結果

問題 No.621 3 x N グリッド上のドミノの置き方の数
ユーザー しらっ亭しらっ亭
提出日時 2017-12-01 19:02:36
言語 C++14
(gcc 13.3.0 + boost 1.87.0)
結果
AC  
実行時間 82 ms / 3,000 ms
コード長 8,733 bytes
コンパイル時間 986 ms
コンパイル使用メモリ 118,680 KB
実行使用メモリ 5,248 KB
最終ジャッジ日時 2024-11-27 22:43:34
合計ジャッジ時間 6,009 ms
ジャッジサーバーID
（参考情報） 		judge5 / judge1
このコードへのチャレンジ
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ファイルパターン 結果
sample AC * 2
other AC * 66
権限があれば一括ダウンロードができます

ソースコード

diff # 

#include <iostream>
#include <algorithm>
#include <bitset>
#include <map>
#include <queue>
#include <set>
#include <stack>
#include <string>
#include <utility>
#include <vector>
#include <array>
#include <unordered_map>
#include <complex>
#include <deque>
#include <cassert>
#include <cmath>
#include <functional>
#include <iomanip>
#include <chrono>
#include <random>
#include <numeric>
#include <tuple>
#include <cstring>
using namespace std;

#define forr(x,arr) for(auto&& x:arr)
#define _overload3(_1,_2,_3,name,...) name
#define _rep2(i,n) _rep3(i,0,n)
#define _rep3(i,a,b) for(int i=int(a);i<int(b);++i)
#define rep(...) _overload3(__VA_ARGS__,_rep3,_rep2,)(__VA_ARGS__)
#define _rrep2(i,n) _rrep3(i,0,n)
#define _rrep3(i,a,b) for(int i=int(b)-1;i>=int(a);i--)
#define rrep(...) _overload3(__VA_ARGS__,_rrep3,_rrep2,)(__VA_ARGS__)
#define all(x) (x).begin(),(x).end()
#define bit(n) (1LL<<(n))
#define sz(x) ((int)(x).size())
#define TEN(n) ((ll)(1e##n))
#define fst first
#define snd second

string DBG_DLM(int &i){return(i++==0?"":", ");}
#define DBG_B(exp){int i=0;os<<"{";{exp;}os<<"}";return os;}
template<class T>ostream&operator<<(ostream&os,vector<T>v);
template<class T>ostream&operator<<(ostream&os,set<T>v);
template<class T>ostream&operator<<(ostream&os,queue<T>q);
template<class T>ostream&operator<<(ostream&os,priority_queue<T>q);
template<class T,class K>ostream&operator<<(ostream&os,pair<T,K>p);
template<class T,class K>ostream&operator<<(ostream&os,map<T,K>mp);
template<class T,class K>ostream&operator<<(ostream&os,unordered_map<T,K>mp);
template<int I,class TPL>void DBG(ostream&os,TPL t){}
template<int I,class TPL,class H,class...Ts>void DBG(ostream&os,TPL t){os<<(I==0?"":", ")<<get<I>(t);DBG<I+1,TPL,Ts...>(os,t);}
template<class T,class K>void DBG(ostream&os,pair<T,K>p,string delim){os<<"("<<p.first<<delim<<p.second<<")";}
template<class...Ts>ostream&operator<<(ostream&os,tuple<Ts...>t){os<<"(";DBG<0,tuple<Ts...>,Ts...>(os,t);os<<")";return os;}
template<class T,class K>ostream&operator<<(ostream&os,pair<T,K>p){DBG(os,p,", ");return os;}
template<class T>ostream&operator<<(ostream&os,vector<T>v){DBG_B(forr(t,v){os<<DBG_DLM(i)<<t;});}
template<class T>ostream&operator<<(ostream&os,set<T>s){DBG_B(forr(t,s){os<<DBG_DLM(i)<<t;});}
template<class T>ostream&operator<<(ostream&os,queue<T>q){DBG_B(for(;q.size();q.pop()){os<<DBG_DLM(i)<<q.front();});}
template<class T>ostream&operator<<(ostream&os,priority_queue<T>q){DBG_B(for(;q.size();q.pop()){os<<DBG_DLM(i)<<q.top();});}
template<class T,class K>ostream&operator<<(ostream&os,map<T,K>m){DBG_B(forr(p,m){os<<DBG_DLM(i);DBG(os,p,"->");});}
template<class T,class K>ostream&operator<<(ostream&os,unordered_map<T,K>m){DBG_B(forr(p,m){os<<DBG_DLM(i);DBG(os,p,"->");});}
#define DBG_OVERLOAD(_1,_2,_3,_4,_5,_6,macro_name,...)macro_name
#define DBG_LINE(){char s[99];sprintf(s,"line:%3d | ",__LINE__);cerr<<s;}
#define DBG_OUTPUT(v){cerr<<(#v)<<"="<<(v);}
#define DBG1(v,...){DBG_OUTPUT(v);}
#define DBG2(v,...){DBG_OUTPUT(v);cerr<<", ";DBG1(__VA_ARGS__);}
#define DBG3(v,...){DBG_OUTPUT(v);cerr<<", ";DBG2(__VA_ARGS__);}
#define DBG4(v,...){DBG_OUTPUT(v);cerr<<", ";DBG3(__VA_ARGS__);}
#define DBG5(v,...){DBG_OUTPUT(v);cerr<<", ";DBG4(__VA_ARGS__);}
#define DBG6(v,...){DBG_OUTPUT(v);cerr<<", ";DBG5(__VA_ARGS__);}
#define DEBUG0(){DBG_LINE();cerr<<endl;}
#ifdef LOCAL
#define out(...){DBG_LINE();DBG_OVERLOAD(__VA_ARGS__,DBG6,DBG5,DBG4,DBG3,DBG2,DBG1)(__VA_ARGS__);cerr<<endl;}
#else
#define out(...)
#endif

using ll=long long;
using pii=pair<int,int>;using pll=pair<ll,ll>;using pil=pair<int,ll>;using pli=pair<ll,int>;
using vs=vector<string>;using vvs=vector<vs>;using vvvs=vector<vvs>;
using vb=vector<bool>;using vvb=vector<vb>;using vvvb=vector<vvb>;
using vi=vector<int>;using vvi=vector<vi>;using vvvi=vector<vvi>;
using vl=vector<ll>;using vvl=vector<vl>;using vvvl=vector<vvl>;
using vd=vector<double>;using vvd=vector<vd>;using vvvd=vector<vvd>;
using vpii=vector<pii>;using vvpii=vector<vpii>;using vvvpii=vector<vvpii>;
template<class A,class B>bool amax(A&a,const B&b){return b>a?a=b,1:0;}
template<class A,class B>bool amin(A&a,const B&b){return b<a?a=b,1:0;}
ll ri(){ll l;cin>>l;return l;} string rs(){string s;cin>>s;return s;}

const int mod = 1e9+7;
template<int MOD> struct Mint {
	int x;
	Mint() : x(0) {}
	Mint(int y) : x(y >= 0 ? y % MOD : MOD - (-y) % MOD) {}
	Mint(int64_t sll) : x(sll % MOD) { if (x < 0) x += MOD; }
	Mint &operator+=(const Mint &rhs){ if((x += rhs.x) >= MOD) x -= MOD; return *this; }
	Mint &operator-=(const Mint &rhs){ if((x += MOD - rhs.x) >= MOD) x -= MOD; return *this; }
	Mint &operator*=(const Mint &rhs){ x = 1LL*x*rhs.x % MOD; return *this; }
	Mint &operator/=(const Mint &rhs){ x = (1LL*x*rhs.inv().x) % MOD; return *this; }
	Mint operator-() const { return Mint(-x); }
	Mint operator+(const Mint &rhs) const { return Mint(*this) += rhs; }
	Mint operator-(const Mint &rhs) const { return Mint(*this) -= rhs; }
	Mint operator*(const Mint &rhs) const { return Mint(*this) *= rhs; }
	Mint operator/(const Mint &rhs) const { return Mint(*this) /= rhs; }
	bool operator<(const Mint &rhs) const { return x < rhs.x; }
	Mint inv() const {
		signed a = x, b = MOD, u = 1, v = 0, t;
		while (b) { t = a / b; a -= t * b; swap(a, b); u -= t * v; swap(u, v); }
		return Mint(u);
	}
	Mint operator^(uint64_t t) const {
		Mint e = *this, res = 1;
		for(; t; e *= e, t>>=1) if (t & 1) res *= e;
		return res;
	}
};
template<int MOD> ostream &operator<<(ostream &os, const Mint<MOD> &rhs) { return os << rhs.x; }
template<int MOD> istream &operator>>(istream &is, Mint<MOD> &rhs) { int64_t s; is >> s; rhs = Mint<MOD>(s); return is; };

using mint = Mint<mod>;
using vm=vector<mint>;using vvm=vector<vm>;using vvvm=vector<vvm>;

template <class T, int N> struct matrix_ {
	array<T, N*N> val;

	matrix_(vector<vector<T>> ini) {
		for (int i = 0; i < N; i++) for (int j = 0; j < N; j++)
			val[i * N + j] = ini[i][j];
	}

	matrix_(int d = 0) {
		for (int i = 0; i < N; i++) for (int j = 0; j < N; j++)
			val[i * N + j] = T((i == j) * d);
	}

	matrix_ operator+(const matrix_ &x) const {
		matrix_ ret;
		for (int i = 0; i < N; i++) for (int j = 0; j < N; j++) {
			ret.val[i * N + j] = val[i * N + j] + x.val[i * N + j];
		}
		return ret;
	}

	matrix_ operator*(const matrix_ &x) const {
		matrix_ ret;
		for (int i = 0; i < N; i++) for (int k = 0; k < N; k++) for (int j = 0; j < N; j++) {
			ret.val[i * N + j] += val[i * N + k] * x.val[k * N + j];
		}
		return ret;
	}

	matrix_ operator^(unsigned long long p) const {
		matrix_ ret(1);
		matrix_ x(*this);
		while (p) {
			if (p & 1) ret = ret * x;
			x = x * x;
			p >>= 1;
		}
		return ret;
	}

	T& at(int row, int col) {
		return val[row * N + col];
	}
};
using Mat = matrix_<mint, 64>;

mint solve() {
	ll n = ri();

	Mat mat;

	rep(i, bit(3)) {
		bool i0 = (i & bit(0)) != 0;
		bool i1 = (i & bit(1)) != 0;
		bool i2 = (i & bit(2)) != 0;
		rep(j, bit(3)) {
			bool j0 = (j & bit(0)) != 0;
			bool j1 = (j & bit(1)) != 0;
			bool j2 = (j & bit(2)) != 0;

			int from = (j << 3) | i;

			rep(p0, 2) {
				if (i0 && p0) continue;
				if (!j0 && !p0) continue;
				rep(p1, 2) {
					if (i1 && p1) continue;
					if (!j1 && !p1) continue;
					rep(p2, 2) {
						if (i2 && p2) continue;
						if (!j2 && !p2) continue;

						if ((i0 | p0) == 0 && (i1 | p1) == 0) continue;
						if ((i2 | p2) == 0 && (i1 | p1) == 0) continue;

						int y = (p2 << 2) + (p1 << 1) + p0;
						int x = y | i;
						int to = (x << 3) | y;
						mat.at(from, to) += 1;
					}
				}
			}

			if (!i0 && !i1) {
				if (i2) {
					int x = 3 + (1 << 2);
					int y = 0 + (0 << 2);
					int to = (x << 3) | y;
					mat.at(from, to) += 1;
				}
				else if (j2) {
					rep(p2, 2) {
						int x = 3 + (p2 << 2);
						int y = 0 + (p2 << 2);
						int to = (x << 3) | y;
						mat.at(from, to) += 1;
					}
				}
				else {
					int x = 3 + (1 << 2);
					int y = 0 + (1 << 2);
					int to = (x << 3) | y;
					mat.at(from, to) += 1;
				}
			}

			if (!i1 && !i2) {
				if (i0) {
					int x = 6 + (1 << 0);
					int y = 0 + (0 << 0);
					int to = (x << 3) | y;
					mat.at(from, to) += 1;
				}
				else if (j0) {
					rep(p2, 2) {
						int x = 6 + (p2 << 0);
						int y = 0 + (p2 << 0);
						int to = (x << 3) | y;
						mat.at(from, to) += 1;
					}
				}
				else {
					int x = 6 + (1 << 0);
					int y = 0 + (1 << 0);
					int to = (x << 3) | y;
					mat.at(from, to) += 1;
				}
			}
		}
	}

	mat = mat ^ n;	

	mint ans = 0;
	rep(j, 2, bit(3)) {
		if (j == 4) continue;
		int from = j << 3;
		ans += mat.at(56, from);
	}

	return ans;
}

void Main() {
	cout << solve() << endl;
}

signed main() {
	cin.tie(nullptr);
	ios::sync_with_stdio(false);
	Main();
	return 0;
}
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