結果

問題 No.783 門松計画
ユーザー はむこはむこ
提出日時 2017-07-18 17:35:29
言語 C++11
(gcc 13.3.0)
結果
TLE  
(最新)
AC  
(最初)
実行時間 -
コード長 8,309 bytes
コンパイル時間 2,339 ms
コンパイル使用メモリ 177,076 KB
実行使用メモリ 8,796 KB
最終ジャッジ日時 2024-07-23 12:16:21
合計ジャッジ時間 12,539 ms
ジャッジサーバーID
（参考情報） 		judge5 / judge2
このコードへのチャレンジ
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ファイルパターン 結果
other AC * 26 TLE * 1
権限があれば一括ダウンロードができます

ソースコード

diff # 

#include <bits/stdc++.h>
#include <sys/time.h>
using namespace std;

#define rep(i,n) for(long long i = 0; i < (long long)(n); i++)
#define repi(i,a,b) for(long long i = (long long)(a); i < (long long)(b); i++)
#define pb push_back
#define all(x) (x).begin(), (x).end()
#define fi first
#define se second
#define mt make_tuple
#define mp make_pair
#define ZERO(a) memset(a,0,sizeof(a))
template<class T1, class T2> bool chmin(T1 &a, T2 b) { return b < a && (a = b, true); }
template<class T1, class T2> bool chmax(T1 &a, T2 b) { return a < b && (a = b, true); }
#define exists find_if
#define forall all_of

using ll = long long; using vll = vector<ll>; using vvll = vector<vll>; using P = pair<ll, ll>;
using ld = long double;  using vld = vector<ld>; 
using vi = vector<int>; using vvi = vector<vi>; vll conv(vi& v) { vll r(v.size()); rep(i, v.size()) r[i] = v[i]; return r; }
using Pos = complex<double>;

template <typename T, typename U> ostream &operator<<(ostream &o, const pair<T, U> &v) {  o << "(" << v.first << ", " << v.second << ")"; return o; }
template<size_t...> struct seq{}; template<size_t N, size_t... Is> struct gen_seq : gen_seq<N-1, N-1, Is...>{}; template<size_t... Is> struct gen_seq<0, Is...> : seq<Is...>{};
template<class Ch, class Tr, class Tuple, size_t... Is>
void print_tuple(basic_ostream<Ch,Tr>& os, Tuple const& t, seq<Is...>){ using s = int[]; (void)s{0, (void(os << (Is == 0? "" : ", ") << get<Is>(t)), 0)...}; }
template<class Ch, class Tr, class... Args> 
auto operator<<(basic_ostream<Ch, Tr>& os, tuple<Args...> const& t) -> basic_ostream<Ch, Tr>& { os << "("; print_tuple(os, t, gen_seq<sizeof...(Args)>()); return os << ")"; }
ostream &operator<<(ostream &o, const vvll &v) { rep(i, v.size()) { rep(j, v[i].size()) o << v[i][j] << " "; o << endl; } return o; }
template <typename T> ostream &operator<<(ostream &o, const vector<T> &v) { o << '['; rep(i, v.size()) o << v[i] << (i != v.size()-1 ? ", " : ""); o << "]";  return o; }
template <typename T>  ostream &operator<<(ostream &o, const set<T> &m) { o << '['; for (auto it = m.begin(); it != m.end(); it++) o << *it << (next(it) != m.end() ? ", " : ""); o << "]";  return o; }
template <typename T, typename U>  ostream &operator<<(ostream &o, const map<T, U> &m) { o << '['; for (auto it = m.begin(); it != m.end(); it++) o << *it << (next(it) != m.end() ? ", " : ""); o << "]";  return o; }
template <typename T, typename U, typename V>  ostream &operator<<(ostream &o, const unordered_map<T, U, V> &m) { o << '['; for (auto it = m.begin(); it != m.end(); it++) o << *it; o << "]";  return o; }
vector<int> range(const int x, const int y) { vector<int> v(y - x + 1); iota(v.begin(), v.end(), x); return v; }
template <typename T> istream& operator>>(istream& i, vector<T>& o) { rep(j, o.size()) i >> o[j]; return i;}
string bits_to_string(ll input, ll n=64) { string s; rep(i, n) s += '0' + !!(input & (1ll << i)); reverse(all(s)); return s; }

template <typename T> unordered_map<T, ll> counter(vector<T> vec){unordered_map<T, ll> ret; for (auto&& x : vec) ret[x]++; return ret;};
string substr(string s, P x) {return s.substr(x.fi, x.se - x.fi); }
struct ci : public iterator<forward_iterator_tag, ll> { ll n; ci(const ll n) : n(n) { } bool operator==(const ci& x) { return n == x.n; } bool operator!=(const ci& x) { return !(*this == x); } ci &operator++() { n++; return *this; } ll operator*() const { return n; } };

size_t random_seed; namespace std { using argument_type = P; template<> struct hash<argument_type> { size_t operator()(argument_type const& x) const { size_t seed = random_seed; seed ^= hash<ll>{}(x.fi); seed ^= (hash<ll>{}(x.se) << 1); return seed; } }; }; // hash for various class
namespace myhash{ const int Bsizes[]={3,9,13,17,21,25,29,33,37,41,45,49,53,57,61,65,69,73,77,81}; const int xor_nums[]={0x100007d1,0x5ff049c9,0x14560859,0x07087fef,0x3e277d49,0x4dba1f17,0x709c5988,0x05904258,0x1aa71872,0x238819b3,0x7b002bb7,0x1cf91302,0x0012290a,0x1083576b,0x76473e49,0x3d86295b,0x20536814,0x08634f4d,0x115405e8,0x0e6359f2}; const int hash_key=xor_nums[rand()%20]; const int mod_key=xor_nums[rand()%20]; template <typename T> struct myhash{ std::size_t operator()(const T& val) const { return (hash<T>{}(val)%mod_key)^hash_key; } }; };
template <typename T> class uset:public std::unordered_set<T,myhash::myhash<T>> { using SET=std::unordered_set<T,myhash::myhash<T>>; public: uset():SET(){SET::rehash(myhash::Bsizes[rand()%20]);} };
template <typename T,typename U> class umap:public std::unordered_map<T,U,myhash::myhash<T>> { public: using MAP=std::unordered_map<T,U,myhash::myhash<T>>; umap():MAP(){MAP::rehash(myhash::Bsizes[rand()%20]);} };    

struct timeval start; double sec() { struct timeval tv; gettimeofday(&tv, NULL); return (tv.tv_sec - start.tv_sec) + (tv.tv_usec - start.tv_usec) * 1e-6; }
struct init_{init_(){ gettimeofday(&start, NULL); ios::sync_with_stdio(false); cin.tie(0); srand((unsigned int)time(NULL)); random_seed = RAND_MAX / 2 + rand() / 2; }} init__;

static const double EPS = 1e-14;
static const long long INF = 1e18;
static const long long mo = 1e9+7;
#define ldout fixed << setprecision(40) 

// 複数個買えるのに注意
// lを長さ2500の数列に展開する必要？
// 相違なら必ず構成できることがわかる。
//
// 相違でない場合は？
//
// DP: i個見て、j円使っていて、門松列々になる？
// 被っている場合は、一番安いのだけを残せば良い。
//
// 最も重複しているものが、n/2個以下ならばよい？

// うーん、2500に展開するのが楽そうだなあ...
// DP[i][pre][ppre][b][k] = ちょうどi個見て、直前が長さpreで、直前前が長さppre、直前前々が存在して(b)、k円使っている場合の最大長さ
// 遷移は、次を取るか取らないか
// O(n^3 c)

ll dp[2][55][55][2][55] = {};
int main(void) {
    ll n, c; cin >> n >> c;
    map<ll, ll> memo;

    vll l_(n), w_(n); cin >> l_ >> w_;
    rep(i, n) {
        ll u = l_[i], v = w_[i];
        if (memo.count(u)) {
            chmax(memo[u], v);
        } else {
            memo[u] = v;
        }
    }
    vll l, w;
    for (auto x : memo) {
        l.pb(x.fi);
        w.pb(x.se);
    }
    n = l.size();

    rep(_, 50) rep(i, n) {
        l.push_back(l[i]);
        w.push_back(w[i]);
    }
    n = l.size();
//    cout << l << endl;
//    cout << w << endl;

    rep(i, 2) rep(j, 55) rep(h, 55) rep(b, 2) rep(k, 55) dp[i][j][h][b][k] = -INF;
    const int init = 54;
    dp[0][init][init][0][0] = 0;
    rep(i, n) {
        ll curr = i % 2;
        ll next = (i + 1) % 2;
        rep(pre, 55) {
            rep(ppre, 55) {
                rep(b, 2) {
                    rep(k, 55) {
                        if (dp[curr][pre][ppre][b][k] == -INF) continue; // 配る必要なし

                        chmax(dp[next][pre][ppre][b][k], dp[curr][pre][ppre][b][k]); // 買わない
//                        cout << i + 1 << " " << pre << " " << ppre << " " << k << " : " << dp[next][pre][ppre][k] << endl;
                        if (k+w[i]>c) continue; // コストオーバー
                        if (
                                (ppre == init && pre == init) || 
                                (ppre == init && pre != init && pre != l[i]) ||
                                (ppre != init && pre != init && (ppre < pre && pre > l[i] && l[i] != ppre)) ||
                                (ppre != init && pre != init && (ppre > pre && pre < l[i] && l[i] != ppre)) 
                           ) { // 門松
//                            cout << ppre << " " << pre << " " << l[i] << "#KADOMATSU" << endl;
                            chmax(dp[next][l[i]][pre][ppre!=init][k+w[i]], dp[curr][pre][ppre][b][k] + l[i]); // 買えるし門松なので買う
//                            cout << i + 1<< " " << l[i] << " " << pre << " " << (ppre!=init) << " " << k+w[i] << " : " << dp[next][l[i]][pre][ppre!=init][k+w[i]] << endl;
                        }
                    }
                }
            }
        }
    }

    ll ret = -INF;
    rep(pre, 55) rep(ppre, 55) rep(k, 55) {
        chmax(ret, dp[n%2][pre][ppre][1][k]);
    }
    if (ret == -INF) {
        cout << 0 << endl;
    } else {
        cout << ret << endl;
    }

    return 0;
}
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