結果
問題 | No.269 見栄っ張りの募金活動 |
ユーザー |
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提出日時 | 2018-01-17 21:28:29 |
言語 | C++11 (gcc 13.3.0) |
結果 |
AC
|
実行時間 | 45 ms / 5,000 ms |
コード長 | 2,208 bytes |
コンパイル時間 | 674 ms |
コンパイル使用メモリ | 86,436 KB |
実行使用メモリ | 13,480 KB |
最終ジャッジ日時 | 2024-07-16 01:59:46 |
合計ジャッジ時間 | 1,685 ms |
ジャッジサーバーID (参考情報) |
judge5 / judge2 |
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ファイルパターン | 結果 |
---|---|
sample | AC * 3 |
other | AC * 22 |
ソースコード
#include <iostream>#include <sstream>#include <cstdio>#include <cstdlib>#include <cmath>#include <ctime>#include <cstring>#include <string>#include <vector>#include <stack>#include <queue>#include <deque>#include <map>#include <set>#include <bitset>#include <numeric>#include <utility>#include <iomanip>#include <algorithm>#include <functional>using namespace std;#define COUT(x) cout << #x << " = " << (x) << " (L" << __LINE__ << ")" << endl#define EACH(i, s) for (__typeof__((s).begin()) i = (s).begin(); i != (s).end(); ++i)template<class T> inline bool chmax(T& a, T b) { if (a < b) { a = b; return 1; } return 0; }template<class T> inline bool chmin(T& a, T b) { if (a > b) { a = b; return 1; } return 0; }template<class T1, class T2> ostream& operator << (ostream &s, pair<T1,T2> P){ return s << '<' << P.first << ", " << P.second << '>'; }template<class T> ostream& operator << (ostream &s, vector<T> P){ for (int i = 0; i < P.size(); ++i) { if (i > 0) { s << " "; } s << P[i]; } return s; }template<class T> ostream& operator << (ostream &s, vector<vector<T> > P){ for (int i = 0; i < P.size(); ++i) { s << endl << P[i]; } return s << endl; }template<class T1, class T2> ostream& operator << (ostream &s, map<T1,T2> P){ EACH(it, P) { s << "<" << it->first << "->" << it->second << "> "; } return s << endl; }const int MOD = 1000000007;const int MAX_N = 21000;const int MAX_K = 110;int PartNum[MAX_N + 1][MAX_K + 1];void initPartNum() {for (int n = 0; n <= MAX_N; ++n)for (int k = 0; k <= MAX_K; ++k)PartNum[n][k] = -1;}int calcPartNum(int n, int k) {if (n == 0 && k == 0) return 1;if (n < 0 || k <= 0) return 0;if (PartNum[n][k] != -1) return PartNum[n][k];PartNum[n][k] = 0;PartNum[n][k] += calcPartNum(n, k-1);PartNum[n][k] += calcPartNum(n-k, k);if (PartNum[n][k] >= MOD) PartNum[n][k] -= MOD;return PartNum[n][k];}int N, S, K;int main() {initPartNum();while (cin >> N >> S >> K) {int n = S - N*(N - 1) / 2 * K;int k = N;cout << calcPartNum(n, k) << endl;}}/*int N, M, S;// k = N2, n = S - k(k+1)/2, m = M-kint main() {initPartNum();while (cin >> N >> M >> S) {int k =}}*/