結果
問題 | No.563 超高速一人かるた large |
ユーザー | はまやんはまやん |
提出日時 | 2017-08-28 11:22:20 |
言語 | C++14 (gcc 12.3.0 + boost 1.83.0) |
結果 |
WA
|
実行時間 | - |
コード長 | 6,111 bytes |
コンパイル時間 | 2,373 ms |
コンパイル使用メモリ | 187,940 KB |
実行使用メモリ | 814,080 KB |
最終ジャッジ日時 | 2024-11-06 08:21:27 |
合計ジャッジ時間 | 22,843 ms |
ジャッジサーバーID (参考情報) |
judge2 / judge5 |
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テストケース
テストケース表示入力 | 結果 | 実行時間 実行使用メモリ |
---|---|---|
testcase_00 | AC | 3 ms
6,820 KB |
testcase_01 | WA | - |
testcase_02 | AC | 3 ms
6,816 KB |
testcase_03 | WA | - |
testcase_04 | WA | - |
testcase_05 | WA | - |
testcase_06 | WA | - |
testcase_07 | WA | - |
testcase_08 | WA | - |
testcase_09 | TLE | - |
testcase_10 | WA | - |
testcase_11 | WA | - |
testcase_12 | WA | - |
testcase_13 | AC | 860 ms
6,820 KB |
testcase_14 | AC | 803 ms
6,816 KB |
testcase_15 | AC | 2,980 ms
6,820 KB |
testcase_16 | AC | 665 ms
6,820 KB |
testcase_17 | WA | - |
testcase_18 | AC | 1,067 ms
7,808 KB |
testcase_19 | MLE | - |
testcase_20 | -- | - |
ソースコード
#include<bits/stdc++.h> #define rep(i,a,b) for(int i=a;i<b;i++) #define rrep(i,a,b) for(int i=a;i>=b;i--) #define fore(i,a) for(auto &i:a) #pragma GCC optimize ("-O3") using namespace std; void _main(); int main() { cin.tie(0); ios::sync_with_stdio(false); _main(); } //--------------------------------------------------------------------------------------------------- template<int MOD> struct ModInt { static const int Mod = MOD; unsigned x; ModInt() : x(0) { } ModInt(signed sig) { x = sig < 0 ? sig % MOD + MOD : sig % MOD; } ModInt(signed long long sig) { x = sig < 0 ? sig % MOD + MOD : sig % MOD; } int get() const { return (int)x; } ModInt &operator+=(ModInt that) { if ((x += that.x) >= MOD) x -= MOD; return *this; } ModInt &operator-=(ModInt that) { if ((x += MOD - that.x) >= MOD) x -= MOD; return *this; } ModInt &operator*=(ModInt that) { x = (unsigned long long)x * that.x % MOD; return *this; } ModInt &operator/=(ModInt that) { return *this *= that.inverse(); } ModInt operator+(ModInt that) const { return ModInt(*this) += that; } ModInt operator-(ModInt that) const { return ModInt(*this) -= that; } ModInt operator*(ModInt that) const { return ModInt(*this) *= that; } ModInt operator/(ModInt that) const { return ModInt(*this) /= that; } ModInt inverse() const { long long a = x, b = MOD, u = 1, v = 0; while (b) { long long t = a / b; a -= t * b; std::swap(a, b); u -= t * v; std::swap(u, v); } return ModInt(u); } bool operator==(ModInt that) const { return x == that.x; } bool operator!=(ModInt that) const { return x != that.x; } ModInt operator-() const { ModInt t; t.x = x == 0 ? 0 : Mod - x; return t; } }; template<int MOD> ostream& operator<<(ostream& st, const ModInt<MOD> a) { st << a.get(); return st; }; template<int MOD> ModInt<MOD> operator^(ModInt<MOD> a, unsigned long long k) { ModInt<MOD> r = 1; while (k) { if (k & 1) r *= a; a *= a; k >>= 1; } return r; } template<typename T, int FAC_MAX> struct Comb { vector<T> fac, ifac; Comb() {fac.resize(FAC_MAX, 1); ifac.resize(FAC_MAX, 1);rep(i, 1, FAC_MAX) fac[i] = fac[i - 1] * i; rep(i, 1, FAC_MAX) ifac[i] = T(1) / fac[i];} T aPb(int a, int b) { if (b < 0 || a < b) return T(0); return fac[a] * ifac[a - b]; } T aCb(int a, int b) { if (b < 0 || a < b) return T(0); return fac[a] * ifac[a - b] * ifac[b]; } T nHk(int n, int k) { if (n == 0 && k == 0) return T(1); if (n <= 0 || k < 0) return 0; return aCb(n + k - 1, k); } }; struct Trie { struct Node { int cnt, dep, hit; string str; Node* c[26]; Node() { cnt = dep = hit = 0; str = ""; rep(i, 0, 26) c[i] = 0; } }; Node* root; Trie() { root = new Node(); } void add(string x) { update(root, x); } void update(Node*& x, string a, int b = 0) { if (!x) x = new Node(); x->cnt++; x->dep = b; x->str = a.substr(0, b); // <- you can erase this if (b == a.length()) { x->str = a; x->hit = 1; return; } update(x->c[a[b] - 'a'], a, b + 1); } void dump() { dump(root); } void dump(Node*& x) { printf("%d [cnt:%d,dep:%d,hit:%d,str:%s]", x, x->cnt, x->dep, x->hit, x->str.c_str()); rep(i, 0, 26) { if (x->c[i]) printf(" (%c -> %d)", char('a' + i), x->c[i]); } printf("\n"); rep(i, 0, 26) if (x->c[i]) dump(x->c[i]); } void getAllBranchDfs(Node* cu, vector<Node*> &res) { int cnt = 0; rep(i, 0, 26) if (cu->c[i]) cnt++; if (2 <= cnt) res.push_back(cu); rep(i, 0, 26) if (cu->c[i]) getAllBranchDfs(cu->c[i], res); } vector<Node*> getAllBranch() { vector<Node*> res; getAllBranchDfs(root, res); return res; } void getAllHitsDfs(Node* cu, vector<Node*> &res) { if (cu->hit) res.push_back(cu); rep(i, 0, 26) if (cu->c[i]) getAllHitsDfs(cu->c[i], res); } vector<Node*> getAllHits() { vector<Node*> res; getAllHitsDfs(root, res); return res; } }; typedef ModInt<1000000007> mint; /*--------------------------------------------------------------------------------------------------- ∧_∧ ∧_∧ (´<_` ) Welcome to My Coding Space! ( ´_ゝ`) / ⌒i / \ | | / / ̄ ̄ ̄ ̄/ | __(__ニつ/ _/ .| .|____ \/____/ (u ⊃ ---------------------------------------------------------------------------------------------------*/ Comb<mint, 2020> com; int N; string S[2020]; mint ans[2020]; //--------------------------------------------------------------------------------------------------- void _main() { cin >> N; rep(i, 0, N) cin >> S[i]; Trie trie; rep(i, 0, N) trie.add(S[i]); //trie.dump(); auto v = trie.getAllBranch(); fore(node, v) { //printf("! %s\n", node->str.c_str()); rep(i, 0, 26) if (node->c[i]) { int c = node->c[i]->cnt; int cc = node->cnt - c; int other = N - node->cnt; mint res = node->c[i]->dep; rep(j, 0, other + 1) rep(k, 0, cc) { mint co = com.aPb(c, c - 1) * com.aPb(other, j) * com.aPb(cc, k) * com.fac[c - 1 + j + k] * com.ifac[j] * com.ifac[k] * com.ifac[c - 1]; mint d = res * co; ans[c + j + k] += d; //printf("%d : %d %d\n", c + j, res.get(), co.get()); } } } v = trie.getAllHits(); fore(node, v) { mint res = node->dep + 1; int c = node->cnt; int other = N - c; rep(j, 0, other + 1) rep(k, 0, c - 1) { mint co = com.aPb(c - 1, k) * com.aPb(other, j) * com.aCb(k + j, j); mint d = res * co; ans[j + k + 1] += d; //printf("%d : %d %d\n", c + j, res.get(), co.get()); } } rep(i, 2, N + 1) ans[i] += ans[i - 1] * (N - i + 1); ans[N] += com.fac[N]; rep(i, 1, N + 1) printf("%d\n", ans[i].get()); }