結果
問題 | No.15 カタログショッピング |
ユーザー | Pachicobue |
提出日時 | 2017-06-04 05:48:53 |
言語 | C++14 (gcc 12.3.0 + boost 1.83.0) |
結果 |
AC
|
実行時間 | 13 ms / 5,000 ms |
コード長 | 2,709 bytes |
コンパイル時間 | 1,977 ms |
コンパイル使用メモリ | 183,744 KB |
実行使用メモリ | 5,376 KB |
最終ジャッジ日時 | 2024-09-22 04:52:35 |
合計ジャッジ時間 | 2,601 ms |
ジャッジサーバーID (参考情報) |
judge2 / judge3 |
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テストケース
テストケース表示入力 | 結果 | 実行時間 実行使用メモリ |
---|---|---|
testcase_00 | AC | 2 ms
5,248 KB |
testcase_01 | AC | 2 ms
5,376 KB |
testcase_02 | AC | 2 ms
5,376 KB |
testcase_03 | AC | 2 ms
5,376 KB |
testcase_04 | AC | 2 ms
5,376 KB |
testcase_05 | AC | 10 ms
5,376 KB |
testcase_06 | AC | 11 ms
5,376 KB |
testcase_07 | AC | 13 ms
5,376 KB |
testcase_08 | AC | 13 ms
5,376 KB |
testcase_09 | AC | 12 ms
5,376 KB |
ソースコード
#include <bits/stdc++.h> #define FOR(i, a, b) for (ll i = (a); i < (b); i++) #define RFOR(i, a, b) for (ll i = (b)-1; i >= (a); i--) #define rep(i, n) for (ll i = 0; i < (n); i++) #define rep1(i, n) for (ll i = 1; i <= (n); i++) #define rrep(i, n) for (ll i = (n)-1; i >= 0; i--) #define pb push_back #define mp make_pair #define fst first #define snd second #define show(x) cout << #x << " = " << x << endl #define chmin(x, y) x = min(x, y) #define chmax(x, y) x = max(x, y) #define pii pair<int, int> #define vi vector<int> using namespace std; template <class S, class T> ostream& operator<<(ostream& o, const pair<S, T>& p) { return o << "(" << p.first << "," << p.second << ")"; } template <class T> ostream& operator<<(ostream& o, const vector<T>& vc) { o << "sz = " << vc.size() << endl << "["; for (const T& v : vc) o << v << ","; o << "]"; return o; } using ll = long long; constexpr ll MOD = 1000000007; void decode(ll c, ll d) { stack<ll> st; for (ll i = 0; i < d; i++) { if ((c >> i) % 2) { st.push(d - i); } } bool first = true; while (not st.empty()) { if (not first) { cout << " "; } first = false; cout << st.top(); st.pop(); } cout << endl; } int main() { ll n; ll s; cin >> n >> s; vector<ll> p(n); rep(i, n) { cin >> p[n - 1 - i]; } const ll former = n / 2; const ll latter = n - former; const ll formernum = (1LL << former); const ll latternum = (1LL << latter); vector<ll> formersum(formernum); formersum[0] = 0; for (ll c = 1; c < formernum; c++) { for (ll b = 0; b < former; b++) { if ((c >> b) % 2) { formersum[c] = formersum[c - (1LL << b)] + p[b]; break; } } } vector<pair<ll, ll>> lattersum(latternum); lattersum[0] = mp(0LL, 0LL); for (ll c = 1; c < latternum; c++) { for (ll b = 0; b < latter; b++) { if ((c >> b) % 2) { lattersum[c] = mp(lattersum[c - (1LL << b)].first + p[b + former], c << former); break; } } } sort(lattersum.begin(), lattersum.end()); vector<ll> choice; for (ll fc = 0; fc < formernum; fc++) { const ll rest = s - formersum[fc]; auto ite = lower_bound(lattersum.begin(), lattersum.end(), mp(rest, -1LL)); while (ite->first == rest) { choice.pb(ite->second + fc); ite++; } } sort(choice.begin(), choice.end(), greater<ll>()); for (const ll c : choice) { decode(c, n); } return 0; }