結果

問題 No.599 回文かい
ユーザー はまやんはまやん
提出日時 2017-11-25 01:20:41
言語 C++14
(gcc 13.3.0 + boost 1.87.0)
結果
AC  
実行時間 164 ms / 4,000 ms
コード長 4,820 bytes
コンパイル時間 1,695 ms
コンパイル使用メモリ 179,900 KB
実行使用メモリ 5,248 KB
最終ジャッジ日時 2024-11-27 08:59:08
合計ジャッジ時間 2,712 ms
ジャッジサーバーID
(参考情報)
judge5 / judge1
このコードへのチャレンジ
(要ログイン)
ファイルパターン 結果
other AC * 22
権限があれば一括ダウンロードができます

ソースコード

diff #
プレゼンテーションモードにする

#include<bits/stdc++.h>
#define rep(i,a,b) for(int i=a;i<b;i++)
#define rrep(i,a,b) for(int i=a;i>=b;i--)
#define fore(i,a) for(auto &i:a)
#pragma GCC optimize ("-O3")
using namespace std; void _main(); int main() { cin.tie(0); ios::sync_with_stdio(false); _main(); }
//---------------------------------------------------------------------------------------------------
template<int MOD> struct ModInt {
static const int Mod = MOD; unsigned x; ModInt() : x(0) { }
ModInt(signed sig) { x = sig < 0 ? sig % MOD + MOD : sig % MOD; }
ModInt(signed long long sig) { x = sig < 0 ? sig % MOD + MOD : sig % MOD; }
int get() const { return (int)x; }
ModInt &operator+=(ModInt that) { if ((x += that.x) >= MOD) x -= MOD; return *this; }
ModInt &operator-=(ModInt that) { if ((x += MOD - that.x) >= MOD) x -= MOD; return *this; }
ModInt &operator*=(ModInt that) { x = (unsigned long long)x * that.x % MOD; return *this; }
ModInt &operator/=(ModInt that) { return *this *= that.inverse(); }
ModInt operator+(ModInt that) const { return ModInt(*this) += that; }
ModInt operator-(ModInt that) const { return ModInt(*this) -= that; }
ModInt operator*(ModInt that) const { return ModInt(*this) *= that; }
ModInt operator/(ModInt that) const { return ModInt(*this) /= that; }
ModInt inverse() const { long long a = x, b = MOD, u = 1, v = 0;
while (b) { long long t = a / b; a -= t * b; std::swap(a, b); u -= t * v; std::swap(u, v); }
return ModInt(u); }
bool operator==(ModInt that) const { return x == that.x; }
bool operator!=(ModInt that) const { return x != that.x; }
ModInt operator-() const { ModInt t; t.x = x == 0 ? 0 : Mod - x; return t; }
};
template<int MOD> ostream& operator<<(ostream& st, const ModInt<MOD> a) { st << a.get(); return st; };
template<int MOD> ModInt<MOD> operator^(ModInt<MOD> a, unsigned long long k) {
ModInt<MOD> r = 1; while (k) { if (k & 1) r *= a; a *= a; k >>= 1; } return r; }
typedef ModInt<1000000007> mint;
typedef ModInt<1000000007> mint1;
typedef ModInt<1000000009> mint2;
int getrand(int l, int r) { // [l, r]
static uint32_t y = time(NULL);
y ^= (y << 13); y ^= (y >> 17);
y ^= (y << 5);
return y % (r - l + 1) + l;
}
struct RollingHash {
int primes[10] = { 10007, 10009, 10037, 10039, 10061, 10067, 10069, 10079, 10091, 10093 };
mint1 p1; mint2 p2;
int n;
vector<mint1> m1; vector<mint2> m2;
vector<mint1> v1; vector<mint2> v2;
RollingHash() {
rep(i, 0, 101) { int a = getrand(0, 9); int b = getrand(0, 9); swap(primes[a], primes[b]); }
p1 = primes[0], p2 = primes[1];
}
void init(string s, char o = 'a') {
vector<int> v;
fore(c, s) v.push_back(c - o);
init(v);
}
void init(vector<int> s) {
n = s.size();
m1.resize(n); m2.resize(n); v1.resize(n); v2.resize(n);
m1[0] = 1; m2[0] = 1;
v1[0] = s[0]; v2[0] = s[0];
rep(i, 1, n) {
m1[i] = m1[i - 1] * p1;
m2[i] = m2[i - 1] * p2;
v1[i] = v1[i - 1] + m1[i] * s[i];
v2[i] = v2[i - 1] + m2[i] * s[i];
}
}
inline pair<mint1, mint2> hash(int l, int r) { // s[l..r]
assert(l <= r); assert(r < n);
mint1 a = v1[r];
if (l) a -= v1[l - 1];
a *= m1[n - 1 - r];
mint2 b = v2[r];
if (l) b -= v2[l - 1];
b *= m2[n - 1 - r];
return { a, b };
}
};
/*---------------------------------------------------------------------------------------------------
           _
     _ ´<_   Welcome to My Coding Space!
     ´_` /  ⌒i
           | |
    /   //  |
  __(__ニ/  _/ .| .|____
     /____/ u 
---------------------------------------------------------------------------------------------------*/
string S;
int N;
RollingHash rh;
//---------------------------------------------------------------------------------------------------
mint memo[10101];
int vis[10101];
mint f(int L, int R) {
if (vis[L]) return memo[L];
mint res = 1;
if (L == R) res = 1;
else if (L + 1 == R) {
if (S[L] == S[R]) res = 2;
else res = 1;
} else {
int l = L + 1, r = R - 1;
while (l - 1 <= r) {
if (rh.hash(L, l - 1) == rh.hash(r + 1, R)) res += f(l, r);
l++;
r--;
}
}
vis[L] = 1;
return memo[L] = res;
}
//---------------------------------------------------------------------------------------------------
void _main() {
cin >> S;
N = S.length();
rh.init(S);
cout << f(0, N - 1) << endl;
}
הההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההה
XXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXX
0