結果
問題 | No.518 ローマ数字の和 |
ユーザー |
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提出日時 | 2017-05-28 22:44:23 |
言語 | Python3 (3.13.1 + numpy 2.2.1 + scipy 1.14.1) |
結果 |
AC
|
実行時間 | 30 ms / 2,000 ms |
コード長 | 1,530 bytes |
コンパイル時間 | 94 ms |
コンパイル使用メモリ | 12,800 KB |
実行使用メモリ | 10,880 KB |
最終ジャッジ日時 | 2024-09-21 15:41:05 |
合計ジャッジ時間 | 1,356 ms |
ジャッジサーバーID (参考情報) |
judge4 / judge3 |
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ファイルパターン | 結果 |
---|---|
sample | AC * 3 |
other | AC * 19 |
ソースコード
Rs = {"I": 1, "V": 5, "X":10, "L": 50, "C": 100, "D": 500, "M": 1000}def RtoInt(Ri): #Ri: strkey = list(Ri)value = [Rs[i] for i in key]for k in range(len(value) - 1):if value[k] < value[k + 1]:value[k] = -1 * value[k]return sum(value)def InttoR(n):strn = str(n)res = ""for i in range(len(strn)):numi = int(strn[- i - 1])if numi == 4:if i == 0:res = "IV" + reselif i == 1:res = "XL" + reselif i == 2:res = "CD" + reselif numi == 9:if i == 0:res = "IX" + reselif i == 1:res = "XC" + reselif i == 2:res = "CM" + reselif numi > 4:if i == 0:res = "V" + "I" * (numi-5) + reselif i == 1:res = "L" + "X" * (numi-5) + reselif i == 2:res = "D" + "C" * (numi-5) + reselif numi < 4:if i == 0:res = "I" * numi + reselif i == 1:res = "X" * numi + reselif i == 2:res = "C" * numi + reselif i == 3:res = "M" * numi + resreturn resN = int(input())R = list(input().split(" "))#N = 5#R = list("IV XXI CCCXL III MMCMVI".split())Rint = list(map(RtoInt, R))sumR = sum(Rint)if sumR > 3999:print("ERROR")else:print(InttoR(sumR))