結果
問題 | No.599 回文かい |
ユーザー |
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提出日時 | 2017-11-25 01:20:41 |
言語 | C++14 (gcc 13.3.0 + boost 1.87.0) |
結果 |
AC
|
実行時間 | 164 ms / 4,000 ms |
コード長 | 4,820 bytes |
コンパイル時間 | 1,695 ms |
コンパイル使用メモリ | 179,900 KB |
実行使用メモリ | 5,248 KB |
最終ジャッジ日時 | 2024-11-27 08:59:08 |
合計ジャッジ時間 | 2,712 ms |
ジャッジサーバーID (参考情報) |
judge5 / judge1 |
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ファイルパターン | 結果 |
---|---|
other | AC * 22 |
ソースコード
#include<bits/stdc++.h>#define rep(i,a,b) for(int i=a;i<b;i++)#define rrep(i,a,b) for(int i=a;i>=b;i--)#define fore(i,a) for(auto &i:a)#pragma GCC optimize ("-O3")using namespace std; void _main(); int main() { cin.tie(0); ios::sync_with_stdio(false); _main(); }//---------------------------------------------------------------------------------------------------template<int MOD> struct ModInt {static const int Mod = MOD; unsigned x; ModInt() : x(0) { }ModInt(signed sig) { x = sig < 0 ? sig % MOD + MOD : sig % MOD; }ModInt(signed long long sig) { x = sig < 0 ? sig % MOD + MOD : sig % MOD; }int get() const { return (int)x; }ModInt &operator+=(ModInt that) { if ((x += that.x) >= MOD) x -= MOD; return *this; }ModInt &operator-=(ModInt that) { if ((x += MOD - that.x) >= MOD) x -= MOD; return *this; }ModInt &operator*=(ModInt that) { x = (unsigned long long)x * that.x % MOD; return *this; }ModInt &operator/=(ModInt that) { return *this *= that.inverse(); }ModInt operator+(ModInt that) const { return ModInt(*this) += that; }ModInt operator-(ModInt that) const { return ModInt(*this) -= that; }ModInt operator*(ModInt that) const { return ModInt(*this) *= that; }ModInt operator/(ModInt that) const { return ModInt(*this) /= that; }ModInt inverse() const { long long a = x, b = MOD, u = 1, v = 0;while (b) { long long t = a / b; a -= t * b; std::swap(a, b); u -= t * v; std::swap(u, v); }return ModInt(u); }bool operator==(ModInt that) const { return x == that.x; }bool operator!=(ModInt that) const { return x != that.x; }ModInt operator-() const { ModInt t; t.x = x == 0 ? 0 : Mod - x; return t; }};template<int MOD> ostream& operator<<(ostream& st, const ModInt<MOD> a) { st << a.get(); return st; };template<int MOD> ModInt<MOD> operator^(ModInt<MOD> a, unsigned long long k) {ModInt<MOD> r = 1; while (k) { if (k & 1) r *= a; a *= a; k >>= 1; } return r; }typedef ModInt<1000000007> mint;typedef ModInt<1000000007> mint1;typedef ModInt<1000000009> mint2;int getrand(int l, int r) { // [l, r]static uint32_t y = time(NULL);y ^= (y << 13); y ^= (y >> 17);y ^= (y << 5);return y % (r - l + 1) + l;}struct RollingHash {int primes[10] = { 10007, 10009, 10037, 10039, 10061, 10067, 10069, 10079, 10091, 10093 };mint1 p1; mint2 p2;int n;vector<mint1> m1; vector<mint2> m2;vector<mint1> v1; vector<mint2> v2;RollingHash() {rep(i, 0, 101) { int a = getrand(0, 9); int b = getrand(0, 9); swap(primes[a], primes[b]); }p1 = primes[0], p2 = primes[1];}void init(string s, char o = 'a') {vector<int> v;fore(c, s) v.push_back(c - o);init(v);}void init(vector<int> s) {n = s.size();m1.resize(n); m2.resize(n); v1.resize(n); v2.resize(n);m1[0] = 1; m2[0] = 1;v1[0] = s[0]; v2[0] = s[0];rep(i, 1, n) {m1[i] = m1[i - 1] * p1;m2[i] = m2[i - 1] * p2;v1[i] = v1[i - 1] + m1[i] * s[i];v2[i] = v2[i - 1] + m2[i] * s[i];}}inline pair<mint1, mint2> hash(int l, int r) { // s[l..r]assert(l <= r); assert(r < n);mint1 a = v1[r];if (l) a -= v1[l - 1];a *= m1[n - 1 - r];mint2 b = v2[r];if (l) b -= v2[l - 1];b *= m2[n - 1 - r];return { a, b };}};/*---------------------------------------------------------------------------------------------------∧_∧∧_∧ (´<_` ) Welcome to My Coding Space!( ´_ゝ`) / ⌒i/ \ | |/ / ̄ ̄ ̄ ̄/ |__(__ニつ/ _/ .| .|____\/____/ (u ⊃---------------------------------------------------------------------------------------------------*/string S;int N;RollingHash rh;//---------------------------------------------------------------------------------------------------mint memo[10101];int vis[10101];mint f(int L, int R) {if (vis[L]) return memo[L];mint res = 1;if (L == R) res = 1;else if (L + 1 == R) {if (S[L] == S[R]) res = 2;else res = 1;} else {int l = L + 1, r = R - 1;while (l - 1 <= r) {if (rh.hash(L, l - 1) == rh.hash(r + 1, R)) res += f(l, r);l++;r--;}}vis[L] = 1;return memo[L] = res;}//---------------------------------------------------------------------------------------------------void _main() {cin >> S;N = S.length();rh.init(S);cout << f(0, N - 1) << endl;}