));
current = found + 1;
}
res.push_back(string(str, current, str.size() - current));
return res;
}
bool is_kadomatsu(int a, int b, int c) {
if (a == b || a == c || b == c)return false;
if (a > b && c > b) return true;
if (a < b && c < b)return true;
return false;
}
struct UF {
int n;
vi d;
UF() {}
UF(int n) :n(n), d(n, -1) {}
int root(int v) {
if (d[v] < 0) return v;
return d[v] = root(d[v]);
}
bool unite(int x, int y) {
x = root(x); y = root(y);
if (x == y) return false;
if (size(x) < size(y)) swap(x, y);
d[x] += d[y];
d[y] = x;
return true;
}
int size(int v) { return -d[root(v)]; }
};
vector<int> divisor(int n) {
if (n == 1) return{};
vi res;
for (int i = 1; i*i <= n; i++) {
if (n%i == 0) {
res.emplace_back(i);
if (i != 1 && i != n / i)res.emplace_back(n / i);
}
}
return res;
}
//-------------------------------------------------------------
int N, M;
vi g[100005];
int used[100005];
deque<int> deq;
void dfs(int now, int pos) {
for (int v: g[now]) {
if (used[v] == 0) {
if (pos == 1) {
deq.push_back(v);
} else {
deq.push_front(v);
}
used[v] = 1;
dfs(v, pos);
return;
}
}
}
int main() {
ll n;
cin >> n;
if (n >= 60) {
P("000000000000");
return 0;
}
ll mul = 1;
for (ll i = n; i >= 1; i--) {
mul *= i;
mul %= 100000000000000;
}
if (mul >= 1000000000000) {
cout << setfill('0') << setw(12) << right << (mul % 1000000000000);
}
else {
P(mul);
}
return 0;
}
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