#213360 (C++14) No.573 a^2[i] = a[i]

• 問題: No.573 a^2[i] = a[i]
• ユーザー: assy1028
• 提出日時: 2017-11-01 12:55:54
• 言語: C++14 (gcc 13.3.0 + boost 1.87.0)
• 結果: AC
• 実行時間: 13 ms / 2,000 ms
• コード長: 2,096 bytes
• コンパイル時間: 961 ms
• コンパイル使用メモリ: 109,512 KB
• 実行使用メモリ: 5,248 KB
• 最終ジャッジ日時: 2024-11-22 14:32:05
• 合計ジャッジ時間: 2,415 ms
• ジャッジサーバーID （参考情報）: judge5 / judge1

ファイルパターン	結果
other	AC * 47

ソースコード

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#include <algorithm>
#include <iostream>
#include <cstdio>
#include <map>
#include <numeric>
#include <cmath>
#include <set>
#include <sstream>
#include <string>
#include <vector>
#include <queue>
#include <stack>
#include <complex>
#include <string.h>
#include <unordered_set>
#include <unordered_map>
#include <bitset>
#include <iomanip>
#include <sys/time.h>
#include <tuple>
#include <random>
using namespace std;
#define endl '\n'
#define ALL(v) (v).begin(), (v).end()
#define RALL(v) (v).rbegin(), (v).rend()
#define UNIQ(v) (v).erase(unique((v).begin(), (v).end()), (v).end())
typedef long long ll;
typedef long double ld;
typedef pair<int, int> P;
typedef complex<double> comp;
typedef vector< vector<ld> > matrix;
struct pairhash {
public:
    template<typename T, typename U>
    size_t operator()(const pair<T, U> &x) const {
    size_t seed = hash<T>()(x.first);
    return hash<U>()(x.second) + 0x9e3779b9 + (seed<<6) + (seed>>2);
    }
};
const int inf = 1e9 + 9;
const ll mod = 1e9 + 7;
const double eps = 1e-8;
const double pi = acos(-1);
int n;
ll mod_pow(ll x, ll n) {
    ll res = 1;
    while (n > 0) {
        if (n & 1) res = (res * x) % mod;
        x = (x * x) % mod;
        n >>= 1;
    }
    return res;
}
ll mod_inverse(ll x) {
    return mod_pow(x, mod-2);
}
const int max_n = 100100;
ll fact[max_n];
ll fact_inv[max_n];
void calc_fact() {
    fact[0] = 1;
    for (ll i = 1; i < max_n; i++)
        fact[i] = (fact[i-1] * i) % mod;
    fact_inv[max_n-1] = mod_inverse(fact[max_n-1]);
    for (ll i = max_n-2; i >= 0; i--)
        fact_inv[i] = (fact_inv[i+1] * (i+1)) % mod;
}
ll mod_comb(ll n, ll k) {
    if (n < 0 || k < 0 || n < k) return 0;
    return (fact[n] * fact_inv[k] % mod) * fact_inv[n-k] % mod;
}
ll solve() {
    calc_fact();
    ll res = 0;
    for (int i = 0; i <= n; i++) {
        res = (res + mod_comb(n, i) * mod_pow(n-i, i) % mod) % mod;
    }
    return res;
}
void input() {
    cin >> n;
}
int main() {
    ios::sync_with_stdio(false);
    cin.tie(0);
    cout << fixed << setprecision(15);
    input();
    cout << solve() << endl;
}
 
 
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