結果
問題 | No.535 自然数の収納方法 |
ユーザー | paruki |
提出日時 | 2017-06-28 15:12:35 |
言語 | C++14 (gcc 12.3.0 + boost 1.83.0) |
結果 |
AC
|
実行時間 | 27 ms / 2,000 ms |
コード長 | 2,915 bytes |
コンパイル時間 | 1,348 ms |
コンパイル使用メモリ | 168,224 KB |
実行使用メモリ | 19,160 KB |
最終ジャッジ日時 | 2024-10-04 14:49:01 |
合計ジャッジ時間 | 2,428 ms |
ジャッジサーバーID (参考情報) |
judge5 / judge3 |
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テストケース
テストケース表示入力 | 結果 | 実行時間 実行使用メモリ |
---|---|---|
testcase_00 | AC | 6 ms
18,920 KB |
testcase_01 | AC | 5 ms
19,092 KB |
testcase_02 | AC | 6 ms
18,988 KB |
testcase_03 | AC | 5 ms
19,008 KB |
testcase_04 | AC | 6 ms
18,996 KB |
testcase_05 | AC | 5 ms
18,888 KB |
testcase_06 | AC | 6 ms
19,072 KB |
testcase_07 | AC | 9 ms
19,064 KB |
testcase_08 | AC | 18 ms
19,060 KB |
testcase_09 | AC | 20 ms
19,024 KB |
testcase_10 | AC | 23 ms
18,940 KB |
testcase_11 | AC | 7 ms
19,148 KB |
testcase_12 | AC | 14 ms
19,116 KB |
testcase_13 | AC | 7 ms
18,976 KB |
testcase_14 | AC | 11 ms
18,832 KB |
testcase_15 | AC | 25 ms
18,972 KB |
testcase_16 | AC | 18 ms
18,988 KB |
testcase_17 | AC | 26 ms
19,160 KB |
testcase_18 | AC | 6 ms
19,036 KB |
testcase_19 | AC | 27 ms
19,136 KB |
testcase_20 | AC | 26 ms
18,912 KB |
testcase_21 | AC | 25 ms
18,960 KB |
testcase_22 | AC | 25 ms
19,124 KB |
ソースコード
#include "bits/stdc++.h" using namespace std; #define FOR(i,j,k) for(int (i)=(j);(i)<(int)(k);++(i)) #define rep(i,j) FOR(i,0,j) #define each(x,y) for(auto &(x):(y)) #define mp make_pair #define MT make_tuple #define all(x) (x).begin(),(x).end() #define debug(x) cout<<#x<<": "<<(x)<<endl #define smax(x,y) (x)=max((x),(y)) #define smin(x,y) (x)=min((x),(y)) #define MEM(x,y) memset((x),(y),sizeof (x)) #define sz(x) (int)(x).size() #define rt return using dbl = double; using ll = long long; using pii = pair<int, int>; using vi = vector<int>; using vll = vector<ll>; template<int MOD> class ModInt { public: ModInt() :value(0) {} ModInt(long long val) :value((int)(val<0 ? MOD + val%MOD : val%MOD)) { } ModInt& operator+=(ModInt that) { value = value + that.value; if (value >= MOD)value -= MOD; return *this; } ModInt& operator-=(ModInt that) { value -= that.value; if (value<0)value += MOD; return *this; } ModInt& operator*=(ModInt that) { value = (int)((long long)value * that.value % MOD); return *this; } ModInt &operator/=(ModInt that) { return *this *= that.inverse(); } ModInt operator+(ModInt that) const { return ModInt(*this) += that; } ModInt operator-(ModInt that) const { return ModInt(*this) -= that; } ModInt operator*(ModInt that) const { return ModInt(*this) *= that; } ModInt operator/(ModInt that) const { return ModInt(*this) /= that; } ModInt pow(long long k) const { if (value == 0)return 0; ModInt n = *this, res = 1; while (k) { if (k & 1)res *= n; n *= n; k >>= 1; } return res; } ModInt inverse() const { long long a = value, b = MOD, u = 1, v = 0; while (b) { long long t = a / b; a -= t * b; swap(a, b); u -= t * v; swap(u, v); } return ModInt(u); } int toi() const { return value; } private: int value; }; typedef ModInt<1000000007> mint; ostream& operator<<(ostream& os, const mint& x) { os << x.toi(); return os; } mint dp[2001][2001]; int N; void calc() { for (int i = 2; i <= N-1; ++i) { int cur = 0; mint sm; for (int j = 1; j <= N; ++j) { while (cur - (i - 1) < j && cur<=N) { sm += dp[i - 1][cur++]; } dp[i][j] += sm; } } } int main(){ ios::sync_with_stdio(false); cin.tie(0); cin >> N; for (int i = 1; i <= N; ++i)for (int j = i; j <= N; ++j) { dp[1][j] += 1; } calc(); mint ans; rep(i, N + 1)ans += dp[N - 1][i]; MEM(dp, 0); for (int j = 1; j <= N; ++j) { dp[1][j] = 1; } calc(); ans -= dp[N - 1][N]; cout << ans << endl; }