結果
問題 | No.623 fudan no modulus to tigau |
ユーザー |
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提出日時 | 2017-12-24 13:03:10 |
言語 | C++14 (gcc 13.3.0 + boost 1.87.0) |
結果 |
AC
|
実行時間 | 2 ms / 2,000 ms |
コード長 | 2,042 bytes |
コンパイル時間 | 1,802 ms |
コンパイル使用メモリ | 170,716 KB |
実行使用メモリ | 6,820 KB |
最終ジャッジ日時 | 2024-12-17 18:32:20 |
合計ジャッジ時間 | 2,188 ms |
ジャッジサーバーID (参考情報) |
judge3 / judge4 |
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ファイルパターン | 結果 |
---|---|
sample | AC * 2 |
other | AC * 12 |
ソースコード
#include "bits/stdc++.h"using namespace std;#define DEBUG(x) cout<<#x<<": "<<x<<endl;#define DEBUG_VEC(v) cout<<#v<<":";for(int i=0;i<v.size();i++) cout<<" "<<v[i]; cout<<endltypedef long long ll;#define vi vector<int>#define vl vector<ll>#define vii vector< vector<int> >#define vll vector< vector<ll> >#define vs vector<string>#define pii pair<int,int>#define pis pair<int,string>#define psi pair<string,int>#define pll pair<ll,ll>const int inf = 1000000001;const ll INF = 2e18 * 2;#define MOD 1000000007#define mod 1000000009#define pi 3.14159265358979323846#define Sp(p) cout<<setprecision(15)<< fixed<<p<<endl;int dx[4] = { 1,0,-1,0 }, dy[4] = { 0,1,0,-1 };int dx2[8] = { 1,1,0,-1,-1,-1,0,1 }, dy2[8] = { 0,1,1,1,0,-1,-1,-1 };struct Modint {ll n;static const ll Mod = 998244353;Modint(int n = 0) : n(n) {}};Modint operator+(Modint a, Modint b) { return Modint((a.n += b.n) >= mod ? a.n - a.Mod : a.n); }Modint operator-(Modint a, Modint b) { return Modint((a.n -= b.n) < 0 ? a.n + a.Mod : a.n); }Modint operator*(Modint a, Modint b) { return Modint(1LL * a.n * b.n % a.Mod); }Modint &operator+=(Modint &a, Modint b) { return a = a + b; }Modint &operator-=(Modint &a, Modint b) { return a = a - b; }Modint &operator*=(Modint &a, Modint b) { return a = a * b; }int n;vector<Modint> memo(51);vi t(51), a(51), b(51);Modint f(int i, Modint x) {if (memo[i].n >= 0) {return memo[i];}else {if (t[i] == 1) {memo[i] = f(a[i], x) + f(b[i], x);return f(a[i], x) + f(b[i], x);}else if (t[i] == 2) {memo[i] = Modint(a[i]) * f(b[i], x);return Modint(a[i]) * f(b[i], x);}else {memo[i] = f(a[i], x)*f(b[i], x);return f(a[i], x)*f(b[i], x);}}}int main() {int i, j;cin >> n;for (i = 2; i <= n; i++) {cin >> t[i] >> a[i] >> b[i];}int q;cin >> q;for (int unko = 0; unko < q; unko++) {fill(memo.begin(), memo.end(), Modint(-1));int x;cin >> x;memo[0] = Modint(1);memo[1] = Modint(x);cout << f(n, Modint(x)).n << endl;}}