結果

問題 No.523 LED
ユーザー mai
提出日時 2017-06-02 22:44:37
言語 C++17
(gcc 13.3.0 + boost 1.87.0)
結果
AC  
実行時間 176 ms / 2,000 ms
コード長 3,351 bytes
コンパイル時間 3,109 ms
コンパイル使用メモリ 213,200 KB
最終ジャッジ日時 2025-01-05 00:33:37
ジャッジサーバーID
（参考情報） 		judge1 / judge1
このコードへのチャレンジ
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ファイルパターン 結果
other AC * 25
権限があれば一括ダウンロードができます
コンパイルメッセージ
main.cpp: In function ‘void {anonymous}::toc()’:
main.cpp:26:45: warning: format ‘%lld’ expects argument of type ‘long long int’, but argument 3 has type ‘std::chrono::duration<long int, std::ratio<1, 1000> >::rep’ {aka ‘long int’} [-Wformat=]
   26 |     void toc() { fprintf(stderr, "TIME : %lldms\n", MILLISEC(TIME - ttt)); }
      |                                          ~~~^
      |                                             |
      |                                             long long int
      |                                          %ld
main.cpp: In member function ‘{anonymous}::MaiScanner& {anonymous}::MaiScanner::operator>>(std::string&)’:
main.cpp:67:9: warning: no return statement in function returning non-void [-Wreturn-type]
   67 |         }
      |         ^

ソースコード

diff # 

#pragma GCC optimize ("O3")
#pragma GCC target ("avx")
#include "bits/stdc++.h" // define macro "/D__MAI"

using namespace std;
typedef long long int ll;

#define debugv(v) printf("L%d %s => ",__LINE__,#v);for(auto e:v){cout<<e<<" ";}cout<<endl;
#define debugm(m) printf("L%d %s is..\n",__LINE__,#m);for(auto v:m){for(auto e:v){cout<<e<<" ";}cout<<endl;}
#define debuga(m,w) printf("L%d %s is => ",__LINE__,#m);for(int x=0;x<(w);x++){cout<<(m)[x]<<" ";}cout<<endl;
#define debugaa(m,w,h) printf("L%d %s is..\n",__LINE__,#m);for(int y=0;y<(h);y++){for(int x=0;x<(w);x++){cout<<(m)[x][y]<<" ";}cout<<endl;}
#define debugaar(m,w,h) printf("L%d %s is..\n",__LINE__,#m);for(int y=0;y<(h);y++){for(int x=0;x<(w);x++){cout<<(m)[y][x]<<" ";}cout<<endl;}
#define ALL(v) (v).begin(),(v).end()
#define repeat(l) for(auto cnt=0;cnt<(l);++cnt)
#define iterate(b,e) for(auto cnt=(b);cnt!=(e);++cnt)
#define MD 1000000007ll
#define PI 3.1415926535897932384626433832795
template<typename T1, typename T2>
ostream& operator <<(ostream &o, const pair<T1, T2> p) { o << "(" << p.first << ":" << p.second << ")"; return o; }

#define TIME chrono::system_clock::now()
#define MILLISEC(t) (chrono::duration_cast<chrono::milliseconds>(t).count())
namespace {
    std::chrono::system_clock::time_point ttt;
    void tic() { ttt = TIME; }
    void toc() { fprintf(stderr, "TIME : %lldms\n", MILLISEC(TIME - ttt)); }
    std::chrono::system_clock::time_point tle = TIME;
#ifdef __MAI
    void safe_tle(int msec) { assert(MILLISEC(TIME - tle) < msec); }
#else
#define safe_tle(k) ;
#endif
}

//#ifdef __MAI //_getchar_nolock
#define getchar_unlocked getchar
//#endif
namespace {
#define isvisiablechar(c) (0x21<=(c)&&(c)<=0x7E)
    class MaiScanner {
    public:
        template<typename T>
        void input_integer(T& var) {
            var = 0;
            T sign = 1;
            int cc = getchar_unlocked();
            for (; cc<'0' || '9'<cc; cc = getchar_unlocked())
                if (cc == '-') sign = -1;
            for (; '0' <= cc&&cc <= '9'; cc = getchar_unlocked())
                var = (var << 3) + (var << 1) + cc - '0';
            var = var*sign;
        }
        inline int c() { return getchar_unlocked(); }
        inline MaiScanner& operator>>(int& var) {
            input_integer<int>(var);
            return *this;
        }
        inline MaiScanner& operator>>(long long& var) {
            input_integer<long long>(var);
            return *this;
        }
        inline MaiScanner& operator>>(string& var) {
            int cc = getchar_unlocked();
            for (; !isvisiablechar(cc); cc = getchar_unlocked());
            for (; isvisiablechar(cc); cc = getchar_unlocked())
                var.push_back(cc);
        }
    };
}
MaiScanner scanner;


template<typename T>
T factm(T n, T mod = 1000000007ll) {
    T p = 1;
    for (; 1<n; p = (p*n--) % mod);
    return p;
}


// MEMO : 逆元...powm(n,E107-2,E107)
template<typename T>
T powm(T x, T p, T mod = 1000000007ll) {
    T y = 1;
    x = x%mod;
    while (0<p) {
        if (p % 2 == 1) {
            y = (y*x) % mod;
        }
        x = (x*x) % mod;
        p /= 2;
    }
    return y;
}


int main() {
    ll n;
    scanner >> n;

    ll t = factm(n*2);

    ll g = powm(2ll, MD - 2, MD);
    repeat(n) {
        t = (t*g)%MD;
    }
    cout << t << endl;

    return 0;
}
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