結果
問題 |
No.460 裏表ちわーわ
|
ユーザー |
![]() |
提出日時 | 2017-06-04 02:27:56 |
言語 | Python3 (3.13.1 + numpy 2.2.1 + scipy 1.14.1) |
結果 |
TLE
|
実行時間 | - |
コード長 | 2,325 bytes |
コンパイル時間 | 114 ms |
コンパイル使用メモリ | 12,928 KB |
実行使用メモリ | 35,328 KB |
最終ジャッジ日時 | 2024-09-22 04:40:52 |
合計ジャッジ時間 | 3,813 ms |
ジャッジサーバーID (参考情報) |
judge1 / judge5 |
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ファイルパターン | 結果 |
---|---|
other | AC * 1 TLE * 1 -- * 26 |
ソースコード
# coding: utf-8 import array, bisect, collections, copy, heapq, itertools, math, random, re, string, sys, time sys.setrecursionlimit(10 ** 7) INF = 10 ** 20 MOD = 10 ** 9 + 7 def II(): return int(input()) def ILI(): return list(map(int, input().split())) def IAI(LINE): return [ILI() for __ in range(LINE)] def IDI(): return {key: value for key, value in ILI()} def read(): M, N = ILI() # a[row][col] a = IAI(N) return (M, N, a) def change_board(board, x, y, M, N): if N == 1: l_x = [0] elif N == 2: l_x = [0, 1] else: if x == 0: l_x = [0, 1] elif x == N - 1: l_x = [N - 2, N - 1] else: l_x = [x - 1, x, x + 1] if M == 1: l_y = [0] elif M == 2: l_y = [0, 1] else: if y == 0: l_y = [0, 1] elif y == M - 1: l_y = [M - 2, M - 1] else: l_y = [y - 1, y, y + 1] ret_board = copy.deepcopy(board) for in_x in l_x: for in_y in l_y: ret_board[in_y][in_x] = (ret_board[in_y][in_x] + 1) % 2 return ret_board def bool_board(board): for row in board: if sum(row) != 0: return False return True def board_to_tuple(board): l_ret = [] for row in board: l_ret += row t_ret = tuple(l_ret) return t_ret def solve(M, N, a): set_check = set() if bool_board(a): return 0 else: ans = 0 stack = [a] set_check.add(board_to_tuple(a)) while len(stack) != 0: next_stack = [] ans += 1 for b in stack: for x in range(N): for y in range(M): ret_board = change_board(b, x, y, M, N) if bool_board(ret_board): return ans else: tup_board = board_to_tuple(ret_board) if tup_board in set_check: continue else: set_check.add(tup_board) next_stack.append(ret_board) stack = copy.deepcopy(next_stack) return "impossible" def main(): params = read() print(solve(*params)) if __name__ == "__main__": main()