結果

問題 No.519 アイドルユニット
ユーザー tails
提出日時 2017-05-28 22:43:42
言語 C
(gcc 13.3.0)
結果
AC  
実行時間 642 ms / 1,000 ms
コード長 512 bytes
コンパイル時間 218 ms
コンパイル使用メモリ 30,592 KB
実行使用メモリ 67,328 KB
最終ジャッジ日時 2024-10-03 03:50:06
合計ジャッジ時間 6,178 ms
ジャッジサーバーID
(参考情報)
judge1 / judge5
このコードへのチャレンジ
(要ログイン)
ファイルパターン 結果
other AC * 34
権限があれば一括ダウンロードができます
コンパイルメッセージ
main.c:1:1: warning: data definition has no type or storage class
    1 | f[24][24];
      | ^
main.c:1:1: warning: type defaults to 'int' in declaration of 'f' [-Wimplicit-int]
main.c:2:1: warning: data definition has no type or storage class
    2 | g[1<<24];
      | ^
main.c:2:1: warning: type defaults to 'int' in declaration of 'g' [-Wimplicit-int]
main.c:4:1: warning: return type defaults to 'int' [-Wimplicit-int]
    4 | main(){
      | ^~~~
main.c: In function 'main':
main.c:6:9: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
    6 |         scanf("%d",&n);
      |         ^~~~~
main.c:1:1: note: include '<stdio.h>' or provide a declaration of 'scanf'
  +++ |+#include <stdio.h>
    1 | f[24][24];
main.c:6:9: warning: incompatible implicit declaration of built-in function 'scanf' [-Wbuiltin-declaration-mismatch]
    6 |         scanf("%d",&n);
      |         ^~~~~
main.c:6:9: note: include '<stdio.h>' or provide a declaration of 'scanf'
main.c:35:9: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
   35 |         printf("%d",g[(1<<n)-1]);
      |         ^~~~~~
main.c:35:9: note: include '<stdio.h>' or provide a declaration of 'printf'
main.c:35:9: warning: incompatible implicit declaration of built-in function 'printf' [-Wbuiltin-declaration-mismatch]
main.c:35:9: note: include '<stdio.h>' or provide a declaration of 'printf'

ソースコード

diff #
プレゼンテーションモードにする

f[24][24];
g[1<<24];
main(){
int n;
scanf("%d",&n);
for(int y=0;y<n;++y){
for(int x=0;x<n;++x){
scanf("%d",&f[y][x]);
}
}
for(int j=0;j<n;++j){
for(int i=0;i<n;++i){
if(j-i){
g[1<<j|1<<i]=f[j][i];
}
}
}
for(int k=1;k<1<<n;++k){
if(!__builtin_parity(k)){
int b=0;
int j=0;
while(!(k&1<<j))++j;
for(int i=j+1;i<n;++i){
if(k&1<<i){
int d=g[k^1<<j^1<<i]+f[j][i];
if(b<d){
b=d;
}
}
}
g[k]=b;
}
}
printf("%d",g[(1<<n)-1]);
return 0;
}
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