結果
問題 | No.611 Day of the Mountain |
ユーザー | Sebastian King |
提出日時 | 2017-12-11 01:19:20 |
言語 | C++11 (gcc 11.4.0) |
結果 |
WA
(最新)
AC
(最初)
|
実行時間 | - |
コード長 | 1,875 bytes |
コンパイル時間 | 1,307 ms |
コンパイル使用メモリ | 159,540 KB |
実行使用メモリ | 13,772 KB |
最終ジャッジ日時 | 2024-11-30 11:31:31 |
合計ジャッジ時間 | 2,855 ms |
ジャッジサーバーID (参考情報) |
judge1 / judge3 |
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テストケース
テストケース表示入力 | 結果 | 実行時間 実行使用メモリ |
---|---|---|
testcase_00 | WA | - |
testcase_01 | WA | - |
testcase_02 | RE | - |
testcase_03 | RE | - |
testcase_04 | RE | - |
testcase_05 | RE | - |
testcase_06 | AC | 5 ms
12,744 KB |
testcase_07 | AC | 3 ms
13,772 KB |
testcase_08 | WA | - |
testcase_09 | RE | - |
testcase_10 | RE | - |
testcase_11 | RE | - |
コンパイルメッセージ
main.cpp: In function ‘ll upd(ll&, ll)’: main.cpp:19:1: warning: no return statement in function returning non-void [-Wreturn-type] 19 | } | ^ main.cpp: In function ‘int main()’: main.cpp:42:18: warning: format ‘%d’ expects argument of type ‘int’, but argument 2 has type ‘ll’ {aka ‘long long int’} [-Wformat=] 42 | printf("%d\n", d[n][m]); | ~^ ~~~~~~~ | | | | int ll {aka long long int} | %lld main.cpp:22:14: warning: ignoring return value of ‘int scanf(const char*, ...)’ declared with attribute ‘warn_unused_result’ [-Wunused-result] 22 | scanf("%d%d", &n, &m); | ~~~~~^~~~~~~~~~~~~~~~ main.cpp:24:22: warning: ignoring return value of ‘int scanf(const char*, ...)’ declared with attribute ‘warn_unused_result’ [-Wunused-result] 24 | scanf("%s", s + 1); | ~~~~~^~~~~~~~~~~~~
ソースコード
#include<bits/stdc++.h> using namespace std; typedef long long ll; const int MM = 201712111; const int MAXN = 2000 + 10; int n, m; int a[MAXN][MAXN]; ll d[MAXN][MAXN]; const ll INF = 1ll << 60; char s[MAXN]; ll f[20][131072]; ll upd(ll &x, ll y){ x = (x + y) % MM; } int main(){ scanf("%d%d", &n, &m); for (int i = 1; i <= n; i++){ scanf("%s", s + 1); for (int j = 1; j <= m; j++) a[i][j] = ((s[j] == '?') ? 0 : (s[j] - '0')); } if (m >= 18){ for (int i = 1; i <= m; i++) for (int j = i + 1; j <= m; j++) swap(a[i][j], a[j][i]); swap(n, m); } for (int i = 0; i <= n; i++) for (int j = 0; j <= m; j++) d[i][j] = INF; d[1][1] = (a[1][1] == 0) + a[1][1]; for (int i = 1; i <= n; i++) for (int j = 1; j <= m; j++) if (i != 1 || j != 1) d[i][j] = min(d[i-1][j], d[i][j-1]) + a[i][j] + (a[i][j] == 0); printf("%d\n", d[n][m]); if (m == 1){ puts("1"); return 0; } int o = 1 << m; for (int i = 0; i < o; i++) f[1][i] = 0; f[1][1] = 1; int oo = o - 1; for (int cnt = 2; cnt <= n * m; cnt++){ int x = (cnt - 1) / m + 1; int y = (cnt - 1) % m + 1; int py = (y == 1 ? m : y - 1); for (int i = 0; i < o; i++) f[y][i] = 0; if (a[x][y] == 0){ for (int i = 0; i < o; i++){ if ((d[x-1][y]+1==d[x][y] && ((i >> (y - 1)) & 1)) || (d[x][y-1]+1==d[x][y] && ((i >> (y - 2)) & 1))) upd(f[y][i|(1<<(y-1))], f[py][i]), upd(f[y][i&(oo^(1<<(y-1)))], f[py][i]*8); else upd(f[y][i&(oo^(1<<(y-1)))], f[py][i]*9); } } else{ for (int i = 0; i < o; i++){ if ((d[x-1][y]+a[x][y]==d[x][y] && ((i >> (y - 1)) & 1)) || (d[x][y-1]+a[x][y]==d[x][y] && ((i >> (y - 2)) & 1))) upd(f[y][i|(1<<(y-1))], f[py][i]); else upd(f[y][i&(oo^(1<<(y-1)))], f[py][i]); } } } ll ans = 0; for (int i = 0; i < o; i++) if ((i >> (m - 1))) upd(ans, f[m][i]); printf("%lld\n", ans); return 0; }