結果
問題 |
No.586 ダブルブッキング
|
ユーザー |
![]() |
提出日時 | 2017-12-05 03:05:06 |
言語 | C++11(廃止可能性あり) (gcc 13.3.0) |
結果 |
RE
|
実行時間 | - |
コード長 | 369 bytes |
コンパイル時間 | 144 ms |
コンパイル使用メモリ | 23,552 KB |
実行使用メモリ | 5,248 KB |
最終ジャッジ日時 | 2024-11-28 07:51:35 |
合計ジャッジ時間 | 2,068 ms |
ジャッジサーバーID (参考情報) |
judge4 / judge3 |
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ファイルパターン | 結果 |
---|---|
sample | RE * 3 |
other | RE * 5 |
コンパイルメッセージ
main.cpp: In function ‘int main()’: main.cpp:11:17: warning: format ‘%d’ expects argument of type ‘int*’, but argument 2 has type ‘int’ [-Wformat=] 11 | scanf("%d\n", x); | ~^ ~ | | | | int* int main.cpp:12:17: warning: format ‘%d’ expects argument of type ‘int*’, but argument 2 has type ‘int’ [-Wformat=] 12 | scanf("%d\n", y); | ~^ ~ | | | | int* int main.cpp:13:17: warning: format ‘%d’ expects argument of type ‘int*’, but argument 2 has type ‘int’ [-Wformat=] 13 | scanf("%d\n", z); | ~^ ~ | | | | int* int main.cpp:18:25: warning: format ‘%d’ expects argument of type ‘int*’, but argument 2 has type ‘int’ [-Wformat=] 18 | scanf("%d\n", p[i]); | ~^ ~~~~ | | | | int* int main.cpp:11:14: warning: ignoring return value of ‘int scanf(const char*, ...)’ declared with attribute ‘warn_unused_result’ [-Wunused-result] 11 | scanf("%d\n", x); | ~~~~~^~~~~~~~~~~ main.cpp:12:14: warning: ignoring return value of ‘int scanf(const char*, ...)’ declared with attribute ‘warn_unused_result’ [-Wunused-result] 12 | scanf("%d\n", y); | ~~~~~^~~~~~~~~~~ main.cpp:13:14: warning: ignoring return value of ‘int scanf(const char*, ...)’ declared with attribute ‘warn_unused_result’ [-Wunused-result] 13 | scanf("%d\n", z); | ~~~~~^~~~~~~~~~~ main.cpp:18:22: warning: ignoring return value of ‘int scanf(const char*, ...)’ declared with attribute ‘warn_unused_result’ [-Wunused-result] 18 | scanf("%d\n", p[i]); | ~~~~~^~~~~~~~~~~~~
ソースコード
#include <stdio.h> #include <stdlib.h> int main() { int x,y,z; int *p; int i = 0; int sum = 0; scanf("%d\n", x); scanf("%d\n", y); scanf("%d\n", z); p = (int*)malloc(sizeof(int) * z); while(i < z){ scanf("%d\n", p[i]); i++; } i = 0; while(i < z){ if(p[i] == p[i + 1]){ sum += 1; } i++; } printf("%d\n", sum * (x + y)); return (0); }