結果

問題 No.247 線形計画問題もどき
ユーザー mai
提出日時 2017-07-04 11:00:12
言語 C++17
(gcc 13.3.0 + boost 1.87.0)
結果
AC  
実行時間 32 ms / 2,000 ms
コード長 3,377 bytes
コンパイル時間 3,472 ms
コンパイル使用メモリ 216,040 KB
最終ジャッジ日時 2025-01-05 01:06:04
ジャッジサーバーID
(参考情報)
judge5 / judge3
このコードへのチャレンジ
(要ログイン)
ファイルパターン 結果
sample AC * 5
other AC * 23
権限があれば一括ダウンロードができます
コンパイルメッセージ
main.cpp: In function ‘void {anonymous}::toc()’:
main.cpp:26:45: warning: format ‘%lld’ expects argument of type ‘long long int’, but argument 3 has type ‘std::chrono::duration<long int, std::ratio<1, 1000> >::rep’ {aka ‘long int’} [-Wformat=]
   26 |     void toc() { fprintf(stderr, "TIME : %lldms\n", MILLISEC(TIME - ttt)); }
      |                                          ~~~^
      |                                             |
      |                                             long long int
      |                                          %ld
main.cpp: In member function ‘{anonymous}::MaiScanner& {anonymous}::MaiScanner::operator>>(std::string&)’:
main.cpp:72:9: warning: no return statement in function returning non-void [-Wreturn-type]
   72 |         }
      |         ^

ソースコード

diff #
プレゼンテーションモードにする

#pragma GCC optimize ("O3")
#pragma GCC target ("avx")
#include "bits/stdc++.h" // define macro "/D__MAI"
using namespace std;
typedef long long int ll;
#define debugv(v) printf("L%d %s => ",__LINE__,#v);for(auto e:v){cout<<e<<" ";}cout<<endl;
#define debugm(m) printf("L%d %s is..\n",__LINE__,#m);for(auto v:m){for(auto e:v){cout<<e<<" ";}cout<<endl;}
#define debuga(m,w) printf("L%d %s is => ",__LINE__,#m);for(int x=0;x<(w);x++){cout<<(m)[x]<<" ";}cout<<endl;
#define debugaa(m,w,h) printf("L%d %s is..\n",__LINE__,#m);for(int y=0;y<(h);y++){for(int x=0;x<(w);x++){cout<<(m)[x][y]<<" ";}cout<<endl;}
#define debugaar(m,w,h) printf("L%d %s is..\n",__LINE__,#m);for(int y=0;y<(h);y++){for(int x=0;x<(w);x++){cout<<(m)[y][x]<<" ";}cout<<endl;}
#define ALL(v) (v).begin(),(v).end()
#define repeat(l) for(auto cnt=0;cnt<(l);++cnt)
#define iterate(b,e) for(auto cnt=(b);cnt!=(e);++cnt)
#define MD 1000000007ll
#define PI 3.1415926535897932384626433832795
template<typename T1, typename T2>
ostream& operator <<(ostream &o, const pair<T1, T2> p) { o << "(" << p.first << ":" << p.second << ")"; return o; }
#define TIME chrono::system_clock::now()
#define MILLISEC(t) (chrono::duration_cast<chrono::milliseconds>(t).count())
namespace {
std::chrono::system_clock::time_point ttt;
void tic() { ttt = TIME; }
void toc() { fprintf(stderr, "TIME : %lldms\n", MILLISEC(TIME - ttt)); }
std::chrono::system_clock::time_point tle = TIME;
#ifdef __MAI
void safe_tle(int msec) { assert(MILLISEC(TIME - tle) < msec); }
#else
#define safe_tle(k) ;
#endif
}
#ifdef __MAI
#define getchar_unlocked getchar
#define putchar_unlocked putchar
#endif
#ifdef __VSCC
#define getchar_unlocked _getchar_nolock
#define putchar_unlocked _putchar_nolock
#endif
namespace {
#define isvisiablechar(c) (0x21<=(c)&&(c)<=0x7E)
class MaiScanner {
public:
template<typename T>
void input_integer(T& var) {
var = 0;
T sign = 1;
int cc = getchar_unlocked();
for (; cc<'0' || '9'<cc; cc = getchar_unlocked())
if (cc == '-') sign = -1;
for (; '0' <= cc&&cc <= '9'; cc = getchar_unlocked())
var = (var << 3) + (var << 1) + cc - '0';
var = var*sign;
}
inline int c() { return getchar_unlocked(); }
inline MaiScanner& operator>>(int& var) {
input_integer<int>(var);
return *this;
}
inline MaiScanner& operator>>(long long& var) {
input_integer<long long>(var);
return *this;
}
inline MaiScanner& operator>>(string& var) {
int cc = getchar_unlocked();
for (; !isvisiablechar(cc); cc = getchar_unlocked());
for (; isvisiablechar(cc); cc = getchar_unlocked())
var.push_back(cc);
}
};
}
MaiScanner scanner;
int cap, n;
int aa[110];
int dp[100010];
constexpr int inf = 1e9;
int main() {
scanner >> cap >> n;
repeat(n) {
scanner >> aa[cnt];
}
fill(dp, dp + cap + 1, inf);
// first
for (int i = 0; i < n; ++i) {
dp[aa[i]] = 1;
}
for (int i = 0; i < n; ++i) {
for (int w = 1; w <= cap - aa[i]; ++w) {
dp[w + aa[i]] = min(dp[w] + 1, dp[w + aa[i]]);
}
}
cout << (dp[cap]!= inf ? dp[cap] : -1) << endl;
return 0;
}
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