結果

問題 No.33 アメーバがたくさん
ユーザー maimai
提出日時 2017-07-09 14:08:53
言語 C++17(gcc12)
(gcc 12.3.0 + boost 1.87.0)
結果
AC  
実行時間 21 ms / 5,000 ms
コード長 4,115 bytes
コンパイル時間 12,282 ms
コンパイル使用メモリ 281,984 KB
最終ジャッジ日時 2025-01-05 01:23:42
ジャッジサーバーID
（参考情報） 		judge3 / judge5
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ファイルパターン 結果
other AC * 11
権限があれば一括ダウンロードができます
コンパイルメッセージ
main.cpp: In member function '{anonymous}::MaiScanner& {anonymous}::MaiScanner::operator>>(std::string&)':
main.cpp:62:9: warning: no return statement in function returning non-void [-Wreturn-type]
   62 |         }
      |         ^

ソースコード

diff # 

#pragma GCC optimize ("O3")
#pragma GCC target ("avx")
#include "bits/stdc++.h" // define macro "/D__MAI"

using namespace std;
typedef long long int ll;

#define debugv(v) {printf("L%d %s => ",__LINE__,#v);for(auto e:v){cout<<e<<" ";}cout<<endl;}
#define debugm(m) {printf("L%d %s is..\n",__LINE__,#m);for(auto v:m){for(auto e:v){cout<<e<<" ";}cout<<endl;}}
#define debuga(m,w) {printf("L%d %s is => ",__LINE__,#m);for(int x=0;x<(w);x++){cout<<(m)[x]<<" ";}cout<<endl;}
#define debugaa(m,w,h) {printf("L%d %s is..\n",__LINE__,#m);for(int y=0;y<(h);y++){for(int x=0;x<(w);x++){cout<<(m)[x][y]<<" ";}cout<<endl;}}
#define debugaar(m,w,h) {printf("L%d %s is..\n",__LINE__,#m);for(int y=0;y<(h);y++){for(int x=0;x<(w);x++){cout<<(m)[y][x]<<" ";}cout<<endl;}}
#define ALL(v) (v).begin(),(v).end()
#define repeat(l) for(auto cnt=0;cnt<(l);++cnt)
#define iterate(b,e) for(auto cnt=(b);cnt!=(e);++cnt)
#define MD 1000000007ll
#define PI 3.1415926535897932384626433832795
template<typename T1, typename T2>
ostream& operator <<(ostream &o, const pair<T1, T2> p) { o << "(" << p.first << ":" << p.second << ")"; return o; }

mt19937 mt(8901016);
inline int rand_int(int l, int h) {
    return uniform_int_distribution<>(l, h)(mt);
}

#ifdef __MAI
#define getchar_unlocked getchar
#define putchar_unlocked putchar
#endif
#ifdef __VSCC
#define getchar_unlocked _getchar_nolock
#define putchar_unlocked _putchar_nolock
#endif
namespace {
#define isvisiablechar(c) (0x21<=(c)&&(c)<=0x7E)
    class MaiScanner {
    public:
        template<typename T> void input_integer(T& var) {
            var = 0;
            T sign = 1;
            int cc = getchar_unlocked();
            for (; cc<'0' || '9'<cc; cc = getchar_unlocked())
                if (cc == '-') sign = -1;
            for (; '0' <= cc&&cc <= '9'; cc = getchar_unlocked())
                var = (var << 3) + (var << 1) + cc - '0';
            var = var*sign;
        }
        inline int c() { return getchar_unlocked(); }
        inline MaiScanner& operator>>(int& var) {
            input_integer<int>(var);
            return *this;
        }
        inline MaiScanner& operator>>(long long& var) {
            input_integer<long long>(var);
            return *this;
        }
        inline MaiScanner& operator>>(string& var) {
            int cc = getchar_unlocked();
            for (; !isvisiablechar(cc); cc = getchar_unlocked());
            for (; isvisiablechar(cc); cc = getchar_unlocked())
                var.push_back(cc);
        }
        template<typename IT> void in(IT begin, IT end) {
            for (auto it = begin; it != end; ++it) *this >> *it;
        }
    };
}
MaiScanner scanner;





ll n,step,tim;
ll aa[111];

int main() {
    scanner >> n >> step >> tim;

    scanner.in(aa, aa + n);

    sort(aa, aa + n);

    map<ll, vector<int>> ofli;

    for (int i = 0; i < n; ++i) {
        ofli[(aa[i] % step + step) % step].push_back(i);
    }

    ll counter = 0;
    for (auto& p : ofli) {
        if (p.second.size() == 1) {
            counter += tim * 2 + 1;
        }
        else {
            ll offset = p.first;

            bool start = false;
            ll left = 0;
            ll right = 0;
            for (auto idx : p.second) {
                if (!start) {
                    ll ce = (aa[idx] - offset) / step;
                    left = ce - tim;
                    right = ce + tim;

                    start = true;
                }
                else {
                    ll ce = (aa[idx] - offset) / step;
                    ll l = ce - tim;
                    ll r = ce + tim;

                    if (right < l) {
                        counter += tim * 2 + 1;
                        left = l;
                        right = r;
                    }
                    else {
                        ll c = right - l + 1;
                        counter += tim * 2 + 1 - c;
                        left = l;
                        right = r;
                    }
                }
            }
            counter += tim * 2 + 1;
        }
    }


    cout << counter << endl;

    return 0;
}
0