結果
問題 | No.184 たのしい排他的論理和(HARD) |
ユーザー |
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提出日時 | 2015-04-17 02:15:09 |
言語 | C++11 (gcc 13.3.0) |
結果 |
AC
|
実行時間 | 473 ms / 5,000 ms |
コード長 | 3,070 bytes |
コンパイル時間 | 819 ms |
コンパイル使用メモリ | 99,916 KB |
実行使用メモリ | 18,036 KB |
最終ジャッジ日時 | 2024-07-04 11:19:37 |
合計ジャッジ時間 | 9,952 ms |
ジャッジサーバーID (参考情報) |
judge5 / judge2 |
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ファイルパターン | 結果 |
---|---|
sample | AC * 3 |
other | AC * 34 |
ソースコード
#include <iostream>#include <iomanip>#include <sstream>#include <vector>#include <string>#include <set>#include <unordered_set>#include <map>#include <unordered_map>#include <stack>#include <queue>#include <deque>#include <algorithm>#include <functional>#include <iterator>#include <limits>#include <numeric>#include <utility>#include <cmath>#include <cassert>#include <cstdio>using namespace std; using namespace placeholders;using LL = long long;using ULL = unsigned long long;using VI = vector< int >;using VVI = vector< vector< int > >;using VS = vector< string >;using SS = stringstream;using PII = pair< int, int >;using VPII = vector< pair< int, int > >;template < typename T = int > using VT = vector< T >;template < typename T = int > using VVT = vector< vector< T > >;template < typename T = int > using LIM = numeric_limits< T >;template < typename T > inline istream& operator>>( istream &s, vector< T > &v ){ for ( T &t : v ) { s >> t; } return s; }template < typename T > inline ostream& operator<<( ostream &s, const vector< T > &v ){ for ( int i = 0; i < int( v.size() ); ++i ){ s << ( " " + !i) << v[i]; } return s; }template < typename T > inline T fromString( const string &s ) { T res; istringstream iss( s ); iss >> res; return res; };template < typename T > inline string toString( const T &a ) { ostringstream oss; oss << a; return oss.str(); };#define REP2( i, n ) REP3( i, 0, n )#define REP3( i, m, n ) for ( int i = ( int )( m ); i < ( int )( n ); ++i )#define GET_REP( a, b, c, F, ... ) F#define REP( ... ) GET_REP( __VA_ARGS__, REP3, REP2 )( __VA_ARGS__ )#define FOR( e, c ) for ( auto &e : c )#define ALL( c ) ( c ).begin(), ( c ).end()#define AALL( a, t ) ( t* )a, ( t* )a + sizeof( a ) / sizeof( t )#define DRANGE( c, p ) ( c ).begin(), ( c ).begin() + p, ( c ).end()#define SZ( v ) ( (int)( v ).size() )#define PB push_back#define EM emplace#define EB emplace_back#define BI back_inserter#define EXIST( c, e ) ( ( c ).find( e ) != ( c ).end() )#define MP make_pair#define fst first#define snd second#define DUMP( x ) cerr << #x << " = " << ( x ) << endl// バイナリ行列の階数を求める// O( N^3 )int binary_matrix_rank( vector< vector<bool> > matrix ){const int N = matrix.size(), M = matrix[0].size();int r = 0;for ( int x = 0; r < N && x < M; ++x ){int p = r;for ( int i = r + 1; i < N; i++ ){if ( matrix[i][x] ){p = i;}}swap( matrix[r], matrix[p] );if ( !matrix[r][x] ){continue;}for ( int i = r + 1; i < N; ++i ){if ( !matrix[i][x] ){continue;}for ( int j = x; j < M; ++j ){matrix[i][j] = matrix[i][j] ^ matrix[r][j];}}r++;}return r;}int main(){cin.tie( 0 );ios::sync_with_stdio( false );int N;cin >> N;VT< LL > A( N );cin >> A;VVT< bool > matrix( N, VT< bool >( 61 ) );REP( i, N ){REP( j, 61 ){matrix[i][j] = !!( A[i] & 1LL << j );}}cout << ( 1LL << binary_matrix_rank( matrix ) ) << endl;return 0;}