結果
問題 | No.176 2種類の切手 |
ユーザー |
|
提出日時 | 2015-04-03 21:17:58 |
言語 | C++11(廃止可能性あり) (gcc 13.3.0) |
結果 |
AC
|
実行時間 | 503 ms / 1,000 ms |
コード長 | 1,945 bytes |
コンパイル時間 | 1,640 ms |
コンパイル使用メモリ | 156,360 KB |
実行使用メモリ | 5,248 KB |
最終ジャッジ日時 | 2024-10-08 03:04:22 |
合計ジャッジ時間 | 3,148 ms |
ジャッジサーバーID (参考情報) |
judge2 / judge3 |
(要ログイン)
ファイルパターン | 結果 |
---|---|
sample | AC * 3 |
other | AC * 29 |
ソースコード
#define _crt_secure_no_warnings#ifndef _GLIBCXX_NO_ASSERT#include <cassert>#endif#include <cctype>#include <cerrno>#include <cfloat>#include <ciso646>#include <climits>#include <clocale>#include <cmath>#include <csetjmp>#include <csignal>#include <cstdarg>#include <cstddef>#include <cstdio>#include <cstdlib>#include <cstring>#include <ctime>#ifdef __GXX_EXPERIMENTAL_CXX0X__#include <ccomplex>#include <cfenv>#include <cinttypes>#include <cstdbool>#include <cstdint>#include <ctgmath>#include <cwchar>#include <cwctype>#endif#include <algorithm>#include <bitset>#include <complex>#include <deque>#include <exception>#include <fstream>#include <functional>#include <iomanip>#include <ios>#include <iosfwd>#include <iostream>#include <istream>#include <iterator>#include <limits>#include <list>#include <locale>#include <map>#include <memory>#include <new>#include <numeric>#include <ostream>#include <queue>#include <set>#include <sstream>#include <stack>#include <stdexcept>#include <streambuf>#include <string>#include <typeinfo>#include <utility>#include <valarray>#include <vector>#ifdef __GXX_EXPERIMENTAL_CXX0X__#include <array>#include <atomic>#include <chrono>#include <condition_variable>#include <forward_list>#include <future>#include <initializer_list>#include <mutex>#include <random>#include <ratio>#include <regex>#include <system_error>#include <thread>#include <tuple>#include <typeindex>#include <type_traits>#include <unordered_map>#include <unordered_set>#endifusing namespace std;int main(){int a, b, c;cin >> a >> b >> c;int d, e, f;if (a > b){swap(a, b);}d = c / b + 1;int ans = INT_MAX;e = 0;while (d != -1){f = d*b + e*a;if (f >= c){ans = min(ans,f);}if (d*b + e*a > c){d--;} else if (f == c){ans = c;break;} else{e++;}}cout << ans << endl;}