結果

問題 No.518 ローマ数字の和
ユーザー nksk38
提出日時 2017-06-21 20:37:03
言語 C++11(廃止可能性あり)
(gcc 13.3.0)
結果
AC  
実行時間 2 ms / 2,000 ms
コード長 2,362 bytes
コンパイル時間 582 ms
コンパイル使用メモリ 80,472 KB
実行使用メモリ 5,248 KB
最終ジャッジ日時 2024-10-02 10:59:49
合計ジャッジ時間 1,289 ms
ジャッジサーバーID
(参考情報)
judge5 / judge4
このコードへのチャレンジ
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ファイルパターン 結果
sample AC * 3
other AC * 19
権限があれば一括ダウンロードができます

ソースコード

diff #
プレゼンテーションモードにする

#include<cstdio>
#include <iostream>
#include<algorithm>
#include<string>
#include<queue>
#include<vector>
#include<functional>
#include<cmath>
#include<map>
#include<stack>
#include<set>
#include<numeric>
using namespace std;
typedef long long ll;
typedef pair<int, int> Pr;
int N;
ll sum;
int main()
{
cin >> N;
for (int i = 0; i < N; i++) {
string s;
cin >> s;
for (int j = 0; j < s.size(); j++) {
if (s[j] == 'I') {
if (j + 1 < s.size()) {
if (s[j + 1] == 'X')sum += 9, j++;
else if (s[j + 1] == 'V')sum += 4, j++;
else sum++;
}
else sum++;
}
else if (s[j] == 'V')sum += 5;
else if (s[j] == 'X' ){
if(j + 1 < s.size()) {
if (s[j + 1] == 'L')sum += 40, j++;
else if (s[j + 1] == 'C')sum += 90, j++;
else sum += 10;
}
else sum += 10;
}
else if (s[j] == 'L')sum += 50;
else if (s[j] == 'C') {
if(j + 1 < s.size()) {
if (s[j + 1] == 'D')sum += 400, j++;
else if (s[j + 1] == 'M')sum += 900, j++;
else sum += 100;
}
else sum += 100;
}
else if (s[j] == 'D')sum += 500;
else if (s[j] == 'M')sum += 1000;
}
}
if (sum > 3999) {
cout << "ERROR" << endl;
}
else {
int m = sum / 1000;
sum -= m * 1000;
for (int i = 0; i < m; i++)
cout << "M";
int c = sum / 100;
if (c <= 3) {
for (int i = 0; i < c; i++)
cout << "C";
sum -= c * 100;
}else{
if (c == 4)cout << "CD", sum -= 400;
else if (c == 5)cout << "D", sum -= 500;
else if (c == 6)cout << "DC", sum -= 600;
else if (c == 7)cout << "DCC", sum -= 700;
else if (c == 8)cout << "DCCC", sum -= 800;
else if (c == 9)cout << "CM", sum -= 900;
}
int x = sum / 10;
if (x <= 3) {
for (int i = 0; i < x; i++)
cout << "X";
sum -= x * 10;
}
else {
if (x == 4)cout << "XL", sum -= 40;
else if (x == 5)cout << "L", sum -= 50;
else if (x == 6)cout << "LX", sum -= 60;
else if (x == 7)cout << "LXX", sum -= 70;
else if (x == 8)cout << "LXXX", sum -= 80;
else if (x == 9)cout << "XC", sum -= 90;
}
if (sum <= 3) {
for (int i = 0; i < sum; i++)
cout << "I";
}else{
if (sum == 4)cout << "IV";
else if (sum == 5)cout << "V";
else if (sum == 6)cout << "VI";
else if (sum == 7)cout << "VII";
else if (sum == 8)cout << "VIII";
else if (sum == 9)cout << "IX";
}
cout << endl;
}
return 0;
}
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