結果
| 問題 | No.15 カタログショッピング |
| コンテスト | |
| ユーザー |
|
| 提出日時 | 2017-06-04 05:48:53 |
| 言語 | C++14 (gcc 13.3.0 + boost 1.87.0) |
| 結果 |
AC
|
| 実行時間 | 13 ms / 5,000 ms |
| コード長 | 2,709 bytes |
| コンパイル時間 | 1,977 ms |
| コンパイル使用メモリ | 183,744 KB |
| 実行使用メモリ | 5,376 KB |
| 最終ジャッジ日時 | 2024-09-22 04:52:35 |
| 合計ジャッジ時間 | 2,601 ms |
|
ジャッジサーバーID (参考情報) |
judge2 / judge3 |
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| ファイルパターン | 結果 |
|---|---|
| other | AC * 10 |
ソースコード
#include <bits/stdc++.h>
#define FOR(i, a, b) for (ll i = (a); i < (b); i++)
#define RFOR(i, a, b) for (ll i = (b)-1; i >= (a); i--)
#define rep(i, n) for (ll i = 0; i < (n); i++)
#define rep1(i, n) for (ll i = 1; i <= (n); i++)
#define rrep(i, n) for (ll i = (n)-1; i >= 0; i--)
#define pb push_back
#define mp make_pair
#define fst first
#define snd second
#define show(x) cout << #x << " = " << x << endl
#define chmin(x, y) x = min(x, y)
#define chmax(x, y) x = max(x, y)
#define pii pair<int, int>
#define vi vector<int>
using namespace std;
template <class S, class T>
ostream& operator<<(ostream& o, const pair<S, T>& p)
{
return o << "(" << p.first << "," << p.second << ")";
}
template <class T>
ostream& operator<<(ostream& o, const vector<T>& vc)
{
o << "sz = " << vc.size() << endl
<< "[";
for (const T& v : vc)
o << v << ",";
o << "]";
return o;
}
using ll = long long;
constexpr ll MOD = 1000000007;
void decode(ll c, ll d)
{
stack<ll> st;
for (ll i = 0; i < d; i++) {
if ((c >> i) % 2) {
st.push(d - i);
}
}
bool first = true;
while (not st.empty()) {
if (not first) {
cout << " ";
}
first = false;
cout << st.top();
st.pop();
}
cout << endl;
}
int main()
{
ll n;
ll s;
cin >> n >> s;
vector<ll> p(n);
rep(i, n)
{
cin >> p[n - 1 - i];
}
const ll former = n / 2;
const ll latter = n - former;
const ll formernum = (1LL << former);
const ll latternum = (1LL << latter);
vector<ll> formersum(formernum);
formersum[0] = 0;
for (ll c = 1; c < formernum; c++) {
for (ll b = 0; b < former; b++) {
if ((c >> b) % 2) {
formersum[c] = formersum[c - (1LL << b)] + p[b];
break;
}
}
}
vector<pair<ll, ll>> lattersum(latternum);
lattersum[0] = mp(0LL, 0LL);
for (ll c = 1; c < latternum; c++) {
for (ll b = 0; b < latter; b++) {
if ((c >> b) % 2) {
lattersum[c] = mp(lattersum[c - (1LL << b)].first + p[b + former], c << former);
break;
}
}
}
sort(lattersum.begin(), lattersum.end());
vector<ll> choice;
for (ll fc = 0; fc < formernum; fc++) {
const ll rest = s - formersum[fc];
auto ite = lower_bound(lattersum.begin(), lattersum.end(), mp(rest, -1LL));
while (ite->first == rest) {
choice.pb(ite->second + fc);
ite++;
}
}
sort(choice.begin(), choice.end(), greater<ll>());
for (const ll c : choice) {
decode(c, n);
}
return 0;
}