結果
問題 | No.518 ローマ数字の和 |
ユーザー |
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提出日時 | 2017-05-28 22:16:32 |
言語 | C++11(廃止可能性あり) (gcc 13.3.0) |
結果 |
AC
|
実行時間 | 2 ms / 2,000 ms |
コード長 | 2,628 bytes |
コンパイル時間 | 1,354 ms |
コンパイル使用メモリ | 165,272 KB |
実行使用メモリ | 5,376 KB |
最終ジャッジ日時 | 2024-09-21 15:32:49 |
合計ジャッジ時間 | 2,145 ms |
ジャッジサーバーID (参考情報) |
judge4 / judge5 |
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ファイルパターン | 結果 |
---|---|
sample | AC * 3 |
other | AC * 19 |
ソースコード
#include <bits/stdc++.h>using namespace std;typedef long long signed int LL;typedef long long unsigned int LU;#define incID(i, l, r) for(int i = (l) ; i < (r); i++)#define incII(i, l, r) for(int i = (l) ; i <= (r); i++)#define decID(i, l, r) for(int i = (r) - 1; i >= (l); i--)#define decII(i, l, r) for(int i = (r) ; i >= (l); i--)#define inc(i, n) incID(i, 0, n)#define inc1(i, n) incII(i, 1, n)#define dec(i, n) decID(i, 0, n)#define dec1(i, n) decII(i, 1, n)#define inII(v, l, r) ((l) <= (v) && (v) <= (r))#define inID(v, l, r) ((l) <= (v) && (v) < (r))#define PB push_back#define EB emplace_back#define MP make_pair#define FI first#define SE second#define UB upper_bound#define LB lower_bound#define PQ priority_queue#define ALL(v) v.begin(), v.end()#define RALL(v) v.rbegin(), v.rend()#define FOR(it, v) for(auto it = v.begin(); it != v.end(); ++it)#define RFOR(it, v) for(auto it = v.rbegin(); it != v.rend(); ++it)template<typename T> bool setmin(T & a, T b) { if(b < a) { a = b; return true; } else { return false; } }template<typename T> bool setmax(T & a, T b) { if(b > a) { a = b; return true; } else { return false; } }template<typename T> bool setmineq(T & a, T b) { if(b <= a) { a = b; return true; } else { return false; } }template<typename T> bool setmaxeq(T & a, T b) { if(b >= a) { a = b; return true; } else { return false; } }template<typename T> T gcd(T a, T b) { return (b == 0 ? a : gcd(b, a % b)); }template<typename T> T lcm(T a, T b) { return a / gcd(a, b) * b; }// ---- ----string rm[13] = { "IV", "IX", "XL", "XC", "CD", "CM", "I", "V", "X", "L", "C", "D", "M" };int val[13] = { 4, 9, 40, 90, 400, 900, 1, 5, 10, 50, 100, 500, 1000 };int r2i(string s) {int v = 0;s += "@";inc(i, s.size()) {inc(j, 13) {if(s.substr(i, rm[j].size()) == rm[j]) {v += val[j];i += (rm[j].size() - 1);break;}}}return v;}string t4[ 4] = { "", "M", "MM", "MMM", };string t3[10] = { "", "C", "CC", "CCC", "CD", "D", "DC", "DCC", "DCCC", "CM" };string t2[10] = { "", "X", "XX", "XXX", "XL", "L", "LX", "LXX", "LXXX", "XC" };string t1[10] = { "", "I", "II", "III", "IV", "V", "VI", "VII", "VIII", "IX" };int n;string r[100];int main() {cin >> n;inc(i, n) { cin >> r[i]; }int sum = 0;inc(i, n) { sum += r2i(r[i]); }if(sum >= 4000) {cout << "ERROR" << endl;} else {string ans;ans += (t4[sum / 1000]); sum %= 1000;ans += (t3[sum / 100]); sum %= 100;ans += (t2[sum / 10]); sum %= 10;ans += (t1[sum / 1]);cout << ans << endl;}return 0;}