結果

問題 No.189 SUPER HAPPY DAY
ユーザー torus711
提出日時 2015-04-22 00:20:49
言語 C++11
(gcc 13.3.0)
結果
AC  
実行時間 29 ms / 5,000 ms
コード長 3,100 bytes
コンパイル時間 916 ms
コンパイル使用メモリ 99,288 KB
実行使用メモリ 7,552 KB
最終ジャッジ日時 2024-07-04 20:14:22
合計ジャッジ時間 1,852 ms
ジャッジサーバーID
(参考情報)
judge3 / judge5
このコードへのチャレンジ
(要ログイン)
ファイルパターン 結果
sample AC * 3
other AC * 23
権限があれば一括ダウンロードができます

ソースコード

diff #
プレゼンテーションモードにする

#include <iostream>
#include <iomanip>
#include <sstream>
#include <vector>
#include <string>
#include <set>
#include <unordered_set>
#include <map>
#include <unordered_map>
#include <stack>
#include <queue>
#include <deque>
#include <algorithm>
#include <functional>
#include <iterator>
#include <limits>
#include <numeric>
#include <utility>
#include <cmath>
#include <cassert>
#include <cstdio>
using namespace std; using namespace placeholders;
using LL = long long;
using ULL = unsigned long long;
using VI = vector< int >;
using VVI = vector< vector< int > >;
using VS = vector< string >;
using SS = stringstream;
using PII = pair< int, int >;
using VPII = vector< pair< int, int > >;
template < typename T = int > using VT = vector< T >;
template < typename T = int > using VVT = vector< vector< T > >;
template < typename T = int > using LIM = numeric_limits< T >;
template < typename T > inline istream& operator>>( istream &s, vector< T > &v ){ for ( T &t : v ) { s >> t; } return s; }
template < typename T > inline ostream& operator<<( ostream &s, const vector< T > &v ){ for ( int i = 0; i < int( v.size() ); ++i ){ s << ( " " + !i
    ) << v[i]; } return s; }
template < typename T > inline T fromString( const string &s ) { T res; istringstream iss( s ); iss >> res; return res; };
template < typename T > inline string toString( const T &a ) { ostringstream oss; oss << a; return oss.str(); };
#define REP2( i, n ) REP3( i, 0, n )
#define REP3( i, m, n ) for ( int i = ( int )( m ); i < ( int )( n ); ++i )
#define GET_REP( a, b, c, F, ... ) F
#define REP( ... ) GET_REP( __VA_ARGS__, REP3, REP2 )( __VA_ARGS__ )
#define FOR( e, c ) for ( auto &e : c )
#define ALL( c ) ( c ).begin(), ( c ).end()
#define AALL( a, t ) ( t* )a, ( t* )a + sizeof( a ) / sizeof( t )
#define DRANGE( c, p ) ( c ).begin(), ( c ).begin() + p, ( c ).end()
#define SZ( v ) ( (int)( v ).size() )
#define PB push_back
#define EM emplace
#define EB emplace_back
#define BI back_inserter
#define EXIST( c, e ) ( ( c ).find( e ) != ( c ).end() )
#define MP make_pair
#define fst first
#define snd second
#define DUMP( x ) cerr << #x << " = " << ( x ) << endl
constexpr int MOD = 1000000009;
int dp[ 256 ][ 2 ][ 2048 ];
VI solve( const string &s, const int total )
{
const int L = SZ( s );
fill( AALL( dp, int ), 0 );
dp[0][0][0] = 1;
// dp[ ][ s ] :=
REP( i, L )
{
const int D = s[i] - '0';
REP( j, 2 )
{
REP( k, total + 1 )
{
for ( int d = 0; d <= ( j ? 9 : D ); ++d )
{
( dp[ i + 1 ][ j || d < D ][ k + d ] += dp[i][j][k] ) %= MOD;
}
}
}
}
VI res;
transform( AALL( dp[L][0], int ), dp[L][1], BI( res ), plus< int >() );
transform( ALL( res ), res.begin(), bind( modulus< int >(), _1, MOD ) );
return res;
}
int main()
{
cin.tie( 0 );
ios::sync_with_stdio( false );
string s, t;
cin >> s >> t;
const int L = min( SZ( s ), SZ( t ) );
VI as = solve( s, L * 9 ), bs = solve( t, L * 9 );
LL res = 0;
REP( i, 1, L * 9 + 1 )
{
( res += LL( as[i] ) * bs[i] % MOD ) %= MOD;
}
cout << res << endl;
return 0;
}
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