結果
問題 | No.705 ゴミ拾い Hard |
ユーザー | はむこ |
提出日時 | 2018-01-30 21:21:41 |
言語 | C++11 (gcc 11.4.0) |
結果 |
TLE
|
実行時間 | - |
コード長 | 10,479 bytes |
コンパイル時間 | 1,629 ms |
コンパイル使用メモリ | 176,984 KB |
実行使用メモリ | 19,668 KB |
最終ジャッジ日時 | 2024-06-09 11:53:13 |
合計ジャッジ時間 | 5,664 ms |
ジャッジサーバーID (参考情報) |
judge3 / judge2 |
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テストケース
テストケース表示入力 | 結果 | 実行時間 実行使用メモリ |
---|---|---|
testcase_00 | AC | 1 ms
10,624 KB |
testcase_01 | AC | 1 ms
5,376 KB |
testcase_02 | AC | 1 ms
5,376 KB |
testcase_03 | AC | 2 ms
5,376 KB |
testcase_04 | AC | 2 ms
5,376 KB |
testcase_05 | AC | 2 ms
5,376 KB |
testcase_06 | AC | 1 ms
5,376 KB |
testcase_07 | AC | 1 ms
5,376 KB |
testcase_08 | AC | 2 ms
5,376 KB |
testcase_09 | AC | 1 ms
5,376 KB |
testcase_10 | AC | 1 ms
5,376 KB |
testcase_11 | AC | 1 ms
5,376 KB |
testcase_12 | AC | 1 ms
5,376 KB |
testcase_13 | AC | 2 ms
5,376 KB |
testcase_14 | AC | 6 ms
5,376 KB |
testcase_15 | AC | 5 ms
5,376 KB |
testcase_16 | AC | 5 ms
5,376 KB |
testcase_17 | AC | 5 ms
5,376 KB |
testcase_18 | AC | 5 ms
5,376 KB |
testcase_19 | AC | 5 ms
5,376 KB |
testcase_20 | AC | 5 ms
5,376 KB |
testcase_21 | AC | 5 ms
5,376 KB |
testcase_22 | AC | 5 ms
5,376 KB |
testcase_23 | AC | 5 ms
5,376 KB |
testcase_24 | TLE | - |
testcase_25 | -- | - |
testcase_26 | -- | - |
testcase_27 | -- | - |
testcase_28 | -- | - |
testcase_29 | -- | - |
testcase_30 | -- | - |
testcase_31 | -- | - |
testcase_32 | -- | - |
testcase_33 | -- | - |
testcase_34 | -- | - |
testcase_35 | -- | - |
testcase_36 | -- | - |
testcase_37 | -- | - |
testcase_38 | -- | - |
testcase_39 | -- | - |
testcase_40 | -- | - |
testcase_41 | -- | - |
testcase_42 | -- | - |
testcase_43 | -- | - |
ソースコード
#include <bits/stdc++.h> #include <sys/time.h> using namespace std; #define rep(i,n) for(long long i = 0; i < (long long)(n); i++) #define repi(i,a,b) for(long long i = (long long)(a); i < (long long)(b); i++) #define pb push_back #define all(x) (x).begin(), (x).end() #define fi first #define se second #define mt make_tuple #define mp make_pair #define ZERO(a) memset(a,0,sizeof(a)) template<class T1, class T2> bool chmin(T1 &a, T2 b) { return b < a && (a = b, true); } template<class T1, class T2> bool chmax(T1 &a, T2 b) { return a < b && (a = b, true); } #define exists find_if #define forall all_of using ll = long long; using vll = vector<ll>; /*using vvll = vector<vll>;*/ using P = pair<ll, ll>; using ld = long double; using vld = vector<ld>; using vi = vector<int>; using vvi = vector<vi>; vll conv(vi& v) { vll r(v.size()); rep(i, v.size()) r[i] = v[i]; return r; } using vvll = vector<vector<ll>>; static const double EPS = 1e-14; static const long long INF = 1e18; static const long long mo = 1e9+7; #define ldout fixed << setprecision(40) inline void input(int &v){ v=0;char c=0;int p=1; while(c<'0' || c>'9'){if(c=='-')p=-1;c=getchar();} while(c>='0' && c<='9'){v=(v<<3)+(v<<1)+c-'0';c=getchar();} v*=p; } template <typename T, typename U> ostream &operator<<(ostream &o, const pair<T, U> &v) { o << "(" << v.first << ", " << v.second << ")"; return o; } template<size_t...> struct seq{}; template<size_t N, size_t... Is> struct gen_seq : gen_seq<N-1, N-1, Is...>{}; template<size_t... Is> struct gen_seq<0, Is...> : seq<Is...>{}; template<class Ch, class Tr, class Tuple, size_t... Is> void print_tuple(basic_ostream<Ch,Tr>& os, Tuple const& t, seq<Is...>){ using s = int[]; (void)s{0, (void(os << (Is == 0? "" : ", ") << get<Is>(t)), 0)...}; } template<class Ch, class Tr, class... Args> auto operator<<(basic_ostream<Ch, Tr>& os, tuple<Args...> const& t) -> basic_ostream<Ch, Tr>& { os << "("; print_tuple(os, t, gen_seq<sizeof...(Args)>()); return os << ")"; } template <typename T> ostream &operator<<(ostream &o, const vector<T> &v) { o << '['; rep(i, v.size()) o << v[i] << (i != v.size()-1 ? ", " : ""); o << "]"; return o; } template <typename T> ostream &operator<<(ostream &o, const set<T> &m) { o << '['; for (auto it = m.begin(); it != m.end(); it++) o << *it << (next(it) != m.end() ? ", " : ""); o << "]"; return o; } template <typename T> ostream &operator<<(ostream &o, const unordered_set<T> &m) { o << '['; for (auto it = m.begin(); it != m.end(); it++) o << *it << (next(it) != m.end() ? ", " : ""); o << "]"; return o; } template <typename T, typename U> ostream &operator<<(ostream &o, const map<T, U> &m) { o << '['; for (auto it = m.begin(); it != m.end(); it++) o << *it << (next(it) != m.end() ? ", " : ""); o << "]"; return o; } template <typename T, typename U, typename V> ostream &operator<<(ostream &o, const unordered_map<T, U, V> &m) { o << '['; for (auto it = m.begin(); it != m.end(); it++) o << *it; o << "]"; return o; } vector<int> range(const int x, const int y) { vector<int> v(y - x + 1); iota(v.begin(), v.end(), x); return v; } template <typename T> istream& operator>>(istream& i, vector<T>& o) { rep(j, o.size()) i >> o[j]; return i;} string bits_to_string(ll input, ll n=64) { string s; rep(i, n) s += '0' + !!(input & (1ll << i)); reverse(all(s)); return s; } template <typename T> ostream &operator<<(ostream &o, const priority_queue<T> &v) { auto tmp = v; while (tmp.size()) { auto x = tmp.top(); tmp.pop(); o << x << " ";} o << endl; return o; } template <typename T> unordered_map<T, ll> counter(vector<T> vec){unordered_map<T, ll> ret; for (auto&& x : vec) ret[x]++; return ret;}; string substr(string s, P x) {return s.substr(x.fi, x.se - x.fi); } size_t random_seed; namespace std { using argument_type = P; template<> struct hash<argument_type> { size_t operator()(argument_type const& x) const { size_t seed = random_seed; seed ^= hash<ll>{}(x.fi); seed ^= (hash<ll>{}(x.se) << 1); return seed; } }; }; // hash for various class namespace myhash{ const int Bsizes[]={3,9,13,17,21,25,29,33,37,41,45,49,53,57,61,65,69,73,77,81}; const int xor_nums[]={0x100007d1,0x5ff049c9,0x14560859,0x07087fef,0x3e277d49,0x4dba1f17,0x709c5988,0x05904258,0x1aa71872,0x238819b3,0x7b002bb7,0x1cf91302,0x0012290a,0x1083576b,0x76473e49,0x3d86295b,0x20536814,0x08634f4d,0x115405e8,0x0e6359f2}; const int hash_key=xor_nums[rand()%20]; const int mod_key=xor_nums[rand()%20]; template <typename T> struct myhash{ std::size_t operator()(const T& val) const { return (hash<T>{}(val)%mod_key)^hash_key; } }; }; template <typename T> class uset:public std::unordered_set<T,myhash::myhash<T>> { using SET=std::unordered_set<T,myhash::myhash<T>>; public: uset():SET(){SET::rehash(myhash::Bsizes[rand()%20]);} }; uint32_t randxor() { static uint32_t x=1+(uint32_t)random_seed,y=362436069,z=521288629,w=88675123; uint32_t t; t=(x^(x<<11));x=y;y=z;z=w; return( w=(w^(w>>19))^(t^(t>>8)) ); } struct timeval start; double sec() { struct timeval tv; gettimeofday(&tv, NULL); return (tv.tv_sec - start.tv_sec) + (tv.tv_usec - start.tv_usec) * 1e-6; } struct init_{init_(){ gettimeofday(&start, NULL); ios::sync_with_stdio(false); cin.tie(0); struct timeval myTime; struct tm *time_st; gettimeofday(&myTime, NULL); time_st = localtime(&myTime.tv_sec); srand(myTime.tv_usec); random_seed = RAND_MAX / 2 + rand() / 2; }} init__; #define rand randxor ll n; vector<ll> a, x, y; // 状態1<=j<=nの確定のときに、状態0<=k<iからの遷移kを選ぶ時のコスト ll w_QuadrangleInequality(ll k, ll j) { assert(1<=j&&j<=n); assert(0<=k&&k<j); // 点P, Qがそれぞれn個ある。 // 点P_i = (a[k], 0) // 点Q_i = (x[k], y[i]) // // この時、cost[i][j] = 点P_iと点Q_iの二乗距離 // cost[i][j]は順QIを満たすことが知られている // return ((a[j-1]-x[k])*(a[j-1]-x[k]) + y[k]*y[k]); return abs(a[j-1]-x[k])*abs(a[j-1]-x[k])*abs(a[j-1]-x[k]) + abs(y[k])*abs(y[k])*abs(y[k]); } using func_t = function<ll(ll, ll)>; bool isQuadrangleInequality(func_t w) { repi(i, 1, n+1) repi(j, 1, n+1) rep(k, n) repi(l, k, n) if (i < l && j < k && i < k && j < l && i <= j && j <= k && k <= l) { if (w(i, l) + w(j, k) >= w(i, k) + w(j, l)) { } else { cout << i << " " << j << " " << k << " " << l << " " << "HIT" << endl; return 0; } } return 1; } ll solveBrutal(ll dp0, func_t w) { vector<ll> dp(n+1, INF); dp[0] = dp0; repi(i, 1, n+1) { rep(j, i) { chmin(dp[i], dp[j] + w(j, i)); } } // cout << dp <<"Brutal"<< endl; return dp[n]; } // Zvi Galil; Raffaele Giancarlo, "Speeding up dynamic programming with applications to molecular biology", 1987 // D. Eppstein, Z. Galil, and R. Giancalco: "Speeding up Dynamic Programming", 29th IEEE Symposium on Foundations of Computer Science, White Plains, New York, pp. 488-496, 1988. // // dp[j] = min_{0 <= k < j} (dp[k] + w(k, j)) (0 <= j <= n) // wが逆Quadrangle Inequalityを満たす場合のO(n log n)あるいはO(n)解法 // // given: // dp[0] // // given: // wは0-indexed monge n*n行列 (逆Quadrangle Ineqalityを満たす) // // 一般にO(n log n) // Closest Zero Propertyが満たされていて、hをO(1)自前実装するならばO(n) ll solveQuadrangleInequality(ll dp0, func_t w) { vector<ll> dp(n+1); dp[0] = dp0; // 状態rの確定のために、遷移kをしようとした時の候補 // k in [0, n), r in [1, n] auto C = [&](ll k, ll r) { assert(0<=k&&k<n && 1<=r<=n); return dp[k] + w(k, r); }; // C(l, h) <= C(k, h)となるような最小のl < h <= n. (k < l < n) // もしなければn+1を返す。 // // wがClosest Zero Propertyを満たしていて、これを自前実装するならばO(1) // デフォルトでO(log n) auto h = [&](ll l, ll k) { assert(k<l&&l<n); if (!(w(l, n) - w(k, n) <= dp[k] - dp[l])) return n+1; ll ng = l, ok = n; while (ok - ng > 1) { ll mid = (ok + ng) / 2; if (w(l, mid) - w(k, mid) <= dp[k] - dp[l]) ok = mid; else ng = mid; } return ok; // Brutal /* ll ret = -1; repi(hc, l+1, n+1) { if (w(l, hc) - w(k, hc) <= dp[k] - dp[l]) { ret = hc; break; } } if (ret < 0) ret = n + 1; assert(ret == ok); return ret; */ }; deque<P> Q = {P(0, 1)}; repi(j, 1, n+1) { ll l = Q.back().fi; // 最小のつもり if (C(j-1, j) <= C(l, j)) { dp[j] = C(j-1, j); Q.clear(); Q.push_back(P(j-1, j+1)); } else { dp[j] = C(l, j); while (C(j-1, Q[0].se) <= C(Q[0].fi, Q[0].se)) Q.pop_front(); ll hc = h(j-1, Q[0].fi); if (hc != n + 1) Q.push_front(P(j-1, hc)); if (Q.size() >= 2 && j + 1 == Q[Q.size()-2].se) Q.pop_back(); else Q.back().se++; } } // cout << dp << "Eppstein" << endl; return dp[n]; } void compareMin(void) { function<ll(ll, ll)> w = w_QuadrangleInequality; ll ret_m = solveQuadrangleInequality(0, w); #if 1 ll ret_b = solveBrutal(0, w); if (ret_b != ret_m) { cout << "Not Match" << endl; cout << "Jury : " << ret_b << ", Participant : " << ret_m<<endl; cout << a << endl; cout << x << endl; cout << y << endl; repi(i, 1, n+1) { rep(j, i) { cout << w(j, i) << "\t"; } cout << endl; } ll is_monge = isQuadrangleInequality(w); if (is_monge) { cout << "Monge OK" << endl; } else { cout << "NOT Monge" << endl; assert(0); } } #endif cout << ret_m << endl; } int main(void) { cin >> n; a.resize(n); x.resize(n); y.resize(n); cin >> a; cin >> x; cin >> y; assert(1<=n&&n<=3e5); rep(i, n) { assert(0<=a[i]&&a[i]<=1e5); assert(0<=x[i]&&x[i]<=1e5); assert(0<=y[i]&&y[i]<=1e5); } rep(i, n-1) { assert(a[i]<=a[i+1]); assert(x[i]<=x[i+1]); } compareMin(); // compareMax(); return 0; }