結果

問題 No.518 ローマ数字の和
ユーザー Pachicobue
提出日時 2017-05-28 22:40:01
言語 C++14
(gcc 13.3.0 + boost 1.87.0)
結果
AC  
実行時間 2 ms / 2,000 ms
コード長 4,697 bytes
コンパイル時間 1,479 ms
コンパイル使用メモリ 168,560 KB
実行使用メモリ 5,376 KB
最終ジャッジ日時 2024-09-21 15:40:39
合計ジャッジ時間 2,182 ms
ジャッジサーバーID
(参考情報)
judge3 / judge2
このコードへのチャレンジ
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ファイルパターン 結果
sample AC * 3
other AC * 19
権限があれば一括ダウンロードができます

ソースコード

diff #
プレゼンテーションモードにする

#include <bits/stdc++.h>
#define FOR(i, a, b) for (int i = (a); i < (b); i++)
#define RFOR(i, a, b) for (int i = (b)-1; i >= (a); i--)
#define rep(i, n) for (int i = 0; i < (n); i++)
#define rep1(i, n) for (int i = 1; i <= (n); i++)
#define rrep(i, n) for (int i = (n)-1; i >= 0; i--)
#define pb push_back
#define mp make_pair
#define fst first
#define snd second
#define show(x) cout << #x << " = " << x << endl
#define chmin(x, y) x = min(x, y)
#define chmax(x, y) x = max(x, y)
#define pii pair<int, int>
#define vi vector<int>
using namespace std;
template <class S, class T>
ostream& operator<<(ostream& o, const pair<S, T>& p)
{
return o << "(" << p.first << "," << p.second << ")";
}
template <class T>
ostream& operator<<(ostream& o, const vector<T>& vc)
{
o << "sz = " << vc.size() << endl
<< "[";
for (const T& v : vc)
o << v << ",";
o << "]";
return o;
}
using ll = long long;
constexpr ll MOD = 1000000007;
struct RomanRadix {
int digit;
char roman;
char romanNext;
// Radix(int d, char r, char rn):digit(d),roman(r),romanNext(rn){}
};
const int ROMAN_MAX_VALUE = 3999;
const int ROMAN_MIN_VALUE = 1;
const char RomanChars[] = "IVXLCDMivxlcdm";
class Roman
{
private:
static bool isRomanString(const string& rstr)
{
return rstr.find_first_not_of(RomanChars) == string::npos;
}
static int rtoi_aux(const char ch)
{
static const char romans[] = "IVXLCDM";
static const int digit[] = {1, 5, 10, 50, 100, 500, 1000};
for (int i = 0; romans[i]; ++i)
if (toupper(ch) == romans[i])
return digit[i];
return -1;
}
static int rtoi(const string& rstr)
{
int v, wk = 0;
for (const char* p = rstr.c_str(); *p; ++p) {
if ((v = rtoi_aux(*p)) < rtoi_aux(*(p + 1)))
wk -= v;
else
wk += v;
}
return wk;
}
int num;
string itor() const;
public:
Roman() : num(0) {}
Roman(const int n);
Roman(const string& r);
int as_int() const { return num; }
string as_str() const { return itor(); }
friend Roman operator+(const Roman& a, const Roman& b)
{
int n = a.num + b.num;
if (n > ROMAN_MAX_VALUE)
throw std::overflow_error("overflow");
return Roman(n);
}
friend Roman operator-(const Roman& a, const Roman& b)
{
int n = a.num - b.num;
if (n < ROMAN_MIN_VALUE)
throw std::underflow_error("underflow");
return Roman(n);
}
};
Roman::Roman(const int n) : num(n)
{
if (num < 1 || 3999 < num)
throw out_of_range("value need 1 - 3999");
};
Roman::Roman(const string& r)
{
if (!isRomanString(r))
throw invalid_argument("invalid character use");
num = rtoi(r);
if (num < 1 || 3999 < num)
throw out_of_range("value need 1 - 3999");
};
string Roman::itor() const
{
static RomanRadix table[] = {
{1000, 'M', '?'},
{100, 'C', 'D'},
{10, 'X', 'L'},
{1, 'I', 'V'}};
const int tableSize = sizeof(table) / sizeof(RomanRadix);
char buff[16]; //max size: 15
char* p = buff;
for (int i = 0, wk = num; i < tableSize; ++i) {
int n = wk / table[i].digit;
if (1 <= n && n <= 3) {
for (int j = 0; j < n; ++j)
*p++ = table[i].roman;
} else if (n == 4) {
*p++ = table[i].roman;
*p++ = table[i].romanNext;
} else if (n == 5) {
*p++ = table[i].romanNext;
} else if (6 <= n && n <= 8) {
*p++ = table[i].romanNext;
for (int j = 0; j < n - 5; ++j)
*p++ = table[i].roman;
} else if (n == 9) {
*p++ = table[i].roman;
*p++ = table[i - 1].roman;
}
wk -= n * table[i].digit;
}
*p = '\0';
return string(buff);
};
ostream& operator<<(ostream& os, const Roman& r)
{
return os << r.as_str();
}
istream& operator>>(istream& is, Roman& r)
{
string rstr;
is >> rstr;
try {
r = Roman(rstr);
} catch (invalid_argument& e) {
cerr << e.what() << endl;
is.clear(ios_base::failbit);
}
return is;
}
std::ostream& operator<<(std::ostream& os, const Roman& r);
std::istream& operator>>(std::istream& is, Roman& r);
int main()
{
int N;
cin >> N;
int sum = 0;
rep(i, N)
{
string str;
cin >> str;
Roman r(str);
sum += r.as_int();
}
if (sum >= 4000) {
cout << "ERROR" << endl;
return 0;
}
Roman r(sum);
cout << r.as_str() << endl;
return 0;
}
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