結果
問題 | No.513 宝探し2 |
ユーザー | tsutaj |
提出日時 | 2017-05-05 23:07:43 |
言語 | C++14 (gcc 12.3.0 + boost 1.83.0) |
結果 |
WA
|
実行時間 | - |
コード長 | 2,988 bytes |
コンパイル時間 | 880 ms |
コンパイル使用メモリ | 100,104 KB |
実行使用メモリ | 25,604 KB |
平均クエリ数 | 112.00 |
最終ジャッジ日時 | 2024-07-16 13:08:47 |
合計ジャッジ時間 | 3,183 ms |
ジャッジサーバーID (参考情報) |
judge3 / judge2 |
(要ログイン)
テストケース
テストケース表示入力 | 結果 | 実行時間 実行使用メモリ |
---|---|---|
testcase_00 | WA | - |
testcase_01 | WA | - |
testcase_02 | AC | 23 ms
25,220 KB |
testcase_03 | WA | - |
testcase_04 | AC | 23 ms
24,580 KB |
testcase_05 | AC | 22 ms
25,220 KB |
testcase_06 | WA | - |
testcase_07 | WA | - |
testcase_08 | AC | 22 ms
24,580 KB |
testcase_09 | AC | 21 ms
24,836 KB |
testcase_10 | WA | - |
testcase_11 | AC | 22 ms
24,836 KB |
コンパイルメッセージ
In file included from /home/linuxbrew/.linuxbrew/Cellar/gcc@12/12.3.0/include/c++/12/iostream:39, from main.cpp:1: In member function 'std::basic_ostream<_CharT, _Traits>::__ostream_type& std::basic_ostream<_CharT, _Traits>::operator<<(long long int) [with _CharT = char; _Traits = std::char_traits<char>]', inlined from 'int main()' at main.cpp:128:26: /home/linuxbrew/.linuxbrew/Cellar/gcc@12/12.3.0/include/c++/12/ostream:202:25: warning: 'ay' may be used uninitialized [-Wmaybe-uninitialized] 202 | { return _M_insert(__n); } | ~~~~~~~~~^~~~~ main.cpp: In function 'int main()': main.cpp:72:13: note: 'ay' was declared here 72 | int ax, ay, mx = INF, my = INF; | ^~ In member function 'std::basic_ostream<_CharT, _Traits>::__ostream_type& std::basic_ostream<_CharT, _Traits>::operator<<(long long int) [with _CharT = char; _Traits = std::char_traits<char>]', inlined from 'int main()' at main.cpp:105:17: /home/linuxbrew/.linuxbrew/Cellar/gcc@12/12.3.0/include/c++/12/ostream:202:25: warning: 'ax' may be used uninitialized [-Wmaybe-uninitialized] 202 | { return _M_insert(__n); } | ~~~~~~~~~^~~~~ main.cpp: In function 'int main()': main.cpp:72:9: note: 'ax' was declared here 72 | int ax, ay, mx = INF, my = INF; | ^~
ソースコード
#include <iostream> #include <iomanip> #include <cstdio> #include <string> #include <cstring> #include <deque> #include <list> #include <queue> #include <stack> #include <vector> #include <utility> #include <algorithm> #include <map> #include <set> #include <complex> #include <cmath> #include <limits> #include <cfloat> #include <climits> #include <ctime> #include <cassert> #include <numeric> using namespace std; #define rep(i,a,n) for(int (i)=(a); (i)<(n); (i)++) #define repq(i,a,n) for(int (i)=(a); (i)<=(n); (i)++) #define repr(i,a,n) for(int (i)=(a); (i)>=(n); (i)--) #define all(v) begin(v), end(v) #define pb(a) push_back(a) #define fr first #define sc second #define INF 2000000000 #define int long long int #define X real() #define Y imag() #define EPS (1e-10) #define EQ(a,b) (abs((a) - (b)) < EPS) #define EQV(a,b) ( EQ((a).X, (b).X) && EQ((a).Y, (b).Y) ) #define LE(n, m) ((n) < (m) + EPS) #define LEQ(n, m) ((n) <= (m) + EPS) #define GE(n, m) ((n) + EPS > (m)) #define GEQ(n, m) ((n) + EPS >= (m)) typedef vector<int> VI; typedef vector<VI> MAT; typedef pair<int, int> pii; typedef long long ll; typedef complex<double> P; typedef pair<P, P> L; typedef pair<P, double> C; int dx[]={1, -1, 0, 0}; int dy[]={0, 0, 1, -1}; int const MOD = 1000000007; ll mod_pow(ll x, ll n) {return (!n)?1:(mod_pow((x*x)%MOD,n/2)*((n&1)?x:1))%MOD;} int madd(int a, int b) {return (a + b) % MOD;} int msub(int a, int b) {return (a - b + MOD) % MOD;} int mmul(int a, int b) {return (a * b) % MOD;} int minv(int a) {return mod_pow(a, MOD-2);} int mdiv(int a, int b) {return mmul(a, minv(b));} namespace std { bool operator<(const P& a, const P& b) { return a.X != b.X ? a.X < b.X : a.Y < b.Y; } } signed main() { int ubx = 100010, lbx = 0, uby = 100010, lby = 0; int ax, ay, mx = INF, my = INF; while(ubx - lbx > 3) { int l = (ubx + 2*lbx) / 3; int r = (2*ubx + lbx) / 3; int kl, kr; cout << l << " " << 0 << endl; cin >> kl; cout << r << " " << 0 << endl; cin >> kr; if(kl < kr) { ubx = r; } else { lbx = l; } } int idx = lbx, inp; while(idx <= ubx) { cout << idx << " " << 0 << endl; cin >> inp; if(mx > inp) { mx = inp; ax = idx; } idx++; } while(uby - lby > 3) { int r = (2*uby + lby) / 3; int l = (uby + 2*lby) / 3; int kl, kr; cout << ax << " " << l << endl; cin >> kl; cout << ax << " " << r << endl; cin >> kr; if(kl < kr) { uby = r; } else { lby = l; } } idx = lby; while(idx <= uby) { cout << ax << " " << idx << endl; cin >> inp; if(my > inp) { my = inp; ay = idx; } idx++; } int ans; cout << ax << " " << ay << endl; cin >> ans; return 0; }