結果
| 問題 |
No.563 超高速一人かるた large
|
| コンテスト | |
| ユーザー |
|
| 提出日時 | 2017-09-11 17:10:40 |
| 言語 | C++14 (gcc 13.3.0 + boost 1.87.0) |
| 結果 |
WA
|
| 実行時間 | - |
| コード長 | 4,925 bytes |
| コンパイル時間 | 2,309 ms |
| コンパイル使用メモリ | 183,552 KB |
| 実行使用メモリ | 55,424 KB |
| 最終ジャッジ日時 | 2024-11-07 16:58:01 |
| 合計ジャッジ時間 | 5,644 ms |
|
ジャッジサーバーID (参考情報) |
judge2 / judge3 |
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| ファイルパターン | 結果 |
|---|---|
| sample | AC * 3 |
| other | AC * 1 WA * 17 |
ソースコード
#include "bits/stdc++.h"
using namespace std;
#define FOR(i,j,k) for(int (i)=(j);(i)<(int)(k);++(i))
#define rep(i,j) FOR(i,0,j)
#define each(x,y) for(auto &(x):(y))
#define mp make_pair
#define MT make_tuple
#define all(x) (x).begin(),(x).end()
#define debug(x) cout<<#x<<": "<<(x)<<endl
#define smax(x,y) (x)=max((x),(y))
#define smin(x,y) (x)=min((x),(y))
#define MEM(x,y) memset((x),(y),sizeof (x))
#define sz(x) (int)(x).size()
#define rt return
using dbl = double;
using ll = long long;
using pii = pair<int, int>;
using vi = vector<int>;
using vll = vector<ll>;
template<int MOD>
class ModInt {
public:
ModInt() :value(0) {}
ModInt(long long val) :value((int)(val<0 ? MOD + val%MOD : val%MOD)) { }
ModInt& operator+=(ModInt that) {
value = value + that.value;
if (value >= MOD)value -= MOD;
return *this;
}
ModInt& operator-=(ModInt that) {
value -= that.value;
if (value<0)value += MOD;
return *this;
}
ModInt& operator*=(ModInt that) {
value = (int)((long long)value * that.value % MOD);
return *this;
}
ModInt &operator/=(ModInt that) {
return *this *= that.inverse();
}
ModInt operator+(ModInt that) const {
return ModInt(*this) += that;
}
ModInt operator-(ModInt that) const {
return ModInt(*this) -= that;
}
ModInt operator*(ModInt that) const {
return ModInt(*this) *= that;
}
ModInt operator/(ModInt that) const {
return ModInt(*this) /= that;
}
ModInt pow(long long k) const {
if (value == 0)return 0;
ModInt n = *this, res = 1;
while (k) {
if (k & 1)res *= n;
n *= n;
k >>= 1;
}
return res;
}
ModInt inverse() const {
long long a = value, b = MOD, u = 1, v = 0;
while (b) {
long long t = a / b;
a -= t * b;
swap(a, b);
u -= t * v;
swap(u, v);
}
return ModInt(u);
}
int toi() const { return value; }
private:
int value;
};
typedef ModInt<1000000007> mint;
ostream& operator<<(ostream& os, const mint& x) {
os << x.toi();
return os;
}
struct RollingHash {
static const int C = 31, C2 = 29, P = 1000000007, P2 = 1000000009;
int _n;
vector<long long> pw, pw2, hs, hs2;
RollingHash() {}
RollingHash(const string &st)
:_n((int)st.size()), pw(_n + 1), pw2(_n + 1), hs(_n + 1), hs2(_n + 1)
{
pw[0] = pw2[0] = 1;
rep(i, _n) {
pw[i + 1] = (pw[i] * C) % P;
pw2[i + 1] = (pw2[i] * C2) % P2;
hs[i + 1] = (C*hs[i] + st[i]) % P;
hs2[i + 1] = (C2*hs2[i] + st[i]) % P2;
}
}
// [l, r)
pii getHash(int l, int r) {
int res, res2;
res = (hs[r] - hs[l] * pw[r - l]) % P;
res2 = (hs2[r] - hs2[l] * pw2[r - l]) % P2;
if (res < 0)res += P;
if (res2 < 0)res2 += P2;
return mp(res, res2);
}
};
vector<vector<int>> combinations(int n, int mod) {
auto res = vector<vector<int>>(n + 1, vector<int>(n + 1));
rep(i, n + 1) res[i][0] = 1;
for (int i = 1; i <= n; ++i) for (int j = 1; j <= i; ++j)
res[i][j] = (res[i - 1][j - 1] + res[i - 1][j]) % mod;
return res;
}
const int MO = (int)1e9 + 7;
string S[2001];
RollingHash rh[2001];
int f[2001][2001], g[2001][2001];
mint ans[2001], fact[2001];
int main(){
ios::sync_with_stdio(false);
cin.tie(0);
int N;
cin >> N;
rep(i, N) {
cin >> S[i];
}
sort(S, S + N);
rep(i, N) {
rh[i] = RollingHash(S[i]);
}
rep(i, N)rep(j, N) {
if (i == j)f[i][j] = 1;
else if (i > j)f[i][j] = f[j][i];
else {
int ok = 0, ng = min(sz(S[i]), sz(S[j])) + 1, mid;
while (ng - ok > 1) {
mid = (ok + ng) / 2;
(rh[i].getHash(0, mid) == rh[j].getHash(0, mid) ? ok : ng) = mid;
}
f[i][j] = ng;
}
}
rep(b, N)g[0][b + 1] = f[b][b + 1];
f[N - 1][N] = 1;
// g[0][N] = 0
rep(a, N)FOR(b, a + 1, N) {
g[a + 1][b + 1] = f[a][b] + f[b][b + 1];
}
auto C = combinations(N + 10, MO);
for (int ba = 1; ba <= N; ++ba) {
mint sm;
// 取ってないのがa
// a+baを次に取る
for (int a = 0; a + ba < N; ++a) {
sm += max(f[a][a + ba], f[a + ba][a + ba + 1]);
}
// 全体でK個取る
for (int K = ba; K <= N - 1; ++K) {
if (ba != N)ans[K - 1] += sm * C[N - ba - 1][K - ba];
}
}
for (int b = 0; b < N; ++b) {
for (int K = b+1; K <= N; ++K) {
ans[K - 1] += f[b][b + 1] * C[N - b - 1][K - b - 1];
}
}
fact[0] = 1;
rep(i, N)fact[i + 1] = fact[i] * (i + 1);
rep(i, N)cout << ans[i] * fact[i + 1] << endl;
}