結果
問題 | No.75 回数の期待値の問題 |
ユーザー | kopricky |
提出日時 | 2017-07-23 17:56:48 |
言語 | C++11 (gcc 11.4.0) |
結果 |
WA
|
実行時間 | - |
コード長 | 8,600 bytes |
コンパイル時間 | 1,490 ms |
コンパイル使用メモリ | 166,960 KB |
実行使用メモリ | 6,824 KB |
最終ジャッジ日時 | 2024-10-09 11:01:52 |
合計ジャッジ時間 | 2,264 ms |
ジャッジサーバーID (参考情報) |
judge1 / judge4 |
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テストケース
テストケース表示入力 | 結果 | 実行時間 実行使用メモリ |
---|---|---|
testcase_00 | AC | 2 ms
6,816 KB |
testcase_01 | AC | 2 ms
6,816 KB |
testcase_02 | AC | 1 ms
6,820 KB |
testcase_03 | AC | 2 ms
6,816 KB |
testcase_04 | AC | 1 ms
6,816 KB |
testcase_05 | AC | 2 ms
6,816 KB |
testcase_06 | AC | 2 ms
6,816 KB |
testcase_07 | WA | - |
testcase_08 | WA | - |
testcase_09 | WA | - |
testcase_10 | WA | - |
testcase_11 | WA | - |
testcase_12 | WA | - |
testcase_13 | WA | - |
testcase_14 | WA | - |
testcase_15 | WA | - |
testcase_16 | WA | - |
testcase_17 | WA | - |
testcase_18 | WA | - |
testcase_19 | WA | - |
ソースコード
#include <bits/stdc++.h> #define ll long long #define INF 1000000005 #define MOD 1000000007 #define EPS 1e-10 #define rep(i,n) for(int i=0;i<(int)n;++i) #define each(a, b) for(auto (a): (b)) #define all(v) (v).begin(),(v).end() #define fi first #define se second #define pb push_back #define show(x) cout <<#x<<" = "<<(x)<<endl #define spair(p) cout <<#p<<": "<<p.fi<<" "<<p.se<<endl #define svec(v) cout<<#v<<":";rep(kbrni,v.size())cout<<" "<<v[kbrni];cout<<endl #define sset(s) cout<<#s<<":";each(kbrni,s)cout <<" "<<kbrni;cout<<endl using namespace std; typedef pair<int,int>P; const int MAX_N = 100005; template<typename T> class mat : public vector<vector<T> > { private: int r,c; //行,列 int mat_rank; T mat_det; public: int row() const { return r; } int column() const { return c; } mat(int n,int m,T val = 0){ mat_rank = INF,mat_det = INF; this->r = n,this->c = m; rep(i,n){ this->push_back(vector<T>(m,val)); } } mat operator+(const mat& another){ if(this->r != another.r && this->c != another.c){ cout << "足し算失敗(サイズ不一致)" << endl; exit(1); } mat<T> X(this->r,this->c); rep(i,this->r){ rep(j,this->c){ X[i][j] = (*this)[i][j] + another[i][j]; } } return X; } mat operator+(const T val){ mat<T> X(this->r,this->c); rep(i,this->r){ rep(j,this->c){ X[i][j] = (*this)[i][j] + val; } } return X; } mat operator-(const mat& another){ if(this->r != another.r && this->c != another.c){ cout << "引き算失敗(サイズ不一致)" << endl; exit(1); } mat<T> X(this->r,this->c); rep(i,this->r){ rep(j,this->c){ X[i][j] = (*this)[i][j] - another[i][j]; } } return X; } mat operator-(const T val){ mat<T> X(this->r,this->c); rep(i,this->r){ rep(j,this->c){ X[i][j] = (*this)[i][j] - val; } } return X; } vector<T> operator*(const vector<T>& another){ if(this->c != another.size()){ cout << "掛け算失敗(サイズ不一致)" << endl; exit(1); } vector<T> vec(this->r,0); rep(i,this->r){ rep(j,this->c){ vec[i] += (*this)[i][j] * another[j]; } } return vec; } mat operator*(const mat& another){ if(this->c != another.r){ cout << "掛け算失敗(サイズ不一致)" << endl; exit(1); } mat<T> X(this->r,another.c); rep(i,this->r){ rep(k,this->c){ rep(j,another.c){ X[i][j] += (*this)[i][k]*another[k][j]; } } } return X; } mat operator-(){ mat<T> X(this->r,this->c); rep(i,this->r){ rep(j,this->c){ X[i][j] = -(*this)[i][j]; } } return X; } int rank(){ if(this->mat_rank <= min(this->r,this->c)){ return this->mat_rank; } int n = this->r; T D = 1; mat B(n,n); rep(i,n){ rep(j,n){ B[i][j] = (*this)[i][j]; } } rep(i,n){ int pivot = i; for(int j=i;j<n;j++){ if(abs(B[j][i]) > abs(B[pivot][i])){ pivot = j; } } if(abs(B[pivot][i]) < EPS){ this->mat_rank = i; this->mat_det = 0; return i; } swap(B[i],B[pivot]); D *= B[i][i]; for(int j=i+1;j<n;j++){ B[i][j] /= B[i][i]; } for(int j=i+1;j<n;j++){ for(int k=i+1;k<n;k++){ B[j][k] -= B[j][i] * B[i][k]; } } } this->mat_rank = n; this->mat_det = D; return n; } T det(){ if(this->r != this->c){ cout << "正方行列でない(行列式定義不可)" << endl; exit(1); } if(this->mat_rank <= this->r){ return this->mat_det; } int res = rank(); return this->mat_det; } mat inverse(){ if(this->r != this->c){ cout << "正方行列でない(逆行列定義不可)" << endl; exit(1); } if(this->mat_rank < this->r){ cout << "ランク落ち(逆行列が存在しない)" << endl; exit(1); } int n = this->r; T D = 1; mat B(n,2*n); rep(i,n){ rep(j,n){ B[i][j] = (*this)[i][j]; } } rep(i,n){ B[i][n+i] = 1; } rep(i,n){ int pivot = i; for(int j=i;j<n;j++){ if(abs(B[j][i]) > abs(B[pivot][i])){ pivot = j; } } if(abs(B[pivot][i]) < EPS){ cout << "解なしor不定" << endl; exit(1); } swap(B[i],B[pivot]); D *= B[i][i]; for(int j=i+1;j<=2*n;j++){ B[i][j] /= B[i][i]; } rep(j,n){ if(i != j){ for(int k=i+1;k<=2*n;k++){ B[j][k] -= B[j][i] * B[i][k]; } } } } this->mat_rank = n; this->mat_det = D; mat res(n,n); rep(i,n){ rep(j,n){ res[i][j] = B[i][n+j]; } } return res; } void print(){ rep(i,this->r){ rep(j,(this->c)-1){ cout << (*this)[i][j] << ","; } cout << (*this)[i][(this->c)-1] << endl; } } }; template<typename T> vector<T> eq_solve(const mat<T>& A,const vector<T>& b){ if(A.row() != A.column()){ cout << "正方行列でない(解なしor不定)" << endl; exit(1); } int n = A.row(); mat<T> B(n,n+1); rep(i,n){ rep(j,n){ B[i][j] = A[i][j]; } } rep(i,n){ B[i][n] = b[i]; } rep(i,n){ int pivot = i; for(int j=i;j<n;j++){ if(abs(B[j][i]) > abs(B[pivot][i])){ pivot = j; } } if(abs(B[pivot][i]) < EPS){ cout << "解なしor不定" << endl; exit(1); } swap(B[i],B[pivot]); for(int j=i+1;j<=n;j++){ B[i][j] /= B[i][i]; } rep(j,n){ if(i != j){ for(int k=i+1;k<=n;k++){ B[j][k] -= B[j][i] * B[i][k]; } } } } vector<T> res(n); rep(i,n){ res[i] = B[i][n]; } return res; } template<typename T> mat<T> pow(mat<T> A,ll cnt) { if(A.row() != A.column()){ cout << "累乗不可" << endl; } int n = A.row(); mat<T> B(n,n); rep(i,n){ B[i][i] = 1; } while(cnt>0){ if(cnt & 1){ B = B*A; } A = A*A; cnt >>= 1; } return B; } template<typename T> mat<T> mod_mul(mat<T>& A,mat<T>& B,ll mod) { if(A.column() != B.row()){ cout << "掛け算失敗(サイズ不一致)" << endl; exit(1); } mat<T> X(A.row(),B.column()); rep(i,A.row()){ rep(k,A.column()){ rep(j,B.column()){ X[i][j] = (X[i][j] + A[i][k]*B[k][j]) % mod; } } } return X; } template<typename T> mat<T> pow(mat<T> A,ll cnt,ll mod) { if(A.row() != A.column()){ cout << "累乗不可" << endl; } int n = A.row(); mat<T> B(n,n); rep(i,n){ B[i][i] = 1; } while(cnt>0){ if(cnt & 1){ B = mod_mul(B,A,mod); } A = mod_mul(A,A,mod); cnt >>= 1; } return B; } int main() { int K; cin >> K; mat<double> ex(K+1,K+1); rep(i,K){ ex[i][i] += 1; for(int j=1;i+j<=K;j++){ ex[i][i+j] -= 1 / 6.0; } } for(int i=max(K-5,0);i<K;i++){ ex[i][0] -= (6-K+i) / 6.0; } ex[K][K] += 1; vector<double> b(K+1,1); b[K] = 0; vector<double> res = eq_solve(ex,b); printf("%.10f\n",res[0]); return 0; }