結果
問題 | No.650 行列木クエリ |
ユーザー | はまやんはまやん |
提出日時 | 2018-02-10 01:58:29 |
言語 | C++14 (gcc 12.3.0 + boost 1.83.0) |
結果 |
AC
|
実行時間 | 122 ms / 2,000 ms |
コード長 | 7,294 bytes |
コンパイル時間 | 3,033 ms |
コンパイル使用メモリ | 199,328 KB |
実行使用メモリ | 30,040 KB |
最終ジャッジ日時 | 2024-10-09 10:47:34 |
合計ジャッジ時間 | 3,686 ms |
ジャッジサーバーID (参考情報) |
judge4 / judge3 |
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テストケース
テストケース表示入力 | 結果 | 実行時間 実行使用メモリ |
---|---|---|
testcase_00 | AC | 6 ms
7,436 KB |
testcase_01 | AC | 45 ms
11,048 KB |
testcase_02 | AC | 122 ms
25,216 KB |
testcase_03 | AC | 6 ms
7,460 KB |
testcase_04 | AC | 43 ms
11,028 KB |
testcase_05 | AC | 116 ms
25,268 KB |
testcase_06 | AC | 5 ms
7,532 KB |
testcase_07 | AC | 6 ms
7,568 KB |
testcase_08 | AC | 37 ms
12,124 KB |
testcase_09 | AC | 80 ms
30,040 KB |
testcase_10 | AC | 5 ms
7,444 KB |
ソースコード
#include<bits/stdc++.h> #define rep(i,a,b) for(int i=a;i<b;i++) #define rrep(i,a,b) for(int i=a;i>=b;i--) #define fore(i,a) for(auto &i:a) #define all(x) (x).begin(),(x).end() #pragma GCC optimize ("-O3") using namespace std; void _main(); int main() { cin.tie(0); ios::sync_with_stdio(false); _main(); } typedef long long ll; const int inf = INT_MAX / 2; const ll infl = 1LL << 60; template<class T>bool chmax(T &a, const T &b) { if (a<b) { a = b; return 1; } return 0; } template<class T>bool chmin(T &a, const T &b) { if (b<a) { a = b; return 1; } return 0; } //--------------------------------------------------------------------------------------------------- // vid : id -> vid head, heavy, parent : unknown // depth : id -> depth inv : vid -> id struct HLDecomposition { vector<set<int>> g; vector<int> vid, head, heavy, parent, depth, inv; HLDecomposition() {} HLDecomposition(int n) { init(n); } void init(int n) { g.resize(n);vid.resize(n, -1);head.resize(n);heavy.resize(n, -1); parent.resize(n);depth.resize(n);inv.resize(n);} void add(int u, int v) { g[u].insert(v); g[v].insert(u); } void build() { dfs(0, -1); bfs(); } int dfs(int curr, int prev) { parent[curr] = prev; int sub = 1, max_sub = 0; for (int next : g[curr]) if (next != prev) { depth[next] = depth[curr] + 1; int sub_next = dfs(next, curr); sub += sub_next; if (max_sub < sub_next) max_sub = sub_next, heavy[curr] = next; }return sub;} void bfs() { int k = 0; queue<int> q({ 0 }); while (!q.empty()) { int h = q.front(); q.pop(); for (int i = h; i != -1; i = heavy[i]) {vid[i] = k++; inv[vid[i]] = i; head[i] = h; for (int j : g[i]) if (j != parent[i] && j != heavy[i]) q.push(j);}}} void foreach(int u, int v, function<void(int, int)> f) { // [x,y] if (vid[u] > vid[v]) swap(u, v); f(max(vid[head[v]], vid[u]), vid[v]); if (head[u] != head[v]) foreach(u, parent[head[v]], f);} int ancestor(int from, int times) { while (true) { if (depth[head[from]] > depth[from] - times) { times-=depth[from]-depth[head[from]]+1;if(head[from]==0)return -1;from=parent[head[from]];} else return inv[vid[from] - times];} } int lca(int u, int v) { if (vid[u] > vid[v]) swap(u, v); if (head[u] == head[v]) return u; return lca(u, parent[head[v]]); } int distance(int u, int v) { return depth[u] + depth[v] - 2 * depth[lca(u, v)]; } int child(int parent,int child,int times){assert(depth[parent]<depth[child]); int d=distance(parent, child);assert(times - 1 <= d);return ancestor(child, d - times);} int go(int from,int to,int times){int d=distance(from,to);assert(0<=times and times<=d); int lc=lca(from,to);if(lc==to)return ancestor(from,times);if(lc==from)return child(from,to,times); int dd=distance(from,lc);if(dd<=times)return go(lc,to,times-dd);return ancestor(from,times);}}; template<int MOD> struct ModInt { static const int Mod = MOD; unsigned x; ModInt() : x(0) { } ModInt(signed sig) { x = sig < 0 ? sig % MOD + MOD : sig % MOD; } ModInt(signed long long sig) { x = sig < 0 ? sig % MOD + MOD : sig % MOD; } int get() const { return (int)x; } ModInt &operator+=(ModInt that) { if ((x += that.x) >= MOD) x -= MOD; return *this; } ModInt &operator-=(ModInt that) { if ((x += MOD - that.x) >= MOD) x -= MOD; return *this; } ModInt &operator*=(ModInt that) { x = (unsigned long long)x * that.x % MOD; return *this; } ModInt &operator/=(ModInt that) { return *this *= that.inverse(); } ModInt operator+(ModInt that) const { return ModInt(*this) += that; } ModInt operator-(ModInt that) const { return ModInt(*this) -= that; } ModInt operator*(ModInt that) const { return ModInt(*this) *= that; } ModInt operator/(ModInt that) const { return ModInt(*this) /= that; } ModInt inverse() const { long long a = x, b = MOD, u = 1, v = 0; while (b) { long long t = a / b; a -= t * b; std::swap(a, b); u -= t * v; std::swap(u, v); } return ModInt(u); } bool operator==(ModInt that) const { return x == that.x; } bool operator!=(ModInt that) const { return x != that.x; } ModInt operator-() const { ModInt t; t.x = x == 0 ? 0 : Mod - x; return t; } }; template<int MOD> ostream& operator<<(ostream& st, const ModInt<MOD> a) { st << a.get(); return st; }; template<int MOD> ModInt<MOD> operator^(ModInt<MOD> a, unsigned long long k) { ModInt<MOD> r = 1; while (k) { if (k & 1) r *= a; a *= a; k >>= 1; } return r; } typedef ModInt<1000000007> mint; struct func { mint x00, x01, x10, x11; func(mint a = 1, mint b = 0, mint c = 0, mint d = 1) : x00(a), x01(b), x10(c), x11(d) {} }; func operator*(func x, func y) { mint a = x.x00 * y.x00 + x.x01 * y.x10; mint b = x.x00 * y.x01 + x.x01 * y.x11; mint c = x.x10 * y.x00 + x.x11 * y.x10; mint d = x.x10 * y.x01 + x.x11 * y.x11; return func(a, b, c, d); } //--------------------------------------------------------------------------------------------------- template<class V, int NV> struct SegTree { // [L,R) V comp(V l, V r) { return l * r; }; vector<V> val; SegTree() { val = vector<V>(NV * 2); } V get(int x, int y, int l = 0, int r = NV, int k = 1) { if(r<=x||y<=l)return V();if(x<=l&&r<=y)return val[k];auto A=get(x,y,l,(l+r)/2,k*2); auto B = get(x,y,(l+r)/2,r,k*2+1);return comp(A,B);} void update(int i, V v){i+=NV;val[i]=v;while (i>1)i>>=1,val[i]=comp(val[i*2],val[i*2+1]);}}; /*--------------------------------------------------------------------------------------------------- ∧_∧ ∧_∧ (´<_` ) Welcome to My Coding Space! ( ´_ゝ`) / ⌒i / \ | | / / ̄ ̄ ̄ ̄/ | __(__ニつ/ _/ .| .|____ \/____/ (u ⊃ ---------------------------------------------------------------------------------------------------*/ int N, Q, A[101010], B[101010]; int f[101010]; SegTree<func, 1 << 17> st; HLDecomposition hld; func ans; int pre; //--------------------------------------------------------------------------------------------------- void _main() { cin >> N; hld.init(N); rep(i, 0, N - 1) { cin >> A[i] >> B[i]; hld.add(A[i], B[i]); } hld.build(); rep(i, 0, N - 1) { if (hld.depth[A[i]] < hld.depth[B[i]]) f[i] = B[i]; else f[i] = A[i]; } cin >> Q; rep(q, 0, Q) { string t; cin >> t; if (t == "x") { int i, a, b, c, d; cin >> i >> a >> b >> c >> d; i = f[i]; st.update(hld.vid[i], func(a, b, c, d)); } else { int i, j; cin >> i >> j; i = hld.go(i, j, 1); ans = func(); pre = -1; hld.foreach(j, i, [](int u, int v) { int uu = hld.inv[u]; if (pre < hld.depth[uu]) ans = ans * st.get(u, v + 1); else ans = st.get(u, v + 1) * ans; pre = hld.depth[uu]; }); printf("%d %d %d %d\n", ans.x00.get(), ans.x01.get(), ans.x10.get(), ans.x11.get()); } } }