結果
| 問題 |
No.399 動的な領主
|
| コンテスト | |
| ユーザー |
|
| 提出日時 | 2017-10-11 08:18:09 |
| 言語 | C++14 (gcc 13.3.0 + boost 1.87.0) |
| 結果 |
AC
|
| 実行時間 | 127 ms / 2,000 ms |
| コード長 | 4,696 bytes |
| コンパイル時間 | 2,175 ms |
| コンパイル使用メモリ | 181,808 KB |
| 実行使用メモリ | 38,736 KB |
| 最終ジャッジ日時 | 2024-11-17 09:09:45 |
| 合計ジャッジ時間 | 4,865 ms |
|
ジャッジサーバーID (参考情報) |
judge1 / judge5 |
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| ファイルパターン | 結果 |
|---|---|
| other | AC * 19 |
ソースコード
#include <bits/stdc++.h>
using namespace std;
using vi = vector<int>;
using vvi = vector<vector<int>>;
class RMQidx{
private:
int n; // size of val
vector<vector<int>> idx; // doubling range min index. idx[k][p]: index of min(val[p:p+2^k]) including p and not including p+2^k.
vector<int> val;
void init(const vector<int> &src){
n = src.size();
val = src;
idx.emplace_back(vector<int>(n, 0));
for (int i = 0; i != n; ++i) idx[0][i] = i;
for (int k = 0, r = 1; r < n; ++k, r <<= 1){
idx.emplace_back(idx[k]);
for (int p = 0; p + r < n; ++p){
auto idxL = idx[k][p];
auto idxR = idx[k][p + r];
idx[k + 1][p] = (val[idxL] > val[idxR]) ? idxR : idxL;
}
}
}
public:
RMQidx(): n(0), idx(vector<vector<int>>()), val(vector<int>()) {}
RMQidx(const vector<int> &src){init(src);}
int query(int L, int R){ // index of min(data[0][L..R] including both ends. [L, R]
assert(L <= R);
if (L == R) return L;
int k = 31 - __builtin_clz(R - L);
auto idxL = idx[k][L];
auto idxR = idx[k][R + 1 - (1 << k)];
return (val[idxL] > val[idxR])? idxR: idxL;
}
};
class LCA{
private:
int n; // number of vertexes
int root;
const vector<vector<int>> & Es;
vector<int> height; // height[v] = height of vertex v.
vector<int> i2v; // i2v[i] = v. Euler tour order of vertexes.
vector<int> v2i; // v2i[v] = i. Last position of vertex v in the Euler tour.
RMQidx rmq; // Range Minimum Query object which returns the position (idx) of the minimum value in the euler tour.
void dfs(int v, int h){
height[v] = h;
i2v.push_back(v);
for (auto u : Es[v]){
if (height[u] == -1) {
dfs(u, h + 1);
i2v.push_back(v);
}
}
}
public:
LCA(const vector<vector<int>> &_Es, int _root = 0):Es(_Es){
n = Es.size();
root = _root;
height = vector<int>(n, -1);
v2i = vector<int>(n, -1);
dfs(root, 0);
assert(i2v.size() == 2 * n - 1);
vector<int> val(2 * n - 1);
for (int i = 0; i != 2 * n - 1; ++i) {
val[i] = height[i2v[i]];
v2i[i2v[i]] = i;
}
rmq = RMQidx(val);
}
int query(int u, int v){
// returns lowest common ancestor of vertex u and vertex v.
int i = v2i[u];
int j = v2i[v];
if (i > j) swap(i, j);
return i2v[rmq.query(i, j)];
}
int dist(int u, int v){
// returns the distance between vertex u and vertex v.
int k = query(u, v);
return height[u] + height[v] - 2 * height[k];
}
};
void dfs_et(int v, int p, vi & euler_tour, const vvi & Es){
// v: current vertex, p: parent of v
euler_tour.push_back(v);
for (auto u : Es[v]){
if (u == p) continue;
dfs_et(u, v, euler_tour, Es);
euler_tour.push_back(v);
}
}
vi get_euler_tour(const vvi &Es, int root = 0){
vi euler_tour;
int nV = Es.size();
dfs_et(root, -1, euler_tour, Es);
return euler_tour;
}
vi get_first_pos(const vi & et, int N){
vi first(N, -1);
for (int i = 0; i < et.size(); ++i){
if (first[et[i]] == -1) first[et[i]] = i;
}
return first;
}
vi get_last_pos(const vi & et, int N){
vi last(N, -1);
for (int i = 0; i < et.size(); ++i){
last[et[i]] = i;
}
return last;
}
int main() {
ios::sync_with_stdio(false);
cin.tie(0);
int N;
cin >> N;
vector<vector<int>> Es(N);
for (int i = 1; i < N; ++i){
int a, b;
cin >> a >> b;
--a;
--b;
Es[a].push_back(b);
Es[b].push_back(a);
}
LCA lca(Es);
auto euler_tour = get_euler_tour(Es);
auto first = get_first_pos(euler_tour, N);
auto last = get_last_pos(euler_tour, N);
vector<long long> imos(2*N - 1, 0);
int M;
cin >> M;
while (M--){
int a, b;
cin >> a >> b;
--a;
--b;
int d = lca.query(a, b);
++imos[first[a]];
++imos[first[b]];
--imos[first[d]];
if (d != 0) --imos[first[d] - 1];
}
vector<long long> cum(2 * N - 1, 0);
cum[0] = imos[0];
for (int i = 1; i < cum.size(); ++i){
cum[i] = cum[i - 1] + imos[i];
}
long long cost = 0;
cost += cum[last[0]] * (cum[last[0]] + 1) / 2;
for (int i = 1; i < N; ++i){
long long temp = cum[last[i]] - cum[first[i] - 1];
cost += temp * (temp + 1LL)/2LL;
}
cout << cost;
return 0;
}