結果

問題 No.229 線分上を往復する3つの動点の一致
コンテスト
ユーザー kopricky
提出日時 2017-08-02 14:45:26
言語 C++11
(gcc 15.2.0 + boost 1.89.0)
コンパイル:
g++-15 -O2 -lm -std=gnu++11 -Wuninitialized -DONLINE_JUDGE -o a.out _filename_
実行:
./a.out
結果
AC  
実行時間 2 ms / 5,000 ms
コード長 1,494 bytes
記録
記録タグの例:
初AC ショートコード 純ショートコード 純主流ショートコード 最速実行時間
コンパイル時間 976 ms
コンパイル使用メモリ 176,424 KB
実行使用メモリ 6,400 KB
最終ジャッジ日時 2026-04-27 12:27:31
合計ジャッジ時間 2,403 ms
ジャッジサーバーID
（参考情報） 		judge2_0 / judge3_1
このコードへのチャレンジ
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ファイルパターン 結果
sample AC * 3
other AC * 43
権限があれば一括ダウンロードができます
コンパイルメッセージ
In file included from /home/linuxbrew/.linuxbrew/Cellar/gcc/15.2.0_1/include/c++/15/ostream:42,
                 from /home/linuxbrew/.linuxbrew/Cellar/gcc/15.2.0_1/include/c++/15/istream:43,
                 from /home/linuxbrew/.linuxbrew/Cellar/gcc/15.2.0_1/include/c++/15/sstream:42,
                 from /home/linuxbrew/.linuxbrew/Cellar/gcc/15.2.0_1/include/c++/15/complex:50,
                 from /home/linuxbrew/.linuxbrew/Cellar/gcc/15.2.0_1/include/c++/15/ccomplex:43,
                 from /home/linuxbrew/.linuxbrew/Cellar/gcc/15.2.0_1/include/c++/15/x86_64-pc-linux-gnu/bits/stdc++.h:133,
                 from main.cpp:1:
In member function 'std::basic_ostream<_CharT, _Traits>::__ostream_type& std::basic_ostream<_CharT, _Traits>::operator<<(long long int) [with _CharT = char; _Traits = std::char_traits<char>]',
    inlined from 'int main()' at main.cpp:59:13:
/home/linuxbrew/.linuxbrew/Cellar/gcc/15.2.0_1/include/c++/15/bits/ostream.h:212:25: warning: 'ans1' may be used uninitialized [-Wmaybe-uninitialized]
  212 |       { return _M_insert(__n); }
      |                ~~~~~~~~~^~~~~
main.cpp: In function 'int main()':
main.cpp:41:8: note: 'ans1' was declared here
   41 |     ll ans1,ans2;
      |        ^~~~
In member function 'std::basic_ostream<_CharT, _Traits>::__ostream_type& std::basic_ostream<_CharT, _Traits>::operator<<(long long int) [with _CharT = char; _Traits = std::char_traits<char>]',
    inlined from 'int main()' at main.cpp:59:28:
/home/linuxbrew/.linuxbrew/Cellar/gcc/15.2.0_1/include/c++/15/bits/ostream.h:212:25: warning: 'ans2' may be used uninitialized [-Wmaybe-uninitialized]
  212 |       { return _M_insert(__n); }
      |                ~~~~~~~~~^~~~~
main.cpp: In function 'int main()':
main.cpp:41:13: note: 'ans2' was declared here
   41 |     ll ans1,ans2;
      |             ^~~~

ソースコード

diff #
raw source code 

#include <bits/stdc++.h>
#define ll long long
#define INF 1000000005
#define MOD 1000000007
#define EPS 1e-10
#define rep(i,n) for(int i=0;i<(int)n;++i)
#define each(a, b) for(auto (a): (b))
#define all(v) (v).begin(),(v).end()
#define fi first
#define se second
#define pb push_back
#define show(x) cout <<#x<<" = "<<(x)<<endl
#define spair(p) cout <<#p<<": "<<p.fi<<" "<<p.se<<endl
#define svec(v) cout<<#v<<":";rep(kbrni,v.size())cout<<" "<<v[kbrni];cout<<endl
#define sset(s) cout<<#s<<":";each(kbrni,s)cout <<" "<<kbrni;cout<<endl

using namespace std;

typedef pair<int,int>P;

const int MAX_N = 100005;

ll gcd(ll a,ll b)
{
    if(a%b == 0){
        return b;
    }else{
        return gcd(b,a%b);
    }
}

int main()
{
    cin.tie(0);
    ios::sync_with_stdio(false);
    int t1,t2,t3;
    cin >> t1 >> t2 >> t3;
    vector<int> v1={t2+t1,t2-t1};
    vector<int> v2={t3+t1,t3-t1};
    double mn = 1e100;
    ll ans1,ans2;
    rep(i,2){
        rep(j,2){
            ll num1 = gcd(v1[i],t1*t2);
            ll a1 = (v1[i])/num1;
            ll a2 = (t1*t2)/num1;
            ll num2 = gcd(v2[j],t1*t3);
            ll a3 = (v2[j])/num2;
            ll a4 = (t1*t3)/num2;
            ll si = a2*a4 / gcd(a2,a4);
            ll bo = gcd(a1,a3);
            if(mn > (double)si/bo){
                mn = (double)si/bo;
                ll hoge = gcd(si,bo);
                ans1 = si/hoge,ans2 = bo/hoge;
            }
        }
    }
    cout << ans1 << "/" << ans2 << endl;
    return 0;
}
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