結果

問題 No.195 フィボナッチ数列の理解(2)
ユーザー 古寺いろは
提出日時 2015-04-26 23:32:37
言語 C++11
(gcc 13.3.0)
結果
WA  
実行時間 -
コード長 2,087 bytes
コンパイル時間 1,972 ms
コンパイル使用メモリ 165,172 KB
実行使用メモリ 6,948 KB
最終ジャッジ日時 2024-07-05 02:28:08
合計ジャッジ時間 2,912 ms
ジャッジサーバーID
（参考情報） 		judge2 / judge4
このコードへのチャレンジ
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ファイルパターン 結果
sample AC * 1 WA * 2
other AC * 5 WA * 17
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ソースコード

diff #
プレゼンテーションモードにする

#include "bits/stdc++.h"
using namespace std;
#define T 50
#define MAX 1000000001
long long A[T];
long long B[T];
long long ansA = MAX;
long long ansB = MAX;
int main() {
    A[0] = 1;
    B[1] = 1;
    for (int i = 2; i < T; i++)
    {
        A[i] = A[i - 1] + A[i - 2];
        B[i] = B[i - 1] + B[i - 2];
    }
    vector<long long> num(3);
    cin >> num[0] >> num[1] >> num[2];
    sort(num.begin(), num.end());
    if (num[0] == num[1] && num[1] == num[2]){
        ansA = 1;
        ansB = num[0];
    }
    if (num[0] == num[1] || num[1] == num[2]){
        int tempA = num[0];
        int tempB = num[2];
        if (tempA > tempB) swap(tempA, tempB);
        if (ansA > tempA || (ansA == tempA && ansB > tempB)){
            ansA = tempA;
            ansB = tempB;
        }
    }
    
    for (int i = 0; i < T; i++)
    {
        if (A[i] + B[i] > num[0]) continue;
        for (int j = i; j < T; j++)
        {
            if (A[j] + B[j] > num[1]) continue;
            for (int k = j; k < T; k++)
            {
                if (A[k] + B[k] > num[2]) continue;
                if (A[k] == 0 || B[k] == 0) continue;
                double lowa = 0;
                double higha = num[2] / A[k] + 1;
                if (lowa > higha) continue;
                for (int l = 0; l < 100; l++)
                {
                    double a1 = (lowa + lowa + higha) / 3;
                    double a2 = (lowa + higha + higha) / 3;
                    double b1 = (num[2] - a1 * A[k]) / B[k];
                    double b2 = (num[2] - a2 * A[k]) / B[k];
                    double diff1 = 0;
                    double diff2 = 0;
                    diff1 += abs(num[0] - (a1 * A[i] + b1 * B[i]));
                    diff1 += abs(num[1] - (a1 * A[j] + b1 * B[j]));
                    diff2 += abs(num[0] - (a2 * A[i] + b2 * B[i]));
                    diff2 += abs(num[1] - (a2 * A[j] + b2 * B[j]));
                    if (diff1 < diff2) higha = a2;
                    else lowa = a1;
                }
                int ta = (int)(lowa + 0.5);
                for (int a = max(ta - 10, 1); a <= ta + 10; a++){
                    int b = (num[2] - a * A[k]) / B[k];
                    if (b <= 0) continue;
                    if (num[0] != a * A[i] + b * B[i]) continue;
                    if (num[1] != a * A[j] + b * B[j]) continue;
                    if (a <= 0) continue;
                    if (ansA > a || (ansA == a && ansB > b)){
                        ansA = a;
                        ansB = b;
                    }
                }
            }
        }
    }
    cout << -1 << endl;
    //if (ansA == MAX) cout << -1 << endl;
    //else cout << ansA << " " <<  ansB << endl;
}
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