結果
問題 | No.618 labo-index |
ユーザー |
|
提出日時 | 2018-01-13 10:51:21 |
言語 | D (dmd 2.109.1) |
結果 |
AC
|
実行時間 | 902 ms / 6,000 ms |
コード長 | 2,464 bytes |
コンパイル時間 | 1,121 ms |
コンパイル使用メモリ | 128,512 KB |
実行使用メモリ | 11,008 KB |
最終ジャッジ日時 | 2024-06-12 23:33:55 |
合計ジャッジ時間 | 19,370 ms |
ジャッジサーバーID (参考情報) |
judge3 / judge1 |
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ファイルパターン | 結果 |
---|---|
sample | AC * 4 |
other | AC * 35 |
ソースコード
import std.stdio, std.array, std.string, std.conv, std.algorithm;import std.typecons, std.range, std.random, std.math, std.container;import std.numeric, std.bigint, core.bitop;void main() {auto Q = readln.chomp.to!int;auto queries = new Tuple!(int, long)[](Q);long[] nums;int[long] comp;long offset;foreach (i; 0..Q) {auto s = readln.split;auto t = s[0].to!int;auto x = s[1].to!long;queries[i] = tuple(t, x);if (t == 1) {nums ~= x-offset;} else if (t == 3) {offset += x;}}nums.sort();foreach (i, e ; nums.enumerate) {comp[e] = i.to!int;}auto st = new SegmentTree(nums.length.to!int);offset = 0;long[] L;foreach (q; queries) {auto t = q[0];auto x = q[1];if (t == 1) {L ~= x - offset;st.add(comp[x-offset], 1);} else if (t == 2) {st.add(comp[L[x.to!int-1]], -1);} else {offset += x;}long hi = 10L^^5+1;long lo = 0;while (hi - lo > 1) {auto mid = (hi + lo) / 2;auto lb = nums.assumeSorted.upperBound(mid-offset-1);auto cnt = lb.empty ? 0 : st.sum(comp[lb.front], nums.length.to!int-1);if (cnt >= mid) lo = mid;else hi = mid;}max(0, lo).writeln;}}class SegmentTree {int[] table;int size;this(int n) {assert(bsr(n) < 29);size = 1 << (bsr(n) + 2);table = new int[](size);}void add(int pos, int num) {return add(pos, num, 0, 0, size/2-1);}void add(int pos, int num, int i, int left, int right) {table[i] += num;if (left == right)return;auto mid = (left + right) / 2;if (pos <= mid)add(pos, num, i*2+1, left, mid);elseadd(pos, num, i*2+2, mid+1, right);}int sum(int pl, int pr) {return sum(pl, pr, 0, 0, size/2-1);}int sum(int pl, int pr, int i, int left, int right) {if (pl > right || pr < left)return 0;else if (pl <= left && right <= pr)return table[i];elsereturnsum(pl, pr, i*2+1, left, (left+right)/2) +sum(pl, pr, i*2+2, (left+right)/2+1, right);}}