結果
問題 | No.896 友達以上恋人未満 |
ユーザー |
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提出日時 | 2018-02-11 13:44:23 |
言語 | C++17 (gcc 13.3.0 + boost 1.87.0) |
結果 |
WA
(最新)
AC
(最初)
|
実行時間 | - |
コード長 | 1,538 bytes |
コンパイル時間 | 574 ms |
コンパイル使用メモリ | 67,760 KB |
最終ジャッジ日時 | 2025-01-05 08:19:06 |
ジャッジサーバーID (参考情報) |
judge3 / judge4 |
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ファイルパターン | 結果 |
---|---|
sample | AC * 1 WA * 3 |
other | WA * 5 RE * 2 |
コンパイルメッセージ
main.cpp: In function ‘int main()’: main.cpp:27:44: warning: format ‘%d’ expects argument of type ‘int*’, but argument 2 has type ‘ll*’ {aka ‘long long int*’} [-Wformat=] 27 | for(int i = 0; i < m; i++) scanf("%d", x+i); | ~^ ~~~ | | | | int* ll* {aka long long int*} | %lld main.cpp:28:44: warning: format ‘%d’ expects argument of type ‘int*’, but argument 2 has type ‘ll*’ {aka ‘long long int*’} [-Wformat=] 28 | for(int i = 0; i < m; i++) scanf("%d", y+i); | ~^ ~~~ | | | | int* ll* {aka long long int*} | %lld main.cpp:48:44: warning: format ‘%d’ expects argument of type ‘int*’, but argument 2 has type ‘ll*’ {aka ‘long long int*’} [-Wformat=] 48 | for(int i = 0; i < m; i++) scanf("%d", a+i); | ~^ ~~~ | | | | int* ll* {aka long long int*} | %lld main.cpp:49:44: warning: format ‘%d’ expects argument of type ‘int*’, but argument 2 has type ‘ll*’ {aka ‘long long int*’} [-Wformat=] 49 | for(int i = 0; i < m; i++) scanf("%d", b+i); | ~^ ~~~ | | | | int* ll* {aka long long int*} | %lld main.cpp:18:14: warning: ignoring return value of ‘int scanf(const char*, ...)’ declared with at
ソースコード
#include <cstdio> #include <cassert> #include <iostream> using namespace std; typedef long long ll; #define N (1<<24) #define M 100010 int m, n, mx, ax, my, ay, mod, mod2, mod3 = 1<<30; ll x[M], y[M], z[N], a[M], b[M]; bool prime[N]; ll solve(ll a, ll b){ b *= a; return (a<mod?z[a]:0)-(b<mod?z[b]:0); } int main(){ scanf("%d%d%d%d%d%d%d%d",&m,&n,&mx,&ax,&my,&ay,&mod,&mod2); /*assert(1<=m&&m<=100); assert(m<=n&&n<=10000000); assert(1<=mod&&mod<=1<<23); assert(__builtin_popcount(mod)==1); assert(0<=mx&&mx<mod); assert(0<=ax&&ax<mod); assert(0<=my&&my<mod); assert(0<=ay&&ay<mod);*/ for(int i = 0; i < m; i++) scanf("%d", x+i); for(int i = 0; i < m; i++) scanf("%d", y+i); for(int i = 0; i < m; i++) z[x[i]] += y[i]; ll xx = x[m-1], yy = y[m-1]; for(int i = m; i < n; i++){ xx = (xx*mx+(ll)ax)&(mod-1); yy = (yy*my+(ll)ay)&(mod-1); z[xx] += yy; } for(int i = 2; i*i<mod; i++){ if(prime[i]) continue; for(int j = i*i; j<mod; j+=i){ prime[j] = true; } } for(int i = 2; i < mod; i++){ if(prime[i]) continue; for(int j = (mod-1)/i*i; j > 0; j-=i){ z[j/i] += z[j]; } } for(int i = 0; i < m; i++) scanf("%d", a+i); for(int i = 0; i < m; i++) scanf("%d", b+i); ll res = 0; for(int i = 0; i < m; i++){ ll r = solve(a[i], b[i]); printf("%lld\n", r); (res+=r)&=mod3-1; } ll aa = a[m-1], bb = b[m-1]; for(int i = m; i < n; i++){ aa = ((aa*mx+(ll)ax+mod2-1)&(mod2-1))+1; bb = ((bb*my+(ll)ay+mod2-1)&(mod2-1))+1; (res+=solve(aa, bb))&=mod3-1; } printf("%lld\n", res); return 0; }