結果

問題 No.620 ぐるぐるぐるりん
ユーザー rickythetarickytheta
提出日時 2017-12-20 11:34:26
言語 C++11
(gcc 13.3.0)
結果
AC  
実行時間 16 ms / 1,000 ms
コード長 2,575 bytes
コンパイル時間 1,478 ms
コンパイル使用メモリ 162,548 KB
実行使用メモリ 5,376 KB
最終ジャッジ日時 2024-06-13 02:03:38
合計ジャッジ時間 3,558 ms
ジャッジサーバーID
(参考情報)
judge3 / judge4
このコードへのチャレンジ
(要ログイン)
ファイルパターン 結果
sample AC * 3
other AC * 28
権限があれば一括ダウンロードができます
コンパイルメッセージ
main.cpp: In function ‘void solve()’:
main.cpp:29:8: warning: ignoring return value of ‘int scanf(const char*, ...)’ declared with attribute ‘warn_unused_result’ [-Wunused-result]
   29 |   scanf("%d%Lf%Lf%Lf%Lf%Lf",&t,&p,&omega,&v,&gx,&gy);
      |   ~~~~~^~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
main.cpp: In function ‘int main()’:
main.cpp:105:8: warning: ignoring return value of ‘int scanf(const char*, ...)’ declared with attribute ‘warn_unused_result’ [-Wunused-result]
  105 |   scanf("%d",&n);
      |   ~~~~~^~~~~~~~~

ソースコード

diff #
プレゼンテーションモードにする

#include <bits/stdc++.h>
using namespace std;
typedef int _loop_int;
#define REP(i,n) for(_loop_int i=0;i<(_loop_int)(n);++i)
#define FOR(i,a,b) for(_loop_int i=(_loop_int)(a);i<(_loop_int)(b);++i)
#define FORR(i,a,b) for(_loop_int i=(_loop_int)(b)-1;i>=(_loop_int)(a);--i)
#define DEBUG(x) cout<<#x<<": "<<x<<endl
#define DEBUG_VEC(v) cout<<#v<<":";REP(i,v.size())cout<<" "<<v[i];cout<<endl
#define double long double
int t;
double p;
double omega, v;
double gx, gy;
int m;
double B[2][35];
double b[35];
double A[2][2];
double Ainv[2][2];
double xy[2];
double z[35];
void solve(){
scanf("%d%Lf%Lf%Lf%Lf%Lf",&t,&p,&omega,&v,&gx,&gy);
vector<double> vx, vy;
REP(i,t){
double x = 1.0, y = 0.0;
FOR(j,i+1,t){
double nx = x - omega*y + v*x;
double ny = y + omega*x + v*y;
x = nx;
y = ny;
}
vx.push_back(x);
vy.push_back(y);
x = 0.0, y = 1.0;
FOR(j,i+1,t){
double nx = x - omega*y + v*x;
double ny = y + omega*x + v*y;
x = nx;
y = ny;
}
vx.push_back(x);
vy.push_back(y);
}
double sx = 1.0, sy = 0.0;
REP(i,t){
double nx = sx - omega*sy + v*sx;
double ny = sy + omega*sx + v*sy;
sx = nx;
sy = ny;
}
double ax = gx-sx, ay = gy-sy;
// problem. sum p_i vx_i == ax
// sum p_i vy_i == ay
// sum p_i^2 <= p
// minimize. sum p_i^2
// subject to. sum p_i vx_i == ax
// sum p_i vy_i == ay
m = 2*t;
// Bx = b
REP(i,2)REP(j,m)B[i][j] = 0.0;
REP(i,m)B[0][i] = vx[i];
REP(i,m)B[1][i] = vy[i];
b[0] = ax;
b[1] = ay;
// A = BB^T
REP(i,2)REP(j,2)A[i][j] = 0.0;
REP(i,2)REP(j,2)REP(k,m)A[i][j] += B[i][k] * B[j][k];
// Ay = b
double detA = A[0][0] * A[1][1] - A[0][1] * A[1][0];
Ainv[0][0] = A[1][1] / detA;
Ainv[0][1] = -A[0][1] / detA;
Ainv[1][0] = -A[1][0] / detA;
Ainv[1][1] = A[0][0] / detA;
// y = Ainv b
xy[0] = Ainv[0][0] * b[0] + Ainv[0][1] * b[1];
xy[1] = Ainv[1][0] * b[0] + Ainv[1][1] * b[1];
// z = A^T y
REP(i,m)z[i] = B[0][i] * xy[0] + B[1][i] * xy[1];
// simulate
double simx = 1.0, simy = 0.0;
double power = 0.0;
REP(i,t){
double ux = z[2*i], uy = z[2*i+1];
printf("%.40Lf %.40Lf\n", ux, uy);
power += ux*ux + uy*uy;
double nx = simx - omega*simy + v*simx + ux;
double ny = simy + omega*simx + v*simy + uy;
simx = nx;
simy = ny;
}
// printf("(%.5f, %.5f) is goal, (%.5f, %.5f) is answer, power is %.5f(<= %.5f)\n", gx, gy, simx, simy, power, p);
}
int main(){
int n;
scanf("%d",&n);
while(n--)solve();
return 0;
}
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