結果
問題 | No.545 ママの大事な二人の子供 |
ユーザー |
|
提出日時 | 2017-07-14 22:45:28 |
言語 | C++14 (gcc 13.3.0 + boost 1.87.0) |
結果 |
AC
|
実行時間 | 23 ms / 2,000 ms |
コード長 | 2,356 bytes |
コンパイル時間 | 1,960 ms |
コンパイル使用メモリ | 174,088 KB |
実行使用メモリ | 5,248 KB |
最終ジャッジ日時 | 2024-10-07 23:42:16 |
合計ジャッジ時間 | 2,581 ms |
ジャッジサーバーID (参考情報) |
judge2 / judge4 |
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ファイルパターン | 結果 |
---|---|
other | AC * 32 |
ソースコード
#include <bits/stdc++.h> #define show(x) cout << #x << " = " << x << endl using namespace std; using ll = long long; using pii = pair<int, int>; using vi = vector<int>; template <typename T> ostream& operator<<(ostream& os, const vector<T>& v) { os << "sz=" << v.size() << "\n["; for (const auto& p : v) { os << p << ","; } os << "]\n"; return os; } template <typename S, typename T> ostream& operator<<(ostream& os, const pair<S, T>& p) { os << "(" << p.first << "," << p.second << ")"; return os; } constexpr ll MOD = 1e9 + 7; template <typename T> constexpr T INF = numeric_limits<T>::max() / 100; int main() { int n; cin >> n; vector<ll> A(n); vector<ll> B(n); for (ll i = 0; i < n; i++) { cin >> A[i] >> B[i]; } const int former_half = n / 2; const int latter_half = n - former_half; vector<ll> former; vector<ll> latter; const ll former_maximum = 1 << former_half; const ll latter_maximum = 1 << latter_half; for (ll i = 0; i < former_maximum; i++) { ll num = i; ll a = 0; ll b = 0; for (int j = 0; j < former_half; j++) { if (num % 2 == 1) { a += A[j]; } else { b += B[j]; } num /= 2; } former.push_back(a - b); } for (ll i = 0; i < latter_maximum; i++) { ll num = i; ll a = 0; ll b = 0; for (int j = 0; j < latter_half; j++) { if (num % 2 == 1) { a += A[j + former_half]; } else { b += B[j + former_half]; } num /= 2; } latter.push_back(a - b); } sort(latter.begin(), latter.end()); ll mini = INF<ll>; for (ll i = 0; i < former_maximum; i++) { const ll need = -former[i]; auto ite = lower_bound(latter.begin(), latter.end(), need); if (ite == latter.end()) { if (ite != latter.begin()) { mini = min(mini, abs(former[i] + (*(ite - 1)))); } } else { mini = min(mini, abs(former[i] + (*ite))); if (ite != latter.begin()) { mini = min(mini, abs(former[i] + (*(ite - 1)))); } } } cout << mini << endl; return 0; }